The name of the train 'Shatabdi Express 'addresses the
centenary of

1 Answer

Answer :

Jawaharlal Nehru

Related questions

Description : Shatabdi Express train was started in A. 1988 B. 1976 C. 1966 D. 1956

Last Answer : A [1988] Explanation: The first Shatabdi Express train was introduced in 1988 to commemorate the birth centenary of Jawahar Lal Nehru, the first Prime Minister of India.

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Last Answer : (4) Samjhauta Express Explanation: The Samjhauta Express is a twice-weekly train -Tuesdays and Fridays - that runs between Delhi and Attari in India and Lahore in Pakistan.

Description : Shatabdi Express train was started in (a) 1984 (b) 1988 (c) 1990 (d) 1985

Last Answer : (b) 1988

Description : Shatabdi Express Trains were introduced in 1989 to commemorate the 100th anniversary of which of the following personalities? A. Swami Vivekanand B. Mahatma Gandhi C. Jawaharlal Nehru D. Rabindranath Tagore

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Description : The rajdhani express of 400m runs at a speed of 124 km/hr and a person runs on the platform at a speed of 40km/hr in the direction opposite to that of the train. Find the time taken by the train to cross the running person? A) 7 sec B) 8.78sec C) 7.78sec D) 8 sec

Last Answer : ANSWER : B Explanation:  Length of the train = 400m  Speed of train = 124 km/hr  Speed of person = 40 km/hr  Relative speed (speed of trai relative to man) = (124 + 40) km/hr  = 164 km/hr [As the ... train to cover 400m at a relative of 45.55 m/s  = 400 / 45.55  = 8.78 sec.

Description : A shatabadi express takes 240 seconds to cover a distance of length 700 meters at a speed of 270 km/hr. What will be the time taken by the train to cross a standing pole? A) 160sec B) 465sec C) 310sec D) 231sec

Last Answer : ANSWER:D Explanation:  Speed of the train = 270 km/hr. Converting the speed into m/sec  Speed = 270 km/hr = 270 x 5/18 m/sec = 75 m/sec  First, we have to find the length of the train  Let ... a standing Pole at 75 m/s =( 17300/75)seconds = 231 seconds. Hence the answer is 231 sec(approx.)