Rinku has built a cuboidal water tank in his house. The top of the water tank is covered with an iron lid. -Maths 9th

Rinku has built a cuboidal water tank in his house. The top of the water tank is covered with an iron lid. -Maths 9th
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Answer :

Total inner surface area of the water tank including the base without top  = 2(l + b) × h + l × b   = 2(180 + 120) × 60 + 180 × 120 = 36000 + 21600 = 57600 cm2  Area of each title = 10 × 8 = 80 cm2 ∴ Number of tiles required = 57600 / 80 = 720 Total amount required for 720 tiles at the rate of 480 per dozen = 480 / 12 × 720  = 28800
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Related questions

Rinku has built a cuboidal water tank in his house. The top of the water tank is covered with an iron lid. -Maths 9th

Description : Rinku has built a cuboidal water tank in his house. The top of the water tank is covered with an iron lid. -Maths 9th

Last Answer : Total inner surface area of the water tank including the base without top = 2(l + b) h + l b = 2(180 + 120) 60 + 180 120 = 36000 + 21600 = 57600 cm2 Area of each title = 10 ... 57600 / 80 = 720 Total amount required for 720 tiles at the rate of 480 per dozen = 480 / 12 720 = 28800

Hameed has built a cubical water tank with lid for his house, with each other edge 1.5m long. -Maths 9th

Description : Hameed has built a cubical water tank with lid for his house, with each other edge 1.5m long. -Maths 9th

Last Answer : Edge of cubical tank = 1.5 m ∴ Area of 4 walls = 4 (side)² = 4(1.5)² m² = 4 x 225 = 9 m² Area of floor = (1.5)² = 2.25 m² ∴ Total surface area = 9 + 2.25 = 11.25 m² Edge of square tile = 25 m = 0.25 m² ∴ Area of 1 tile = (0.25)2 = .0625 m²

Shahid has built a cubical water tank with lid for his house, -Maths 9th

Description : Shahid has built a cubical water tank with lid for his house, -Maths 9th

Last Answer : Edge of tank = 2 m = 2 x 100 cm = 200 cm Area of five faces of the tank = 5a2 = 5 (200 cm)2 = 2,00,000 cm2 Area of a square tile = 25 cm x 25 cm = 625 cm2 Number of tiles required = Area of ... /12 do zen Cost of one dozen of tiles = ₹480 ∴ Cost of 320/12 dozen tiles = ₹480 x 320/12 = ₹12, 800

The capacity of a cuboidal tank is 50000 litres of water. Find the breadth of the tank, if its length and depth are respectively 2.5 m and 10 m -Maths 9th

Description : The capacity of a cuboidal tank is 50000 litres of water. Find the breadth of the tank, if its length and depth are respectively 2.5 m and 10 m -Maths 9th

Last Answer : Length (l) and depth (h) of tank is 2.5 m and 10 m respectively. To find: The value of breadth, say b. Formula to find the volume of a tank = l b h = (2.5 b 10) m3= 25b m3 Capacity ... of water (Given) Therefore, 25000 b = 50000 This implies, b = 2 Therefore, the breadth of the tank is 2 m.

A cuboidal water tank is 6m long, 5m wide and 4.5m deep. How many litres of water can it hold? -Maths 9th

Description : A cuboidal water tank is 6m long, 5m wide and 4.5m deep. How many litres of water can it hold? -Maths 9th

Last Answer : Dimensions of a cuboidal water tank are: l = 6 m and b = 5 m and h = 4.5 m Formula to find volume of tank, V = l b h Put the values, we get V = (6 5 4.5) = 135 ... water, 135 m3volume hold = (135 1000) litres = 135000 litres Therefore, given cuboidal water tank can hold up to135000 litres of wate

A cuboidal water tank is 6 m long, -Maths 9th

Description : A cuboidal water tank is 6 m long, -Maths 9th

Last Answer : Volume of cuboidal tank = 1 x b x h = 6 m x 5 m x 4.5 m = 135 m3 = 135 x 1000 L = 135000 L

Find the cost of digging a cuboidal pit 8m long, 6m broad and 3m deep at the rate of Rs 30 per m3 -Maths 9th

Description : Find the cost of digging a cuboidal pit 8m long, 6m broad and 3m deep at the rate of Rs 30 per m3 -Maths 9th

Last Answer : The given pit has its length(l) as 8m, width (b)as 6m and depth (h)as 3 m. Volume of cuboidal pit = l×b×h = (8×6×3) = 144 (using formula) Required Volume is 144 m3 Now, Cost of digging per m3 volume = Rs 30 Cost of digging 144 m3 volume = Rs (144×30) = Rs 4320

A cubical box has each edge 10 cm and another cuboidal box is 12.5cm long, 10 cm wide and 8 cm high -Maths 9th

Description : A cubical box has each edge 10 cm and another cuboidal box is 12.5cm long, 10 cm wide and 8 cm high -Maths 9th

Last Answer : From the question statement, we have Edge of a cube = 10cm Length, l = 12.5 cm Breadth, b = 10cm Height, h = 8 cm (i) Find the lateral surface area for both the figures Lateral surface ... . Therefore, the total surface area of the cubical box is smaller than that of the cuboidal box by 10 cm2

A cone of height 7 cm and base radius 1 cm is carved from a cuboidal block of wood 10 cm × 5 cm × 2 cm -Maths 9th

Description : A cone of height 7 cm and base radius 1 cm is carved from a cuboidal block of wood 10 cm × 5 cm × 2 cm -Maths 9th

Last Answer : 92239223% Volume of cone = 1313πr2h = 13×227×1×7=22313×227×1×7=223 cu. cm Volume of cubical block = (10 × 5 × 2) cm3 = 100 cm3 ∴ Wastage of wood = (100−227)100×100(100−227)100×100 = 27832783% = 92239223%

A hemispherical tank is made up of an iron -Maths 9th

Description : A hemispherical tank is made up of an iron -Maths 9th

Last Answer : Inner radius of the hemispherical tank (r) = 1 m Outer radius of the hemispherical tank (R) = 1 + 0.01 = 1.01 m Volume of iron used to make the hemispherical tank = 2/3 πR3 - 2/3πr3 = 2/3π(R3 - r3) = 2/3 x 22/7 [(1.01)3 - 13] = 44/21(1.0303 - 1) = 44/21 x 0.0303 = 0.06349 m3

A closed iron tank 12 m long 9 m wide and 4 m deep is to be made . Determine the cost of iron sheet used at the rate of rs 5 per meter , sheet being 2 m wide. -Maths 9th

Description : A closed iron tank 12 m long 9 m wide and 4 m deep is to be made . Determine the cost of iron sheet used at the rate of rs 5 per meter , sheet being 2 m wide. -Maths 9th

Last Answer : This answer was deleted by our moderators...

Where does the water come from under the lid when something is cooked and covered ?

Last Answer : Cooked vegetables have high heat (more than 100 degrees). And since the boiling point of water is 100, it evaporates. And it flies up. But because of the lid, it obstructs the lid and water accumulates there. This is how water comes.

Rinku works in a fruit juice company as the marketing manager. -Technology

Description : Rinku works in a fruit juice company as the marketing manager. -Technology

Last Answer : Rinku should make an interactive presentation and for this type of presentation nothing could be better than multimedia. He can use various multimedia components for making his presentation interactive.

Rinku Of name Money What ?

Last Answer : Rinku Of name Money Is : - Attention.

Mary wants to decorate her ********* tree. She wants to place the tree on a wooden block covered with coloured paper with picture of Santa Claus on it. -Maths 9th

Description : Mary wants to decorate her Christmas tree. She wants to place the tree on a wooden block covered with coloured paper with picture of Santa Claus on it. -Maths 9th

Last Answer : Length of box (l) = 80 cm Breadth (b) = 40 cm and height (h) = 20 cm ∴ Total surface area = 2(lb + bh + hl) = 2[80 x 40 + 40 x 20 + 20 x 80] cm² = 2[3200 + 800 + 1600] ... of one sheet = (40 cm)² = 1600 cm² ∴ No. of sheets required for the box = 11200 = 1600 = 7 sheets

he auto-rickshaw fare in a city is charged as ₹10 for the first kilometre and @ ₹4 per kilometre for subsequent distance covered. Write the linear equation to express the above statement. Draw the graph of linear equation. -Maths 9th

Description : he auto-rickshaw fare in a city is charged as ₹10 for the first kilometre and @ ₹4 per kilometre for subsequent distance covered. Write the linear equation to express the above statement. Draw the graph of linear equation. -Maths 9th

Last Answer : Solution :- Fig. 3.12 represents the graph of the linear equation y = 4x+6.

A storage tank is in the form of a cube. When it is full of water, the volume of water is 15.625 m3. -Maths 9th

Description : A storage tank is in the form of a cube. When it is full of water, the volume of water is 15.625 m3. -Maths 9th

Last Answer : When it is full of water, the volume of water is 15.625m3. If the present depth of water is 1.3m, then, find the volume of water alredy used fom the tank. Hence, the volume of water ... 7500 L. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

A storage tank is in the form of a cube. When it is full of water, the volume of water is 15.625 m3. -Maths 9th

Description : A storage tank is in the form of a cube. When it is full of water, the volume of water is 15.625 m3. -Maths 9th

Last Answer : Let side of a cube be = x m ∴ Volume of cubical tank = 15.625 m3 [given] ⇒ x3 = 15.625 m3 ⇒ x = 2.5 m and present depth of water in cubical tank = 1.3 m ∴ Height of water used =2.5 - 1.3 ... 7. 5 x 1000 = 7500 L [∴ 1 m3 = 1000 L] Hence, the volume of water already used from the tank is 7500 L.

Water is following at the rate of 5 km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50 m long -Maths 9th

Description : Water is following at the rate of 5 km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50 m long -Maths 9th

Last Answer : Convert all to metres: 5 km = 5000 m 14 cm = 0.14 m 7 cm = 0.07 m Find the radius: Radius = Diameter 2 Radius = 0.14 2 = 0.07 m Find the amount of water that flowed out in an hour: Volume ... hours needed: Number of hours = 154 77 = 2 hours It takes 2 hours to fill up the tank to rise by 7 cm

Water flows in a tank 150 m × 100 m at the base, through a pipe whose cross-section is 2 dm by 1.5 dm, at a speed of 15 km per hour. -Maths 9th

Description : Water flows in a tank 150 m × 100 m at the base, through a pipe whose cross-section is 2 dm by 1.5 dm, at a speed of 15 km per hour. -Maths 9th

Last Answer : Volume of water discharged through the pipe = Volume increase of the tank First, consider the pipe. Volume discharge through pipe = length breadth speed time Let the time taken to fill the tank to 3 m depth be t. ... the tank V=150 100 3 cu. m ⇒ V=450 100 Therefore, 450t=450 100 ⇒ t=100 hours

A tank internally measuring 150 cm × 120 cm × 100 cm has 1281600 cm^3 of water in it. Porous bricks are placed in the water until the tank -Maths 9th

Description : A tank internally measuring 150 cm × 120 cm × 100 cm has 1281600 cm^3 of water in it. Porous bricks are placed in the water until the tank -Maths 9th

Last Answer : Volume of a brick = 20 cm 6 cm 4 cm = 480 cm3. Water absorbed by one brick = (110 480)(110 480) cm3 = 48 cm3. Let x bricks be placed in the water. Then, x bricks absorb 48x cm3 of water. ... tank ⇒ 1281600 + 480xx - 48xx = 150 x 120 x 100 ⇒ 432xx = 1800000 - 1281600 = 518400 ⇒ xx = 1200.

Find (i) the lateral or curved surface area of a closed cylindrical petrol storage tank that is 4.2 m in diameter and 4.5m high. -Maths 9th

Description : Find (i) the lateral or curved surface area of a closed cylindrical petrol storage tank that is 4.2 m in diameter and 4.5m high. -Maths 9th

Last Answer : Height of cylindrical tank, h = 4.5m Radius of the circular end , r = (4.2/2)m = 2.1m (i) the lateral or curved surface area of cylindrical tank is 2πrh = 2 (22/7) 2.1 4.5 m2 = (44 0.3 ... ) = 87.12 m2 This implies, S = 95.04 m2 Therefore, 95.04m2 steel was used in actual while making such a tank.

It is required to make a closed cylindrical tank of height 1m and base diameter 140cm from a metal sheet. How many square meters of the sheet are required for the same? -Maths 9th

Description : It is required to make a closed cylindrical tank of height 1m and base diameter 140cm from a metal sheet. How many square meters of the sheet are required for the same? -Maths 9th

Last Answer : Let h be the height and r be the radius of a cylindrical tank. Height of cylindrical tank, h = 1m Radius = half of diameter = (140/2) cm = 70cm = 0.7m Area of sheet required = Total surface are of tank = 2πr( ... [2 (22/7) 0.7(0.7+1)] = 7.48 Therefore, 7.48 square meters of the sheet are required.

A storage tank consists of a circular cylinder with a hemisphere adjoined on either end. If the external diameter of the cylinder be 1.4 m and its length be 8 m, find the cost of painting it on the outside at the rate of Rs. 10 per m -Maths 9th

Description : A storage tank consists of a circular cylinder with a hemisphere adjoined on either end. If the external diameter of the cylinder be 1.4 m and its length be 8 m, find the cost of painting it on the outside at the rate of Rs. 10 per m -Maths 9th

Last Answer : Answer We have, r=0.7m, h=8m ∴ Total surface area = 2πr2+2πrh=2πr(r+h)=2×722​×0.7×8.7m2 Required cost = Rs. {2×722​×0.7×8.7×10}=Rs.382.80

It is required to make a closed cylindrical tank of height 1 m and base diameter 140 cm from a metal sheet. -Maths 9th

Description : It is required to make a closed cylindrical tank of height 1 m and base diameter 140 cm from a metal sheet. -Maths 9th

Last Answer : Radius of the closed cylindrical tank = 140/2 cm = 70 cm = 0.7 m Height of the closed cylindrical tank = 1 m Area of metal sheet required = 2πr(r + h) = 2 x 22/7 x 0.7 (1 + 0.7) = 7.48 m2

A storage tank is in the form of a cube. -Maths 9th

Description : A storage tank is in the form of a cube. -Maths 9th

Last Answer : Volume of water in cubical storage tank = 15.625 m3 = (2.5 m)3 = a3 ⇒ a = 2.5 m Volume of water in cubical tank when depth of water is 1.3 m = 2.5 X 2.5 x 1.3 = 8.125 m3 Volume of water already used from the tank = 15.625 - 8.125 = 7.5 m3

A wall of length 10 m is to be built across an open ground. -Maths 9th

Description : A wall of length 10 m is to be built across an open ground. -Maths 9th

Last Answer : Length of the wall = 10 m = 1000 cm Thickness of the wall = 42 cm Height of the wall = 5 m = 500 cm ∴ Volume of the wall = 1000 × 500 × 42 cm3 Volume of each brick = 42 × 12 × 10 cm3 No. of bricks = Volume of the wall / Volume of each brick = 1000 × 500 × 42 / 42 × 12 × 10 = 4166.67 = 4167

A wall of length 10 m is to be built across an open ground. -Maths 9th

Description : A wall of length 10 m is to be built across an open ground. -Maths 9th

Last Answer : Length of the wall = 10 m = 1000 cm Thickness of the wall = 42 cm Height of the wall = 5 m = 500 cm ∴ Volume of the wall = 1000 × 500 × 42 cm3 Volume of each brick = 42 × 12 × 10 cm3 No. of bricks = Volume of the wall / Volume of each brick = 1000 × 500 × 42 / 42 × 12 × 10 = 4166.67 = 4167

Is the top of a lid still the top if it is upside down on the table?

Description : Is the top of a lid still the top if it is upside down on the table?

Last Answer : Yes. The top is a description of the shape of the lid. The position of the lid relative to space is arbitrary. It might be in the same position if it were laying right-side-up on a table in Australia. There’s no “up” in space.

A cylinder is filled to 4/5 th of its volume. It is, then tilted so that the level of water coincides with one edge of its bottom and top edge -Maths 9th

Description : A cylinder is filled to 4/5 th of its volume. It is, then tilted so that the level of water coincides with one edge of its bottom and top edge -Maths 9th

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Germinal epithelial cells are cuboidal and these are found in

Description : Germinal epithelial cells are cuboidal and these are found in

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Lower most layer of stratified squamous tissue is known as Germinative layer. Reason : lower most layer of stratified tissue is mostly cuboidal in sha

Description : Lower most layer of stratified squamous tissue is known as Germinative layer. Reason : lower most layer of stratified tissue is mostly cuboidal in sha

Last Answer : Lower most layer of stratified squamous tissue is known as Germinative layer. Reason : lower most layer ... D. If both Assertion & Reason are false.

Assertion : Simple cuboidal epithelium is also called as germinal epithelium Reason : Cuboidal cells of gonads forms gametes

Description : Assertion : Simple cuboidal epithelium is also called as germinal epithelium Reason : Cuboidal cells of gonads forms gametes

Last Answer : Assertion : Simple cuboidal epithelium is also called as germinal epithelium Reason : Cuboidal cells of ... . If both Assertion & Reason are false.

What is the function of cuboidal epithelium?

Description : What is the function of cuboidal epithelium?

Last Answer : Cuboidal epithelium in glands help in secretion. For example salivary gland and thyroid gland.

What is cuboidal epithelium? Where do they occur?

Description : What is cuboidal epithelium? Where do they occur?

Last Answer : The epithelium that have cube shaped cells are called cuboidal epithelium. They are found in the lining of many ducts such as pancreatic duct, salivary duct and sweat ducts.

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Description : How many angles of obliquity are there for a cuboidal body under complex stresses? a. 6 b. 8 c. 4 d. None

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Description : Stratum germinativum is an example of which kind of epithelium? (a) Columnar (b) Squamous (c) Cuboidal (d) Ciliated

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Description : The epithelial tissue present on the inner surface of bronchioles and Fallopian tubes is (a) glandular (b) ciliated (c) squamous (d) cuboidal.

Last Answer : (b) ciliated

Choose the correctly matched pair. (a) Inner lining of - Ciliated epithelium salivary ducts (b) Moist surface - Glandular epithelium of buccal cavity (c) Tubular parts of -Cuboidal epithelium nephrons (d) Inner surface of - Squamous epithelium bronchioles

Description : Choose the correctly matched pair. (a) Inner lining of - Ciliated epithelium salivary ducts (b) Moist surface - Glandular epithelium of buccal cavity (c) Tubular parts of -Cuboidal epithelium nephrons (d) Inner surface of - Squamous epithelium bronchioles

Last Answer : (c) Tubular parts of -Cuboidal epithelium nephrons

Which type of tissue correctly matches with its location? Tissue Location (a) Transitional Tip of nose epithelium (b) Cuboidal epithelium Lining of stomach (c) Smooth muscle Wall of intestine (d) Areolar tissue Tendons

Description : Which type of tissue correctly matches with its location? Tissue Location (a) Transitional Tip of nose epithelium (b) Cuboidal epithelium Lining of stomach (c) Smooth muscle Wall of intestine (d) Areolar tissue Tendons

Last Answer : (c) Smooth muscle Wall of intestine

Cuboidal epithelium with brush border of microvilli is found in (a) lining of intestine (b) ducts of salivary glands (c) proximal convoluted tubule of nephron (d) Eustachian tube

Description : Cuboidal epithelium with brush border of microvilli is found in (a) lining of intestine (b) ducts of salivary glands (c) proximal convoluted tubule of nephron (d) Eustachian tube

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Now that the lid is off the REAL reason Trump doesn’t want his taxes exposed, is anyone REALLY surprised?

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My cat has flipped his lid, I think. Can anyone suggest something to calm him down?

Description : My cat has flipped his lid, I think. Can anyone suggest something to calm him down?

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he frame has a base diameter of 20 cm and height of 30 cm. A margin of 2.5 cm is to be given for folding it over the top and bottom of the frame. -Maths 9th

Description : he frame has a base diameter of 20 cm and height of 30 cm. A margin of 2.5 cm is to be given for folding it over the top and bottom of the frame. -Maths 9th

Last Answer : Say h = height of the frame of lampshade, looks like cylindrical shape r = radius Total height is h = (2.5+30+2.5) cm = 35cm and r = (20/2) cm = 10cm Use curved surface area formula to find the ... 2πrh = (2 (22/7) 10 35) cm2 = 2200 cm2 Hence, 2200 cm2 cloth is required for covering the lampshade.

A child consumed an ice-cream of inverted right-circular conical shape from the top and left only 12.5% of the cone for her mother. -Maths 9th

Description : A child consumed an ice-cream of inverted right-circular conical shape from the top and left only 12.5% of the cone for her mother. -Maths 9th

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The angle of elevation of the top of a tower from two points distant s and t from its foot are complementary. Prove that the height of the tower is √st. -Maths 9th

Description : The angle of elevation of the top of a tower from two points distant s and t from its foot are complementary. Prove that the height of the tower is √st. -Maths 9th

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A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 30° with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree. -Maths 9th

Description : A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 30° with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree. -Maths 9th

Last Answer : The broken part bends so that the top of the tree touches the ground making an angle 30 °. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Original height of ... After rationalising Now we have , A`BC = AB + BC Take LCM So , original height of tree is

Twenty-seven solid iron spheres, -Maths 9th

Description : Twenty-seven solid iron spheres, -Maths 9th

Last Answer : (i) Volume of 27 solid sphere, each of radius, r = 27 x 4/3 πr3 = 36 πr3 According to statement, Volume of sphere of radius r' = Volume of 27 solid spheres ⇒ 4/3 π(r'3 ) = 36 πr3 ⇒ (r')3 = 27r3 = (3r)3 ⇒ r' = 3r ( ... πr'2 = 4 π(3r)2 = 36 πr2 ∴ S/S' = 4 πr2 /36 πr2 = 1/9 ⇒ S : S' = 1 : 9

A cylindrical rod of iron whose height is eight times its radius is melted and cast into spherical balls each of half the radius of the cylinder. -Maths 9th

Description : A cylindrical rod of iron whose height is eight times its radius is melted and cast into spherical balls each of half the radius of the cylinder. -Maths 9th

Last Answer : Let radius of iron rod = r ∴∴ Height = 8r ∴∴ Volume of iron rod =π×(r)2×8r⇒8πr3=π×(r)2×8r⇒8πr3 ⇒⇒ Radius of spherical ball =r2=r2 Volume of spherical ball =43π(r2)3=43π(r2)3 Let n balls are casted ∴n×43π(r38)=8πr3∴n×43π(r38)=8πr3 ⇒n6=8⇒n=48