Calculate the edge of the cube if its volume is 1331 cm3 -Maths 9th

Calculate the edge of the cube if its volume is 1331 cm3 -Maths 9th
by

1 Answer

Answer :

Let the edge of the cube be a Volume of a cube = a×a×a 1331= a×a×a 11 =a ( as 1331 is the cube of  11 Therefore , Edge of a cube is 11 cm
by

Related questions

Calculate the edge of the cube if its volume is 1331 cm3 -Maths 9th

Description : Calculate the edge of the cube if its volume is 1331 cm3 -Maths 9th

Last Answer : Let the edge of the cube be a Volume of a cube = a×a×a 1331= a×a×a 11 =a ( as 1331 is the cube of 11 Therefore , Edge of a cube is 11 cm

The total surface area of a cube is 726 cm2. Find the length of its edge . -Maths 9th

Description : The total surface area of a cube is 726 cm2. Find the length of its edge . -Maths 9th

Last Answer : Total surface area of a cube = 726 cm2 6 × (side)2 = 726 (side)2 = 121 side = 11 cm Hence, the length of the edge of cube is 11 cm.

The total surface area of a cube is 726 cm2. Find the length of its edge . -Maths 9th

Description : The total surface area of a cube is 726 cm2. Find the length of its edge . -Maths 9th

Last Answer : Total surface area of a cube = 726 cm2 6 × (side)2 = 726 (side)2 = 121 side = 11 cm Hence, the length of the edge of cube is 11 cm.

Find the lateral surface area and total surface area of a cube of edge 10 cm. -Maths 9th

Description : Find the lateral surface area and total surface area of a cube of edge 10 cm. -Maths 9th

Last Answer : Edge of cube (a) = 10 cm (i) ∴ Lateral surface area = 4a² = 4 x (10)² = 4 x 100 cm²= 400 cm² (ii) Total surface area = 6a² = 6 x(10)² cm² = 6 x 100 = 600 cm²

an edge of cube is increased by 10%. find the percentage by which the surface area of cube has increased -Maths 9th

Description : an edge of cube is increased by 10%. find the percentage by which the surface area of cube has increased -Maths 9th

Last Answer : each side of cube=l incresed by 10%=L+L/10 =11L/10 surface area of the new cube= 6l^2 =6x 11L/10 x 11L/10 =726/100L^2 % increase= 726/100L^2 - 6L^2 / 6L^2 x 100 =126L^2/100 / 6L^2 x 100 =126L^2/600L^2 x 100 =126L^2/ 6L^2 =126/6 =21 %

an edge of cube is increased by 10%. find the percentage by which the surface area of cube has increased -Maths 9th

Description : an edge of cube is increased by 10%. find the percentage by which the surface area of cube has increased -Maths 9th

Last Answer : each side of cube=l incresed by 10%=L+L/10 =11L/10 surface area of the new cube= 6l^2 =6x 11L/10 x 11L/10 =726/100L^2 % increase= 726/100L^2 - 6L^2 / 6L^2 x 100 =126L^2/100 / 6L^2 x 100 =126L^2/600L^2 x 100 =126L^2/ 6L^2 =126/6 =21 %

If three cubes of copper, each with an edge 6 cm, 8 cm and 10 cm respectively are melted to form a single cube, -Maths 9th

Description : If three cubes of copper, each with an edge 6 cm, 8 cm and 10 cm respectively are melted to form a single cube, -Maths 9th

Last Answer : 20.8 cm Let the edge of the single cube be ‘a’ cm. Then, total volume melted = Volume of cube formed ⇒ (6)3 + (8)3 + (10)3 = a3 ⇒ a3 = 216 + 512 + 1000 = 1728 ... Diagonal of the new cube = 3–√a=(3–√×12)3a=(3×12) cm = 20.8 cm (approx.)

A 4 cm cube is cut into 1 cm cubes. Calculate the total surface area of all the small cubes. -Maths 9th

Description : A 4 cm cube is cut into 1 cm cubes. Calculate the total surface area of all the small cubes. -Maths 9th

Last Answer : Side of cube = 4 cm But cutting into 1 cm cubes, we get = 4 x 4 x 4 = 64 Now surface area of one cube = 6 x (1)² = 6 x 1=6 cm² and surface area of 64 cubes = 6 x 64 cm² = 384 cm²

A cylindrical vessel can hold 154 g of water. If the radius of its base is 3.5 cm, and 1 cm3 of water weighs lg,find the depth of water. -Maths 9th

Description : A cylindrical vessel can hold 154 g of water. If the radius of its base is 3.5 cm, and 1 cm3 of water weighs lg,find the depth of water. -Maths 9th

Last Answer : Since 1 cm3 of water weighs 1 g. ∴ Volume of cyclinder vessel = 154 cm3 πr2h = 154 h = 154 × 7 / 22 × 3.5 × 3.5 h ;= 4 cm Hence, the depth of water is 4 cm.

A cylindrical vessel can hold 154 g of water. If the radius of its base is 3.5 cm, and 1 cm3 of water weighs lg,find the depth of water. -Maths 9th

Description : A cylindrical vessel can hold 154 g of water. If the radius of its base is 3.5 cm, and 1 cm3 of water weighs lg,find the depth of water. -Maths 9th

Last Answer : Since 1 cm3 of water weighs 1 g. ∴ Volume of cyclinder vessel = 154 cm3 πr2h = 154 h = 154 × 7 / 22 × 3.5 × 3.5 h ;= 4 cm Hence, the depth of water is 4 cm.

A shot-put is a metallic sphere of radius 4.9 cm. If the density of the metal is 7.8 g/cm3. -Maths 9th

Description : A shot-put is a metallic sphere of radius 4.9 cm. If the density of the metal is 7.8 g/cm3. -Maths 9th

Last Answer : We have, the radius of a metallic sphere (r) = 4.9 cm ∴ Volume of the sphere = 4 / 3 πr3 = 4 / 3 × 22 / 7 × 4.9 × 4.9 × 4.9 = 493.005 cm3 ∵ Density of the metal used = 7.8 g/cm3 Hence, the mass of the shot - put = 493.005 × 7.8 = 3845.44

A shot-put is a metallic sphere of radius 4.9 cm. If the density of the metal is 7.8 g/cm3. -Maths 9th

Description : A shot-put is a metallic sphere of radius 4.9 cm. If the density of the metal is 7.8 g/cm3. -Maths 9th

Last Answer : We have, the radius of a metallic sphere (r) = 4.9 cm ∴ Volume of the sphere = 4 / 3 πr3 = 4 / 3 × 22 / 7 × 4.9 × 4.9 × 4.9 = 493.005 cm3 ∵ Density of the metal used = 7.8 g/cm3 Hence, the mass of the shot - put = 493.005 × 7.8 = 3845.44

The volume of a cube is numerically equal to sum of its edges. What is the total surface area in square units ? -Maths 9th

Description : The volume of a cube is numerically equal to sum of its edges. What is the total surface area in square units ? -Maths 9th

Last Answer : answer:

If S is the total surface area of a cube and V is its volume, then which of the following is correct ? -Maths 9th

Description : If S is the total surface area of a cube and V is its volume, then which of the following is correct ? -Maths 9th

Last Answer : answer:

If a sphere is inscribed in a cube, then find the ratio of the volume of the cube to the volume of the sphere. -Maths 9th

Description : If a sphere is inscribed in a cube, then find the ratio of the volume of the cube to the volume of the sphere. -Maths 9th

Last Answer : The ratio of the volume of the cube to the volume of the sphere are as

If a sphere is inscribed in a cube, then find the ratio of the volume of the cube to the volume of the sphere. -Maths 9th

Description : If a sphere is inscribed in a cube, then find the ratio of the volume of the cube to the volume of the sphere. -Maths 9th

Last Answer : The ratio of the volume of the cube to the volume of the sphere are as

The total surface area of a cube is 96 cm2 . The volume of the cube is -Maths 9th

Description : The total surface area of a cube is 96 cm2 . The volume of the cube is -Maths 9th

Last Answer : NEED ANSWER

The lateral surface area of a cube is 256 m2. The volume of the cube is -Maths 9th

Description : The lateral surface area of a cube is 256 m2. The volume of the cube is -Maths 9th

Last Answer : NEED ANSWER

A storage tank is in the form of a cube. When it is full of water, the volume of water is 15.625 m3. -Maths 9th

Description : A storage tank is in the form of a cube. When it is full of water, the volume of water is 15.625 m3. -Maths 9th

Last Answer : When it is full of water, the volume of water is 15.625m3. If the present depth of water is 1.3m, then, find the volume of water alredy used fom the tank. Hence, the volume of water ... 7500 L. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

The total surface area of a cube is 96 cm2 . The volume of the cube is -Maths 9th

Description : The total surface area of a cube is 96 cm2 . The volume of the cube is -Maths 9th

Last Answer : (c) Surface area of a cube = 96 cm2 Surface area of a cube = 6 (Side)2 = 96 ⇒ (Side)2 = 16 ⇒ (Side) = 4 cm [taking positive square root because side is always a positive quantity] Volume of cube = (Side)3 = (4)3 = 64 cm3 Hence, the volume of the cube is 64 cm3.

The lateral surface area of a cube is 256 m2. The volume of the cube is -Maths 9th

Description : The lateral surface area of a cube is 256 m2. The volume of the cube is -Maths 9th

Last Answer : (a) Given, lateral surface area of a cube = 256 m2 We know that, lateral surface area of a cube = 4 x (Side)2 ⇒ 256 = 4 x (Side)2 ⇒ (Side)2 = 256/4 = 64 ⇒ Side = √64 = 8 m [taking positive square root ... of a cube = (Side)3 = (8)3 = 8 x 8 x 8 = 512 m3 Hence, the volume of the cube is 512 m3.

A storage tank is in the form of a cube. When it is full of water, the volume of water is 15.625 m3. -Maths 9th

Description : A storage tank is in the form of a cube. When it is full of water, the volume of water is 15.625 m3. -Maths 9th

Last Answer : Let side of a cube be = x m ∴ Volume of cubical tank = 15.625 m3 [given] ⇒ x3 = 15.625 m3 ⇒ x = 2.5 m and present depth of water in cubical tank = 1.3 m ∴ Height of water used =2.5 - 1.3 ... 7. 5 x 1000 = 7500 L [∴ 1 m3 = 1000 L] Hence, the volume of water already used from the tank is 7500 L.

A sphere and a cube have the same surface area. What is the ratio of the square of volume of the sphere to the square of volume of the cube ? -Maths 9th

Description : A sphere and a cube have the same surface area. What is the ratio of the square of volume of the sphere to the square of volume of the cube ? -Maths 9th

Last Answer : answer:

There are two identical cubes. Out of one cube, a sphere of maximum volume (VS) is cut off. Out of the second cube, a cone of maximum volume -Maths 9th

Description : There are two identical cubes. Out of one cube, a sphere of maximum volume (VS) is cut off. Out of the second cube, a cone of maximum volume -Maths 9th

Last Answer : answer:

A cylinder is filled to 4/5 th of its volume. It is, then tilted so that the level of water coincides with one edge of its bottom and top edge -Maths 9th

Description : A cylinder is filled to 4/5 th of its volume. It is, then tilted so that the level of water coincides with one edge of its bottom and top edge -Maths 9th

Last Answer : answer:

How can you work out the volume of a cube of edge 5cm?

Description : How can you work out the volume of a cube of edge 5cm?

Last Answer : 5 x 5 x 5 = 125 cubic cm

Find the radius of the largest right circular cone that can be cut out from a cube of edge 4.2 cm. -Maths 10th

Description : Find the radius of the largest right circular cone that can be cut out from a cube of edge 4.2 cm. -Maths 10th

Last Answer : Radius of the largest right circular cone 1/2 (Edge of the Square) =4.2/2 = 2.1 cm

Write a program in C++ to overload a „volume‟ function to calculate volume of cube and rectangular box.

Description : Write a program in C++ to overload a „volume‟ function to calculate volume of cube and rectangular box. 

Last Answer : #include<iostream.h> #include<conio.h> void volume(float); void volume(float, float, float); void main() { float a, length, width, height; clrscr(); cout<<"\n ... width*height; cout<<"\n Volume of a rectangular box is:"<<v; }

The total surface area of a cube is 150sq.cm. Find the perimeter of any one of its face ? -Maths 9th

Description : The total surface area of a cube is 150sq.cm. Find the perimeter of any one of its face ? -Maths 9th

Last Answer : NEED ANSWER

The total surface area of a cube is 150sq.cm. Find the perimeter of any one of its face ? -Maths 9th

Description : The total surface area of a cube is 150sq.cm. Find the perimeter of any one of its face ? -Maths 9th

Last Answer : Take the side be s, 6s^(2)=150cm^(2) s^(2)= 150/6 =25 s^(2)=square root of 25 s=5 Area of square s^(2) 5×5=25sq.cm. Perimeter = 4×side =4×5=20cm

Find the ratio of the total surface area and lateral surface area of a cube. -Maths 9th

Description : Find the ratio of the total surface area and lateral surface area of a cube. -Maths 9th

Last Answer : Let a be the edge of the cube, then Total surface area = 6a2² and lateral surface area = 4a² Now ratio between total surface area and lateral surface area = 6a² : 4a² = 3 : 2

The perimeter of one face of a cube is 20 cm. Find the lateral surface area of the cube. -Maths 9th

Description : The perimeter of one face of a cube is 20 cm. Find the lateral surface area of the cube. -Maths 9th

Last Answer : Let a be the edge of cube, ∴ Perimeter of one face of cube = 20 cm ⇒ 4a = 20 ⇒ a = 5 ∴ Lateral surface area of cube = 4a2 = 4 (5)2 = 100 cm2

The perimeter of one face of a cube is 20 cm. Find the lateral surface area of the cube. -Maths 9th

Description : The perimeter of one face of a cube is 20 cm. Find the lateral surface area of the cube. -Maths 9th

Last Answer : Let a be the edge of cube, ∴ Perimeter of one face of cube = 20 cm ⇒ 4a = 20 ⇒ a = 5 ∴ Lateral surface area of cube = 4a2 = 4 (5)2 = 100 cm2

Divide: 12 15 under root 4 by 8 cube root 3. -Maths 9th

Description : Divide: 12 15 under root 4 by 8 cube root 3. -Maths 9th

Last Answer : Solution :-

If a+b+c=0, then what is the value of a(cube) + b(cube) + c(cube)? -Maths 9th

Description : If a+b+c=0, then what is the value of a(cube) + b(cube) + c(cube)? -Maths 9th

Last Answer : Solution :-

Find the value of a, if x-a is a factor of x(cube) - ax(square) + a-1. -Maths 9th

Description : Find the value of a, if x-a is a factor of x(cube) - ax(square) + a-1. -Maths 9th

Last Answer : Solution :-

Find the factors of {1-x(cube)}. -Maths 9th

Description : Find the factors of {1-x(cube)}. -Maths 9th

Last Answer : Solution :-

Find the factors of y(cube) + y(square) + y + 1 -Maths 9th

Description : Find the factors of y(cube) + y(square) + y + 1 -Maths 9th

Last Answer : Solution :-

If x(square) - 1 is a factor of ax(cube) + bx(square) + cx + d,show that a+c=0. -Maths 9th

Description : If x(square) - 1 is a factor of ax(cube) + bx(square) + cx + d,show that a+c=0. -Maths 9th

Last Answer : Solution :-

Find the remainder when f(x)=4x(cube) - 12x(square) +14x - 3 is divided by g(x) = (2x-1). -Maths 9th

Description : Find the remainder when f(x)=4x(cube) - 12x(square) +14x - 3 is divided by g(x) = (2x-1). -Maths 9th

Last Answer : ____2x2-5x+4________________ 2x-1 ) 4x3-12x2+14x-3( 4x3-2x2 - + ____________ 0 -10x2+14x-3 ... + ___________ X+1

If (x+1) is a factor of ax(cube) + x(square) - 2x + 4a - 9,find the value of a. -Maths 9th

Description : If (x+1) is a factor of ax(cube) + x(square) - 2x + 4a - 9,find the value of a. -Maths 9th

Last Answer : solution :-

Find the value of k if (x-2)is a factor of polynomial p(x) = 2x(cube) - 6x(square) + 5x + k. -Maths 9th

Description : Find the value of k if (x-2)is a factor of polynomial p(x) = 2x(cube) - 6x(square) + 5x + k. -Maths 9th

Last Answer : Solution :-

What must be substract from x(to the power 4) + 3x(cube) + 4x(square) - 3x - 6 to get 3x(cube) + 4x(square) - x + 3? -Maths 9th

Description : What must be substract from x(to the power 4) + 3x(cube) + 4x(square) - 3x - 6 to get 3x(cube) + 4x(square) - x + 3? -Maths 9th

Last Answer : Solution :-

What must be added to 2x(square) - 5x + 6 to get x(cube) - 3x(square) + 3x - 5? -Maths 9th

Description : What must be added to 2x(square) - 5x + 6 to get x(cube) - 3x(square) + 3x - 5? -Maths 9th

Last Answer : Solution :-

Find the remainder when f(x)=9x(cube) -x 3x(square) + 14x - 3 is divided by g(x)=(3x-1). -Maths 9th

Description : Find the remainder when f(x)=9x(cube) -x 3x(square) + 14x - 3 is divided by g(x)=(3x-1). -Maths 9th

Last Answer : Solution :-

Check whether polynomial p(x) = 2x(cube) - 9x(square) + x + 12 is a multiple of 2x-3 or not. -Maths 9th

Description : Check whether polynomial p(x) = 2x(cube) - 9x(square) + x + 12 is a multiple of 2x-3 or not. -Maths 9th

Last Answer : Solution :-

Show that 2x+1 is a factor of polynomial 2x(cube) - 11x(square) - 4x + 1. -Maths 9th

Description : Show that 2x+1 is a factor of polynomial 2x(cube) - 11x(square) - 4x + 1. -Maths 9th

Last Answer : Solution :-

Factorise: 2x(5) + 432x(square) y(cube). -Maths 9th

Description : Factorise: 2x(5) + 432x(square) y(cube). -Maths 9th

Last Answer : Solution :-

A cube and a sphere are of the same height. -Maths 9th

Description : A cube and a sphere are of the same height. -Maths 9th

Last Answer : Volume of cube/ volume of the sphere = a3 / 4/3.π.(a/2)3 = 6/π (Let edge of cube be a then radius of sphere = a/2) ∴ Required ratio = 6 : π

A storage tank is in the form of a cube. -Maths 9th

Description : A storage tank is in the form of a cube. -Maths 9th

Last Answer : Volume of water in cubical storage tank = 15.625 m3 = (2.5 m)3 = a3 ⇒ a = 2.5 m Volume of water in cubical tank when depth of water is 1.3 m = 2.5 X 2.5 x 1.3 = 8.125 m3 Volume of water already used from the tank = 15.625 - 8.125 = 7.5 m3