In the following figure ABCD is a cyclic quadrilateral, the sum of degree measures of ∠A and ∠D is: (SOURCE: Fig. 3.7, Exercise 3.7, Chapter 3, PAIR of LINEAR EQUATIONS in TWO VARIABLES, NCERT, Class X) (a) 120° (b) 180° (c) 230°(d) 250°

In the following figure ABCD is a cyclic quadrilateral, the sum of degree measures of ∠A and ∠D is:
(SOURCE: Fig. 3.7, Exercise 3.7, Chapter 3, PAIR of LINEAR EQUATIONS in TWO VARIABLES,
NCERT, Class X)
(a) 120°
(b) 180°
(c) 230°(d) 250°
by

1 Answer

Answer :

(c) 230°
by

Related questions

ABCD is a trapezium in which AB || CD and AD = BC (see Fig. 8.23). Show that (i) ∠A = ∠B (ii) ∠C = ∠D (iii) ΔABC ≅ ΔBAD (iv) diagonal AC = diagonal BD [Hint : Extend AB and draw a line through C parallel to DA intersecting AB produced at E.] -Maths 9th

Description : ABCD is a trapezium in which AB || CD and AD = BC (see Fig. 8.23). Show that (i) ∠A = ∠B (ii) ∠C = ∠D (iii) ΔABC ≅ ΔBAD (iv) diagonal AC = diagonal BD [Hint : Extend AB and draw a line through C parallel to DA intersecting AB produced at E.] -Maths 9th

Last Answer : ] Solution: To Construct: Draw a line through C parallel to DA intersecting AB produced at E. (i) CE = AD (Opposite sides of a parallelogram) AD = BC (Given) , BC = CE ⇒∠CBE = ∠CEB also, ∠A+∠CBE = ... BC (Given) , ΔABC ≅ ΔBAD [SAS congruency] (iv) Diagonal AC = diagonal BD by CPCT as ΔABC ≅ ΔBA.

Chapter 3 Pair of Linear Equations in Two Variables

Description : Chapter 3 Pair of Linear Equations in Two Variables

Last Answer : Chapter 3 Pair of Linear Equations in Two Variables

If (x, y) is a solution of the following pair of linear equations in two variables, then the value of expression (√ is: x + 2y = 4 and 3x - y = 5 (a) 2 (b) 3 (c) 4 (d) √

Description : If (x, y) is a solution of the following pair of linear equations in two variables, then the value of expression (√ is: x + 2y = 4 and 3x - y = 5 (a) 2 (b) 3 (c) 4 (d) √2

Last Answer : (a) 2

ABCD is a rectangle in which diagonal AC bisects ∠A as well as ∠C. Show that: (i) ABCD is a square (ii) Diagonal BD bisects ∠B as well as ∠D. -Maths 9th

Description : ABCD is a rectangle in which diagonal AC bisects ∠A as well as ∠C. Show that: (i) ABCD is a square (ii) Diagonal BD bisects ∠B as well as ∠D. -Maths 9th

Last Answer : Solution: (i) ∠DAC = ∠DCA (AC bisects ∠A as well as ∠C) ⇒ AD = CD (Sides opposite to equal angles of a triangle are equal) also, CD = AB (Opposite sides of a rectangle) ,AB = BC = CD = AD Thus ... interior angles) ⇒ ∠CBD = ∠ABD Thus, BD bisects ∠B Now, ∠CBD = ∠ADB ⇒ ∠CDB = ∠ADB Thus, BD bisects ∠D

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.1 -Maths 9th

Last Answer : (i) (x + 4)(x + 10): Using the identity (x + a)(x + b) = x2 + (a + b)x + ab, we have: (x + 4)(x + 10) = x2 + (4 + 10)x + (4 x 10) = x2 + 14x + 40 (ii) (x + 8)(x - 10): Here, a = 8 and b = ( ... have 64m3 - 343n3 = (4m)3 - (7n)3 = (4m - 7n)[(4m)2 + (4m)(7n) + (7n)2] = (4m - 7n)(16m2 + 28mn + 49n2)

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.2 -Maths 9th

Last Answer : 1. How will you describe the position of a table lamp on your study table to another person ? To describe the position of a table lamp placed on the table, let us consider the table lamp as P and the table as a plane ... the point A(4, 3). (ii) A unique cross street as shown by the point B(3, 4).

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.3 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.3 -Maths 9th

Last Answer : 1: Draw the graph of each of the following linear equations in two variables: (i) x + y = 4 (ii) x - y = 2 (iii) y = 3x (iv) 3 = 2x + y Solution: (i)x + y= 4 ⇒ y = 4 - x If ... graph paper and joining them, we get a straight line PQ. Thus, PQ is the required graph of the linear equation y = 5x + 3.

NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 4 Linear Equation in Two Variables Exercise 4.4 -Maths 9th

Last Answer : 1. Give the geometric representations of y = 3 as an equation (i) in one variable (ii) in two variables (i) y = 3 [An equation in one variable] ∵ y = 3 is an equation in one variable, i.e. y only. ∴ It has ... equation in two variables] We can write 2x + 9 = 0 as 2x + 0y + 9 = 0 or 2x = -9 + 0y

Out of the following linear equations in two variables, the two representing a pair of parallel lines graphically are: 3x - 4y = 6 3x + 4y = 6 6x + 8y = 12 6x - 8y + 6 = 0 (a) 3x - 4y = 6 and 6x + 8y = 12 (b) 3x - 4y = 6 and 6x - 8y + 6 = 0 (c) 6x + 8y = 12 and 3x + 4y = 6 (d) 6x - 8y + 6 = 0 and 3x + 4y = 6

Description : Out of the following linear equations in two variables, the two representing a pair of parallel lines graphically are: 3x - 4y = 6 3x + 4y = 6 6x + 8y = 12 6x - 8y + 6 = 0 (a) 3x - 4y = 6 and 6x + 8y = 12 (b) 3x - 4y = 6 ... 6 = 0 (c) 6x + 8y = 12 and 3x + 4y = 6 (d) 6x - 8y + 6 = 0 and 3x + 4y = 6

Last Answer : (b) 3x - 4y = 6 and 6x - 8y + 6 = 0

The value(s) of 'k' for which the following pair of linear equations will represent a pair of intersecting lines graphically is/are: 3x - 4y + 7 = 0 kx - 8y = 5 (a) k = 6 (b) k ≠ 6(c) any real number (d) any real number except 6

Description : The value(s) of 'k' for which the following pair of linear equations will represent a pair of intersecting lines graphically is/are: 3x - 4y + 7 = 0 kx - 8y = 5 (a) k = 6 (b) k ≠ 6(c) any real number (d) any real number except 6

Last Answer : (d) any real number except 6

The solution of the following system of linear equations in two variables is: 55x + 67y = 311; 67x + 55y = 299 (a) (2, 3) (b) (3, 2) (c) (-2,3) (d) (3, -2)

Description : The solution of the following system of linear equations in two variables is: 55x + 67y = 311; 67x + 55y = 299 (a) (2, 3) (b) (3, 2) (c) (-2,3) (d) (3, -2)

Last Answer : (b) (3, 2)

Which of the following pair of linear equations represent the two parallel tracks of the railway line? a) x-2y-4=0 and 2x + 4y - 12 = 0 c) 2x + 4y -12 = 0 and x +2y-4=0 b) x +2y-4=0 and 2x + 4y +12 = 0 d) 2x + 4y + 12 = 0 and x-2y-4=0

Description : Which of the following pair of linear equations represent the two parallel tracks of the railway line? a) x-2y-4=0 and 2x + 4y - 12 = 0 c) 2x + 4y -12 = 0 and x +2y-4=0 b) x +2y-4=0 and 2x + 4y +12 = 0 d) 2x + 4y + 12 = 0 and x-2y-4=0

Last Answer : c) 2x + 4y -12 = 0 and x +2y-4=0

What is the value of x, y in the following pair of linear equations: 4x + = 15 , 6x – = 14 ? (a) 3,2 (b) -3,-2 (c) 3,-2 (d) -3,2

Description : What is the value of x, y in the following pair of linear equations: 4x + = 15 , 6x – = 14 ? (a) 3,2 (b) -3,-2 (c) 3,-2 (d) -3,2

Last Answer : (a) 3,2

What is the value of x, y in the following pair of linear equations: 4x + = 15 , 6x – = 14 ? (a) 3,2 (b) -3,-2 (c) 3,-2 (d) -3,2

Description : What is the value of x, y in the following pair of linear equations: 4x + = 15 , 6x – = 14 ? (a) 3,2 (b) -3,-2 (c) 3,-2 (d) -3,2

Last Answer : (a) 3,2

"Ravi is 10 years older than Rehan. Five years ago, one-seventh of Ravi's age was equal to one-fifth of Rehan's age." If Rehan's age be 'x' years and Ravi's age be 'y' years, which of the following pair of linear equations is describing it algebraically? (a) x - y = 10 and 7x - 5y + 10 = 0 (b) y -x = 10 and 5y -7x + 10 = 0 (c) x + y = 10 and 7x + 5y - 10 = 0 (d) x - y = -10 and 7y - 5x + 10 = 0

Description : "Ravi is 10 years older than Rehan. Five years ago, one-seventh of Ravi's age was equal to one-fifth of Rehan's age." If Rehan's age be 'x' years and Ravi's age be 'y' years, which of the following pair of linear equations is ... y = 10 and 7x + 5y - 10 = 0 (d) x - y = -10 and 7y - 5x + 10 = 0

Last Answer : (b) y -x = 10 and 5y -7x + 10 = 0

A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Description : A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Last Answer : (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Assertion (A):A pair of linear equations has no solution (s) if it represented by intersecting lines graphically. Reason (R) : If the pair of lines are intersecting, then the pair has unique solution and is called consistent pair of equations. (a) Both A and R are correct; R is the correct explanation of A. (b) Both A and R are correct; R is not the correct explanation of A. (c) A is correct; R is incorrect. (d) R is correct; A is incorrect.

Description : Assertion (A):A pair of linear equations has no solution (s) if it represented by intersecting lines graphically. Reason (R) : If the pair of lines are intersecting, then the pair has unique solution and is called ... of A. (c) A is correct; R is incorrect. (d) R is correct; A is incorrect.

Last Answer : (d) R is correct; A is incorrect.

One equation of a pair of dependent linear equations is -5x+7y=2 .The second equation can be (a)10x-14y-4=0 (b) -10x+14y+4=0 (c) 10x-14y-4=0 (d) -10x+14y-4=0

Description : One equation of a pair of dependent linear equations is -5x+7y=2 .The second equation can be (a)10x-14y-4=0 (b) -10x+14y+4=0 (c) 10x-14y-4=0 (d) -10x+14y-4=0

Last Answer : (d) -10x+14y-4=0

Diagonal AC of a parallelogram ABCD bisects ∠A (see Fig. 8.19). Show that (i) it bisects ∠C also, (ii) ABCD is a rhombus. -Maths 9th

Description : Diagonal AC of a parallelogram ABCD bisects ∠A (see Fig. 8.19). Show that (i) it bisects ∠C also, (ii) ABCD is a rhombus. -Maths 9th

Last Answer : . Solution: (i) In ΔADC and ΔCBA, AD = CB (Opposite sides of a parallelogram) DC = BA (Opposite sides of a parallelogram) AC = CA (Common Side) , ΔADC ≅ ΔCBA [SSS congruency] Thus, ∠ACD = ∠CAB by ... are equal) Also, AB = BC = CD = DA (Opposite sides of a parallelogram) Thus, ABCD is a rhombus.

MCQ Questions for Class 9 Maths Chapter 4 Linear Equations in Two Variables with answers -Maths 9th

Description : MCQ Questions for Class 9 Maths Chapter 4 Linear Equations in Two Variables with answers -Maths 9th

Last Answer : 1) The linear equation 3x-11y=10 has: a. Unique solution b. Two solutions c. Infinitely many solutions d.No solutions c Explanation: 3x-11y=10 y=(3x-10)/11 Now for infinite values of x, y will ... c=0, always lie in the: a. First quadrant b. Second quadrant c. Third quadrant d. Fourth quadrant a

Cbqs (case base study ) of chapter 4 Linear Equations in Two Variables of maths class 9th -Maths 9th

Description : Cbqs (case base study ) of chapter 4 Linear Equations in Two Variables of maths class 9th -Maths 9th

Last Answer : answer:

Diagonal AC of a parallelogram ABCD bisects ∠A (see figure). Show that (i) it bisects ∠C also, (ii) ABCD is a rhombus -Maths 9th

Description : Diagonal AC of a parallelogram ABCD bisects ∠A (see figure). Show that (i) it bisects ∠C also, (ii) ABCD is a rhombus -Maths 9th

Last Answer : (i) Here, ABCD is a parallelogram and diagonal AC bisects ∠A. ∴ ∠DAC=∠BAC ---- ( 1 ) Now, AB∥DC and AC as traversal, ∴ ∠BAC=∠DCA [ Alternate angles ] --- ( 2 ) AD∥BC and AAC as traversal, ∴ ∠DAC= ... ---- ( 2 ) From ( 1 ) and ( 2 ), ⇒ AB=BC=CD=DA Hence, ABCD is a rhombus.

NCERT Solutions for class 9 Maths Chapter 7 Triangles Exercise 7.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 7 Triangles Exercise 7.1 -Maths 9th

Last Answer : 1. In quadrilateral ACBD, AC = AD and AB bisects ∠A (see figure). Show that ΔABC ∠ ΔABD. What can you say about BC and BD ? In quadrilateral ABCD we have AC = AD and AB being the bisector of ∠A. Now, in ΔABC and ΔABD, AC = AD ... [Given] ∴ CM = (1/2) DC = (1/2) AB ⇒ CM = (1/2) AB

NCERT Solutions for class 9 Maths Chapter 7 Triangles Exercise 7.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 7 Triangles Exercise 7.2 -Maths 9th

Last Answer : 1. In an isosceles triangle ABC, with AB = AC, the bisectors of B and ∠C intersect each other at O. Join A to O. Show that: (i) OB = OC (ii) AO bisects ∠ A (i) In ΔABC, we have AB = AC ... 180° or x =(180o/3) = 60° ∴ ∠A= ∠B = ∠C = 60° Thus, the angles of an equilateral triangle are 60° each.

NCERT Solutions for class 9 Maths Chapter 7 Triangles Exercise 7.3 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 7 Triangles Exercise 7.3 -Maths 9th

Last Answer : 1. ΔABC and ΔDBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see figure). If AD is extended to intersect BC at P, show that (i) ΔABD ≌ ... [common] ∴ Using RHS criteria, ΔABP ≌ ΔACP ∴ Their corresponding parts are congruent. ⇒ ∠B= ∠C

NCERT Solutions for class 9 Maths Chapter 7 Triangles Exercise 7.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 7 Triangles Exercise 7.4 -Maths 9th

Last Answer : 1. Show that in a right angled triangle, the hypotenuse is the longest side Let us consider ΔABC such that ∠B = 90º ∴ ∠A + ∠B + ∠C = 180º ∴ [∠A + ∠C] + ∠B = 180º ⇒ ∠A + ∠C = 90º ⇒ ... on the line l. Thus, the perpendicular segment is the shortest line segment drawn on a line from a point not on it.

NCERT Solutions for class 9 Maths Chapter 7 Triangles Exercise 7.5 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 7 Triangles Exercise 7.5 -Maths 9th

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The pair of equations y=0 and y=-7 has (a)one solution (b)two solutions (c)no solution (d)infinitely many solutions

Description : The pair of equations y=0 and y=-7 has (a)one solution (b)two solutions (c)no solution (d)infinitely many solutions

Last Answer : (c)no solution

The pair of equations ax+2y=7 and 3x+by=16 represent parallel lines if (a)a=b (b)3a=2b (c)ab=6 (d)2a=3b

Description : The pair of equations ax+2y=7 and 3x+by=16 represent parallel lines if (a)a=b (b)3a=2b (c)ab=6 (d)2a=3b

Last Answer : (c)ab=6

The pair of equations 3 x + y = 81 , 81 x – y = 3 has (a) no solution (b) unique solution (c) infinitely many solutions (d) x = 2 , y = 1

Description : The pair of equations 3 x + y = 81 , 81 x – y = 3 has (a) no solution (b) unique solution (c) infinitely many solutions (d) x = 2 , y = 1

Last Answer : d) x = 2 , y = 1

The pair of equations 3 x + y = 81 , 81 x – y = 3 has (a) no solution (b) unique solution (c) infinitely many solutions (d) x = 2 , y = 1

Description : The pair of equations 3 x + y = 81 , 81 x – y = 3 has (a) no solution (b) unique solution (c) infinitely many solutions (d) x = 2 , y = 1

Last Answer : d) x = 2 , y = 1

Chapter 4 Quadratic Equations

Description : Chapter 4 Quadratic Equations

Last Answer : Chapter 4 Quadratic Equations

ABCD is a parallelogram with diagonal AC If a line XZ is drawn such that XZ ∥ AB, then BX/XC = ? (a) (AY/AC) (b) DZ/AZ (c) AZ/ZD (d) AC/AY Answer: (c) AZ/ZD 13. In the given figure, value of x (in cm) is (a) 5cm (b) 3.6 cm (c) 3.2 cm (d) 10 cm

Description : ABCD is a parallelogram with diagonal AC If a line XZ is drawn such that XZ ∥ AB, then BX/XC = ? (a) (AY/AC) (b) DZ/AZ (c) AZ/ZD (d) AC/AY Answer: (c) AZ/ZD 13. In the given figure, value of x (in cm) is (a) 5cm (b) 3.6 cm (c) 3.2 cm (d) 10 cm

Last Answer : (a) 5cm

If lines corresponding to given linear equations are coincident, the solutionof the given equations is: e) Unique solution f) Two solutionsg) Infintely many solutions h) No solution

Description : If lines corresponding to given linear equations are coincident, the solutionof the given equations is: e) Unique solution f) Two solutionsg) Infintely many solutions h) No solution

Last Answer : g) Infintely many solutions

If lines corresponding to given linear equations are coincident, the solutionof the given equations is: a) Unique solution b) Two solutions c) Infintely many solutions d) No solution

Description : If lines corresponding to given linear equations are coincident, the solutionof the given equations is: a) Unique solution b) Two solutions c) Infintely many solutions d) No solution

Last Answer : c) Infintely many solutions

What are some fast ways to solve a system of 3 linear equations with this special form?

Description : What are some fast ways to solve a system of 3 linear equations with this special form?

Last Answer : Perhaps an algebraic matrix ?

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Description : Assertion (A) : The value of k for which the system of linear equations kx+2y+1=0 and 6x+4y-5=0 has a unique solution is 3. Reason (R):The system of linear equations a1x + b1y + c1= 0 and a2x + ... not the correct explanation of A. (c) A is correct; R is incorrect. (d) R is correct; A is incorrect.

Last Answer : (d) R is correct; A is incorrect.

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.3 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.3 -Maths 9th

Last Answer : 1. Write the following in decimal form and say what kind of decimal expansion each has : (i) 36/100 Solution: = 0.36 (Terminating) (ii)1/11 Solution: Solution: = 4.125 (Terminating) ... Since the number,1.101001000100001 , is non-terminating non-repeating (non-recurring), it is an irrational number.

NCERT Solutions for class 9 Maths Chapter 1 Exercise 1.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Exercise 1.1 -Maths 9th

Last Answer : In this chapter, though our main topic is Heron’s (or Hero’s) formula given by Heron to calculate area of triangle whose sides are a, b, c as given under Yet, we list all formulas that were used at one point or other in this chapter.

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.2 -Maths 9th

Last Answer : Solids Bodies occupying space are called solids. A solid has three dimensions viz., length, breadth and thickness or depth or height. The space occupied by a solid body is called its volume .Volume ... a right-angled triangle VOA is revolved about OV, it generates a cone shown in figure alongside.

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.4 -Maths 9th

Last Answer : 1. Is zero a rational number ? Can you write it in the form p/q , where p and q are integers and q ≠ 0? Yes, zero is a rational number. We can write it in the form (p/q). That is zero. 2. ... such as -1, -2 are non-whole numbers] (iii) False statement [∵ Rational number (1/2) is not a whole number]

NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.5 . -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 1 Number System Exercise 1.5 . -Maths 9th

Last Answer : 1. State whether the following statements are true or false. Justify your answers. (i) Every irrational number is a real number. (ii) Every point on the number line is of the form √m , where m is a natural ... 5 ⇒ OC = √5 With O as centre and OC as radius, draw an arc intersecting OX at D. Since

NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.1 -Maths 9th

Last Answer : 1. Write the following in decimal form and say what kind of decimal expansion each has: 4. Express 0.99999 in the form p/q . Are you surprised by your answer? With your teacher ... ) 0.767076700767000767 (iii) 0.78080078008000780 9. Classify the following numbers as rational or irrational:

NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.2 -Maths 9th

Last Answer : 1. Visualise 3.765 on the number line, using successive magnification. 3.765 lies between 3 and 4. Let us divide the interval (3, 4) into 10 equal parts. Since, 3.765 lies between 3.7 and 3. ... 10 equal parts. Now, the point corresponding to 3.765 is clearly located, as shown in Fig. (iii) above.

NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.4 -Maths 9th

Last Answer : Classify the following numbers as rational or irrational: 2: Simplify each of the following expressions: 3. Recall, π is defined as the ratio of the circumference (say c) of a circle to ... is no contradiction in saying that π is irrational . 4. Rationalise the denominators of the following:

NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.5 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 2 Polynomials Exercise 2.5 -Maths 9th

Last Answer : 1. Which of the following expressions are polynomials in one variable and which are not ? State reasons for your answer. 2: Write the co-efficients of x2 in each of the following: (i) 2 + x2 + x The ... It is a quadratic polynomial. (vii) 7x3 ∵ The degree of 7x3 is 3. ∴ It is a cubic polynomial.

NCERT Solutions for class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.2 -Maths 9th

Last Answer : For x + 1 = 0, we have x = -1. ∴ The zero of x + 1 is -1. (i) p(x) = x3 + x2 + x + 1 ∴ p(-1) = (-1)3 + (-1)2 + (-1) + 1 = -1 + 1 - 1 + 1 = 0 i.e. when p(x) is divided by (x + 1), then the remainder is zero. ∴ ... ] = (y - 1)[2y(y + 1) + 1(y + 1)] = (y - 1)[(y + 1)(2y + 1)] = (y - 1)(y + 1)(2y + 1)

NCERT Solutions for class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 3 Coordinate Geometry Exercise 3.1 -Maths 9th

Last Answer : 1. Find the value of the polynomial 5x - 4x2 + 3 at (i) x = 0 (ii) x = -1 (iii) x = 2 (i) ∵ p(x) = 5x - 4x2 + 3 = 5(x) - 4(x)2 + 3 ∴ p(0) = 5(0) - 4(0) + 3 = 0 - 0 + 3 = 3 Thus, the value of 5x - 4x2 ... p(x) = cx + d ∴ p(x) = 0 ⇒ cx + d = 0 or c x = -d or x = - dc Thus, a zero of cx + d is - dc.

NCERT Solutions for class 9 Maths Chapter 5 Introduction to Euclid’s Geometry Exercise 5.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 5 Introduction to Euclid’s Geometry Exercise 5.2 -Maths 9th

Last Answer : 1. How would you rewrite Euclid's fifth postulate so that it would be easier to understand ? We can have: Two distinct intersecting lines cannot be parallel to the same line. 2. Does Euclid's fifth postulate imply ... other side also. ∴ The lines m' and n' never meet, i.e., they are parallel.

NCERT Solutions for class 9 Maths Chapter 6 Lines and Angles Exercise 6.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 6 Lines and Angles Exercise 6.1 -Maths 9th

Last Answer : 1. Which of the following statements are true and which are false? Give reasons for your answers. (i) Only one line can pass through a single point. (ii) There are an infinite number of lines which pass ... statement is true for all things and in all parts of Universe. So, it is a Universal truth'.