Description : An anti-aircraft gun can take a maximum of four shots at any plane moving away from it. The probabilities of hitting the plane at 1st, 2nd, 3rd -Maths 9th
Last Answer : (c) 0.6976Let A, B, C, D be the events that 1st, 2nd, 3rd and 4th shots hits the plane respectively. Then, P(A) = 0.4, P(B) = 0.3, P(C) = 0.2, P(D) = 0.1 ⇒ P(not A) = 1 - P(A),= ... and D are independent events) P(At least one shot hits the plane) = 1 - P(None hits the plane) = 1 - 0.3024 = 0.6976