SIMplify (2x+p-q)raise to power 2 -(2x-p+q)raise to power2 -Maths 9th

SIMplify (2x+p-q)raise to power 2 -(2x-p+q)raise to power2 -Maths 9th
by

1 Answer

Answer :

2p-2q+2 is answer of the question
by

Related questions

SIMplify (2x+p-q)raise to power 2 -(2x-p+q)raise to power2 -Maths 9th

Description : SIMplify (2x+p-q)raise to power 2 -(2x-p+q)raise to power2 -Maths 9th

Last Answer : 2p-2q+2 is answer of the question

Simplify: (i) (a + b + c)2 + (a – b + c)2 (ii) (a + b + c)2 – (a – b + c)2 (iii) (a + b + c)2 + (a – b + c)2 + (a + b – c)2 (iv) (2x + p – c)2 – (2x – p + c)2 (v) (x2 + y2 – z2)2 – (x2 – y2 + z2)2 -Maths 9th

Description : Simplify: (i) (a + b + c)2 + (a – b + c)2 (ii) (a + b + c)2 – (a – b + c)2 (iii) (a + b + c)2 + (a – b + c)2 + (a + b – c)2 (iv) (2x + p – c)2 – (2x – p + c)2 (v) (x2 + y2 – z2)2 – (x2 – y2 + z2)2 -Maths 9th

Last Answer : answer:

Simplify (2x- 5y)3 – (2x+ 5y)3. -Maths 9th

Description : Simplify (2x- 5y)3 – (2x+ 5y)3. -Maths 9th

Last Answer : (2x -5y)3 - (2x + 5y)3 = [(2x)3 - (5y)3 - 3(2x)(5y)(2x - 5y)] -[(2x)3 + (5y)3 + 3(2x)(5y)(2x+5y)] [using identity, (a - b)3 = a3 -b3 - 3ab and (a + b)3 =a3 +b3 + 3ab] = (2x)3 - (5y)3 - ... 2x)3- (5y)3 - 30xy (2x + 5y) = -2 (5y)3 - 30xy(2x - 5y + 2x + 5y) = -2 x 125y3 - 30xy(4x) = -250y3 -120x2y

Simplify (2x- 5y)3 – (2x+ 5y)3. -Maths 9th

Description : Simplify (2x- 5y)3 – (2x+ 5y)3. -Maths 9th

Last Answer : (2x -5y)3 - (2x + 5y)3 = [(2x)3 - (5y)3 - 3(2x)(5y)(2x - 5y)] -[(2x)3 + (5y)3 + 3(2x)(5y)(2x+5y)] [using identity, (a - b)3 = a3 -b3 - 3ab and (a + b)3 =a3 +b3 + 3ab] = (2x)3 - (5y)3 - ... 2x)3- (5y)3 - 30xy (2x + 5y) = -2 (5y)3 - 30xy(2x - 5y + 2x + 5y) = -2 x 125y3 - 30xy(4x) = -250y3 -120x2y

Simplify: (2x–5y)3 – (2x + 5y)3 -Maths 9th

Description : Simplify: (2x–5y)3 – (2x + 5y)3 -Maths 9th

Last Answer : Solution :-

When (x^3 – 2x^2 + px – q) is divided by (x^2 – 2x – 3), the remainder is (x – 6), What are the values of p and q respectively ? -Maths 9th

Description : When (x^3 – 2x^2 + px – q) is divided by (x^2 – 2x – 3), the remainder is (x – 6), What are the values of p and q respectively ? -Maths 9th

Last Answer : answer:

If the expression (px^3 + x^2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ? -Maths 9th

Description : If the expression (px^3 + x^2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ? -Maths 9th

Last Answer : Let f(x)=px3+x2−2x−q Since f(x) is divisible by (x−1) and (x+1) so x=1 and −1 must make f(x)=0. Therefore, p+1−2−q=0, i.e., p−q=1; and −p+1+2−q=0, i.e., p+q=3 Thus p=2 and q=1

Simplify: x to the power 4 whole to the power 1/3 under root 12. -Maths 9th

Description : Simplify: x to the power 4 whole to the power 1/3 under root 12. -Maths 9th

Last Answer : Solution :-

Simplify: ( 3125/243) to the power -4/5. -Maths 9th

Description : Simplify: ( 3125/243) to the power -4/5. -Maths 9th

Last Answer : Solution :-

Simplify: 125 to power -1/3[125 to the power 1/3 - 125 to the power 2/3]. -Maths 9th

Description : Simplify: 125 to power -1/3[125 to the power 1/3 - 125 to the power 2/3]. -Maths 9th

Last Answer : Solution :-

Simplify: 9 to the power 1/3 x 27 to the 3 to the power -1/2 / 3 to the power 1/6 x 3 to the power -2/3. -Maths 9th

Description : Simplify: 9 to the power 1/3 x 27 to the 3 to the power -1/2 / 3 to the power 1/6 x 3 to the power -2/3. -Maths 9th

Last Answer : Solution :-

Use the Factor Theorem to determine whether g(x) is a factor of p(x) in each of the following cases: (i) p(x) = 2x3+x2–2x–1, g(x) = x+1 -Maths 9th

Description : Use the Factor Theorem to determine whether g(x) is a factor of p(x) in each of the following cases: (i) p(x) = 2x3+x2–2x–1, g(x) = x+1 -Maths 9th

Last Answer : Solution: p(x) = 2x3+x2–2x–1, g(x) = x+1 g(x) = 0 ⇒ x+1 = 0 ⇒ x = −1 ∴Zero of g(x) is -1. Now, p(−1) = 2(−1)3+(−1)2–2(−1)–1 = −2+1+2−1 = 0 ∴By factor theorem, g(x) is a factor of p(x

Zero of the polynomial p(x)=2x+5 is -Maths 9th

Description : Zero of the polynomial p(x)=2x+5 is -Maths 9th

Last Answer : (b) Given, p(x) = 2x+5 For zero of the polynomial, put p(x) = 0 ∴ 2x + 5 = 0 ⇒ -5/2 Hence, zero of the polynomial p(x) is -5/2.

Zero of the polynomial p(x)=2x+5 is -Maths 9th

Description : Zero of the polynomial p(x)=2x+5 is -Maths 9th

Last Answer : (b) Given, p(x) = 2x+5 For zero of the polynomial, put p(x) = 0 ∴ 2x + 5 = 0 ⇒ -5/2 Hence, zero of the polynomial p(x) is -5/2.

if (1.-2) is a solution of the equation 2x-y=p,then find the value of p. -Maths 9th

Description : if (1.-2) is a solution of the equation 2x-y=p,then find the value of p. -Maths 9th

Last Answer : x = 1 y = -2 2x-y = p Therefore, p = 2(1)-(-2) = 2 + 2 = 4

if (1.-2) is a solution of the equation 2x-y=p,then find the value of p. -Maths 9th

Description : if (1.-2) is a solution of the equation 2x-y=p,then find the value of p. -Maths 9th

Last Answer : 2x-y=p put x-1,y=-2 =2(1)-(-2)=p p=4

Find the value of k if (x-2)is a factor of polynomial p(x) = 2x(cube) - 6x(square) + 5x + k. -Maths 9th

Description : Find the value of k if (x-2)is a factor of polynomial p(x) = 2x(cube) - 6x(square) + 5x + k. -Maths 9th

Last Answer : Solution :-

Check whether polynomial p(x) = 2x(cube) - 9x(square) + x + 12 is a multiple of 2x-3 or not. -Maths 9th

Description : Check whether polynomial p(x) = 2x(cube) - 9x(square) + x + 12 is a multiple of 2x-3 or not. -Maths 9th

Last Answer : Solution :-

Find the value of the polynomial p(x) = x^3-3x^2-2x+6 at x = underroot 2 -Maths 9th

Description : Find the value of the polynomial p(x) = x^3-3x^2-2x+6 at x = underroot 2 -Maths 9th

Last Answer : In this chapter, we shall proceed with recalling some of the constructions already learnt in the earlier classes and deal with some more. Here in this section, we will construct some of these ... be done? 2. Always explain the construction. Write the sequence of steps that are actually taken.

For what value of p is the coefficient of x^2 in the product (2x – 1) (x – k) (px + 1) equal to 0 and the constant term equal to 2 ? -Maths 9th

Description : For what value of p is the coefficient of x^2 in the product (2x – 1) (x – k) (px + 1) equal to 0 and the constant term equal to 2 ? -Maths 9th

Last Answer : answer:

If the expressions (px^3 + 3x^2 – 3) and (2x^3 – 5x + p) when divided by (x – 4) leave the same remainder, then what is the value of p ? -Maths 9th

Description : If the expressions (px^3 + 3x^2 – 3) and (2x^3 – 5x + p) when divided by (x – 4) leave the same remainder, then what is the value of p ? -Maths 9th

Last Answer : Given that the following polynomials leave the same remainder when divided by (x - 4) : We are to find the value of a. Remainder theorem: When (x - b) divides a polynomial p(x), then the remainder is p(b). So, from (i) and (ii), we get Thus, the required value of a is 1.

If the sum of the zeroes of the polynomial p(x) = (k2 – 14) x2 – 2x – 12 is 1, then find the value of k. -Maths 9th

Description : If the sum of the zeroes of the polynomial p(x) = (k2 – 14) x2 – 2x – 12 is 1, then find the value of k. -Maths 9th

Last Answer : p(x) = (k2 – 14) x2 – 2x – 12 Here a = k2 – 14, b = -2, c = -12 Sum of the zeroes, (α + β) = 1 …[Given] ⇒ − = 1 ⇒ −(−2)2−14 = 1 ⇒ k2 – 14 = 2 ⇒ k2 = 16 ⇒ k = ±4

Simplify the question -Maths 9th

Description : Simplify the question -Maths 9th

Last Answer : After rationalizing it 42/11

Simplify by combining similar terms: -Maths 9th

Description : Simplify by combining similar terms: -Maths 9th

Last Answer : 5√2 + 20√2 = (5+20)√2 = 25√2

Simplify by combining similar terms : -Maths 9th

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form √12 = √22 × 3 = 2√3 √75 = √3 × 52 = 5√3 Therefore 4√3 - 3√12 + 2√75 = 4√3 - 3 × 2√3 + 2 × 5√3 = 4√3 - 6√3 + 10√3 = (4 - 6 + 10) √3 = 8√3

Simplify by combining similar terms : -Maths 9th

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form √8 = √(22× 2) = 2 × √2 √32 = √(22 × 22 × 2) = 2 × 2√2 = 4√2 ∴ √8 + √32 - √2 = 2√2 + 4√2 - √2 = (2 + 4 -1) √2 = 5√2 .

Simplify by combining similar terms : -Maths 9th

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : √12 = √(22 × 3) = 2√3 √50 = √(2 × 52) = (5 √2) √48 = √(22 × 22 × 3) = (2 × 2√3)= 4√3 ∴ 4√12 - √50 - 7 √48 = 4 × 2√3 - 5√2 - 7 × 4√3 = 8√3 - 5√2 - 28√3 = (8 -28)√3 - 5√2 = -20√3 - 5√2

Simplify by combining similar terms : -Maths 9th

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form

Simplify and express the result in its simplest form : -Maths 9th

Description : Simplify and express the result in its simplest form : -Maths 9th

Last Answer : √14 × √21 = √14 × 21 = √2 × 7 × 3 × 7 = √2 × 3 × 72 = 7√6

Simplify and express the result in its simplest form : -Maths 9th

Description : Simplify and express the result in its simplest form : -Maths 9th

Last Answer : √15 × √7 = √15 × 7 = √105

Simplify and express the result in its simplest form : -Maths 9th

Description : Simplify and express the result in its simplest form : -Maths 9th

Last Answer : 3√4 × 3√22 = 3√4 × 22 = 3√22 × 2 × 11 =3√23 × 11 = 23√11

Simplify and express the result in its simplest form : -Maths 9th

Description : Simplify and express the result in its simplest form : -Maths 9th

Last Answer : L.C.M. of 3,4 of 12 3√2 = 12√24 = 12√16 4√3 = 12√33 = 12√27 3√2 × 4√3 = 12√16 × 12√27 = 12√(16×27) = 12√432

Simplify and express the result in its simplest form : -Maths 9th

Description : Simplify and express the result in its simplest form : -Maths 9th

Last Answer : 4√12 × 7√6 = 28√12 × 6 = 28√62 × 2 = 28 × 6√2 = 168√2.

Simplify and express the result in its simplest form : -Maths 9th

Description : Simplify and express the result in its simplest form : -Maths 9th

Last Answer : L.C.M. of 3,2 is 6 3√2 = 6√22 = 6√4 √5 = 6√53 = 6√125 3√2 × √5 = 6√4 × 6√125 = 6√(4 × 125) = 6√500 .

Simplify and express the result in its simplest form : -Maths 9th

Description : Simplify and express the result in its simplest form : -Maths 9th

Last Answer : 4√28 / 3√7 = 4√28 / 3√7 4√28 / 3√7 = 4 / 3√4 = 4 / 3 × 2 = 8 / 3

Simplify the following question -Maths 9th

Description : Simplify the following question -Maths 9th

Last Answer : Simplification of following question

Simplify by rationalizing the denominator : -Maths 9th

Description : Simplify by rationalizing the denominator : -Maths 9th

Last Answer : Rationalizing the denominator

simplify (2a + b)3 + (2a - b)3 -Maths 9th

Description : simplify (2a + b)3 + (2a - b)3 -Maths 9th

Last Answer : (2a + b)3 + (2a - b)3 = (8a3 + 12a2b + 3ab2 + b3 ) + (8a3 - 12a2b + 3ab2 - b3) = 16a3 + 6ab2

Simplify the following -Maths 9th

Description : Simplify the following -Maths 9th

Last Answer : Simplification:

Simplify the following question : -Maths 9th

Description : Simplify the following question : -Maths 9th

Last Answer : Simplification of following number

Simplify the following question : -Maths 9th

Description : Simplify the following question : -Maths 9th

Last Answer : Simplification

Simplify the question -Maths 9th

Description : Simplify the question -Maths 9th

Last Answer : After rationalizing it 42/11

Simplify by combining similar terms: -Maths 9th

Description : Simplify by combining similar terms: -Maths 9th

Last Answer : 5√2 + 20√2 = (5+20)√2 = 25√2

Simplify by combining similar terms : -Maths 9th

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form √12 = √22 × 3 = 2√3 √75 = √3 × 52 = 5√3 Therefore 4√3 - 3√12 + 2√75 = 4√3 - 3 × 2√3 + 2 × 5√3 = 4√3 - 6√3 + 10√3 = (4 - 6 + 10) √3 = 8√3

Simplify by combining similar terms : -Maths 9th

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form √8 = √(22× 2) = 2 × √2 √32 = √(22 × 22 × 2) = 2 × 2√2 = 4√2 ∴ √8 + √32 - √2 = 2√2 + 4√2 - √2 = (2 + 4 -1) √2 = 5√2 .

Simplify by combining similar terms : -Maths 9th

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : √12 = √(22 × 3) = 2√3 √50 = √(2 × 52) = (5 √2) √48 = √(22 × 22 × 3) = (2 × 2√3)= 4√3 ∴ 4√12 - √50 - 7 √48 = 4 × 2√3 - 5√2 - 7 × 4√3 = 8√3 - 5√2 - 28√3 = (8 -28)√3 - 5√2 = -20√3 - 5√2

Simplify by combining similar terms : -Maths 9th

Description : Simplify by combining similar terms : -Maths 9th

Last Answer : Reducing into simplest form

Simplify and express the result in its simplest form : -Maths 9th

Description : Simplify and express the result in its simplest form : -Maths 9th

Last Answer : √14 × √21 = √14 × 21 = √2 × 7 × 3 × 7 = √2 × 3 × 72 = 7√6

Simplify and express the result in its simplest form : -Maths 9th

Description : Simplify and express the result in its simplest form : -Maths 9th

Last Answer : √15 × √7 = √15 × 7 = √105

Simplify and express the result in its simplest form : -Maths 9th

Description : Simplify and express the result in its simplest form : -Maths 9th

Last Answer : 3√4 × 3√22 = 3√4 × 22 = 3√22 × 2 × 11 =3√23 × 11 = 23√11