How can I factorise this...

1 Answer

Answer :

answer:first of all, correct term is to factor, not to factorise. Secondly, while you are right that because 29 is a prime number this cannot be easily factored, you can always use the quadratic formula… ay^2 + by + c y = [negb +/- sqrt(b^2–4ac)]/2a in this case, [neg4 +/- sqrt(16 + 145)]/10 =neg4/10 +/- sqrt(1.61)... this formula gives you the factors of the equation, what y= such that the equation holds…you can use this to factor the equation.

Related questions

Description : Will you help me with this (easy) maths question?

Last Answer : 180X+400=220X |-180X 400=40X |:40 10=X

Description : (4) Algebra question: Can you help?

Last Answer : Keep working on it. Let’s try some combinations.

Description : (3) Algebra Problem: Can you help?

Last Answer : No matter, I’ve figured it out

Description : (2) Algebra problem: Can you help?

Last Answer : *to get to the answer

Description : Algebra problem: Can you help?

Last Answer : Yes, but “a” changed sides as well; therefore it would be negative in the answer…

Description : How do I do this problem with exponential numbers and whatnot?

Last Answer : answer:First of all, remember that negative exponents are the inverse, so they divide. 5x^-3 is 1/5x^3. And, when multiplying you add the exponents. (10^5)(10^3) = 10^8 When dividing you subtract the exponent of the denominator from the exponent of the numerator. 10^5/ 10^3 = 10^2 Hope that helps.

Description : Which one of these is right (math)

Last Answer : When dividing by a number (such as the 3x-to-x or 5y-to-y) you need to divide all the terms that are on each of the sides.

Description : Using phasors, determine in the following equations

Last Answer : Using phasors, determine in the following equations

Description : Linear Algebra Problem the solution to the system of equations

Last Answer : Linear Algebra Problem the solution to the system of equations https://youtu.be/y_FlupirxZM

Description :  The number of loop equations required to completely analysing a network comprising of 8 independent branches and 6 nodes including the reference node shall be A) 3 B) 2 C) 4 D) 5 

Last Answer :  The number of loop equations required to completely analysing a network comprising of 8 independent branches and 6 nodes including the reference node shall be 3 

Description : The number of independent equations to solve a network is equal to?

Last Answer : The number of independent equations to solve a network is equal to the number of chords.

Description : How to factorise using cross method?

Last Answer : This may help

Description : x^4+x^2+25 factorise this -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : Factorise each of the following expressions: -Maths 9th

Last Answer : (i) 48x3 - 36x2 = 12.4 x2 x - 12.3x2 = 12x2 (4x - 3) (ii) 5x2 - 15xy = 5x (x-3y) (iii) 15x3y2z - 25xy2z3 = 5xy2z(3x2 - 5z2)

Description : Factorise this question -Maths 9th

Last Answer : (i) The greatest monomial that is a common factor of the three terms is 6xy. ∴ 30x3y + 24x2y2 - 6xy = 6xy (5x2 + 4xy - 1) (ii) Here the polynomial (a-b) is a common factor. ∴ 5x(a-b) + 6y(a-b) = (a-b) (5x + 6y)

Description : Factorise this question -Maths 9th

Last Answer : (i) 7a3 + 7a - 2a2 - 2 = 7a(a2 + 1) - 2 (a2 + 1) = (a2 + 1) (7a - 2) (ii) The term of 4ax + 3by - 3ay - 4bx can be rearranged and factorized . 4ax - 4bx - 3ay + 3by = 4x(a-b) - 3y(a-b) = (a-b) (4x - 3y) (iii) x3 + y3 + x2y + xy2 = x3 + x2y + xy2 + y3 = x2(x+y) + y2 (x+y) = (x+y) (x2+y2)

Description : Factorise this question -Maths 9th

Last Answer : (i) 9x2 + 30xy + 25y2 = (3x2 + 2(3x) (5y) + (5y)2 = (3x + 5y)2 (ii) 9x2 - 30xy + 25y2 = (3x)2 - 2(3x) (5y) + 5y2 = (3x - 5y)2

Description : Factorise : x2 + 9x +18 -Maths 9th

Last Answer : Factorisation

Description : Factorise : 2x3 -3x2 -17x + 30 -Maths 9th

Last Answer : Factorisation of following

Description : Factorise the following : 9x2 -12x+ 3 -Maths 9th

Last Answer : Factorise the following :

Description : Factorise the following : 9x2 +4y2 + 16z2 +12xy-16yz -24xz -Maths 9th

Last Answer : Factorise the following

Description : Factorise the following -Maths 9th

Last Answer : Factorise the following

Description : Factorise : 1 + 64x3 -Maths 9th

Last Answer : Factorisation

Description : Factorise: a3 -8b3 -64c3 -24abc -Maths 9th

Last Answer : Factorisation

Description : Without finding the cubes, factorise (x- 2y)3 + (2y – 3z)3 + (3z – x)3. -Maths 9th

Last Answer : We know that, a3 + b3 + c3 – 3 abc = (a + b + c)(a2 + b2 + c2 -ab-bc-ca) Also, if a + b + c = 0, then a3 + b3 + c3 = 3abc Here, we see that (x-2y) +(2y-3z)+ (3z-x) = 0 Therefore, (x-2y)3 + (2y-3z)3 + (3z-x)3 = 3(x-2y)(2y-3z)(3z-x).

Description : x^4+x^2+25 factorise this -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : Factorise each of the following expressions: -Maths 9th

Last Answer : (i) 48x3 - 36x2 = 12.4 x2 x - 12.3x2 = 12x2 (4x - 3) (ii) 5x2 - 15xy = 5x (x-3y) (iii) 15x3y2z - 25xy2z3 = 5xy2z(3x2 - 5z2)

Description : Factorise this question -Maths 9th

Last Answer : (i) The greatest monomial that is a common factor of the three terms is 6xy. ∴ 30x3y + 24x2y2 - 6xy = 6xy (5x2 + 4xy - 1) (ii) Here the polynomial (a-b) is a common factor. ∴ 5x(a-b) + 6y(a-b) = (a-b) (5x + 6y)

Description : Factorise this question -Maths 9th

Last Answer : (i) 7a3 + 7a - 2a2 - 2 = 7a(a2 + 1) - 2 (a2 + 1) = (a2 + 1) (7a - 2) (ii) The term of 4ax + 3by - 3ay - 4bx can be rearranged and factorized . 4ax - 4bx - 3ay + 3by = 4x(a-b) - 3y(a-b) = (a-b) (4x - 3y) (iii) x3 + y3 + x2y + xy2 = x3 + x2y + xy2 + y3 = x2(x+y) + y2 (x+y) = (x+y) (x2+y2)

Description : Factorise this question -Maths 9th

Last Answer : (i) 9x2 + 30xy + 25y2 = (3x2 + 2(3x) (5y) + (5y)2 = (3x + 5y)2 (ii) 9x2 - 30xy + 25y2 = (3x)2 - 2(3x) (5y) + 5y2 = (3x - 5y)2

Description : Factorise : x2 + 9x +18 -Maths 9th

Last Answer : Factorisation

Description : Factorise : 2x3 -3x2 -17x + 30 -Maths 9th

Last Answer : Factorisation of following

Description : Factorise the following : 9x2 -12x+ 3 -Maths 9th

Last Answer : Factorise the following :

Description : Factorise the following : 9x2 +4y2 + 16z2 +12xy-16yz -24xz -Maths 9th

Last Answer : Factorise the following

Description : Factorise the following -Maths 9th

Last Answer : Factorise the following

Description : Factorise : 1 + 64x3 -Maths 9th

Last Answer : Factorisation

Description : Factorise: a3 -8b3 -64c3 -24abc -Maths 9th

Last Answer : Factorisation

Description : Without finding the cubes, factorise (x- 2y)3 + (2y – 3z)3 + (3z – x)3. -Maths 9th

Last Answer : We know that, a3 + b3 + c3 – 3 abc = (a + b + c)(a2 + b2 + c2 -ab-bc-ca) Also, if a + b + c = 0, then a3 + b3 + c3 = 3abc Here, we see that (x-2y) +(2y-3z)+ (3z-x) = 0 Therefore, (x-2y)3 + (2y-3z)3 + (3z-x)3 = 3(x-2y)(2y-3z)(3z-x).

Description : factorise (x-2y)^3-(x+2y)^3 -Maths 9th

Last Answer : NEED ANSWER

Description : factorise the following 4x^2+20x+25 -Maths 9th

Last Answer : NEED ANSWER

Description : factorise (x-2y)^3-(x+2y)^3 -Maths 9th

Last Answer : Given ( x - 2y) 3 + (2y - 3z) 3 + ( 3z - x) 3 Let a = ( x - 2y), b =(2y - 3z), c= ( 3z - x) a + b + c = ( x - 2y)+(2y - 3z)+( 3z - x) = 0 Recall that if (a + b + c) = 0 then a 3 + b 3 + c 3 = 3abc Thus, ( x - 2y) 3 + (2y - 3z) 3 + ( 3z - x) 3 = 3( x - 2y)(2y - 3z)( 3z - x)

Description : factorise the following 4x^2+20x+25 -Maths 9th

Last Answer : 4x^2+20x+25 4x^2+10x+10x+25 2x(2x+5)+5(2x+5) (2x+5)(2x+5) 2x^2+2(2x)(5)+25 2x^2+20x+25

Description : Factorise: 25/4.x(square) - y(square)/9. -Maths 9th

Last Answer : Solution :-

Description : Factorise: a(square) + b(square) - 2ba + 2bc - 2ca -Maths 9th

Last Answer : Solution :-

Description : Factorise: 2x(5) + 432x(square) y(cube). -Maths 9th

Last Answer : Solution :-

Description : Factorise: 125x3 + 27y3 + 8z3 - 90xyz. -Maths 9th

Last Answer : Solution :-

Description : Factorise : r3/8 - s3/343 - t3/216 - 1/28 rst. -Maths 9th

Last Answer : Solution :-

Description : Factorise: 2x(square) - 7x -15 by spliting the middle term. -Maths 9th

Last Answer : Solution :-

Description : Factorise :125x3 - 343y3. -Maths 9th

Last Answer : Solution :-

Description : Without finding the cubes, factorise: (2r-3s)3 +(3s -5t)3+ (5t-2r)3. -Maths 9th

Last Answer : Solution :-