1) The linear equation 3x-11y=10 has: a. Unique solution b. Two solutions c. Infinitely many solutions d.No solutions c Explanation: 3x-11y=10 y=(3x-10)/11 Now for infinite values of x, y will also have the infinite solutions. 2) 3x+10 = 0 will has: a. Unique solution b. Two solutions c. Infinitely many solutions d.No solutions a Explanation: 3x+10 = 0 x = -10/3. Hence, only one solution is possible. 3) The solution of equation x-2y = 4 is: a. (0,2) b. (2,0) c. (4,0) d. (1,1) c Explanation: Putting x=4 and y = 0, on the L.H.S. of the given equation, we get; 4-2(0) = 4 – 0 = 4 Which is equal to R.H.S. 4) Find the value of k, if x = 1, y = 2 is a solution of the equation 2x + 3y = k. a. 5 b. 6 c. 7 d. 8 d Explanation: 2x + 3y = k k=2(1)+3(2) = 2+6 = 8 5) Point (3, 4) lies on the graph of the equation 3y = kx + 7. The value of k is: a. 4/3 b. 5/3 c. 3 d. 7/3 b Explanation: 3y = kx + 7 Here, x = 3 and y = 4 Hence, (3×4) = (kx3) + 7 12 = 3k+7 3k = 12–7 3k = 5 k = 5/3 6) The graph of linear equation x+2y = 2, cuts the y-axis at: a. (2,0) b. (0,2) c. (0,1) d. (1,1) c Explanation: x+2y = 2 y = (2-x)/2 If x=0, then; y=(2-0)/2 = 2/2 = 1 Hence, x+2y=2 cuts the y-axis at (0,1). 7) Any point on the line x = y is of the form: a. (k, -k) b. (0, k) c. (k, 0) d. (k, k) d 8) The graph of x = 3 is a line: a. Parallel to the x-axis at a distance of 3 units from the origin b. Parallel to the y-axis at a distance of 3 units from the origin c. Makes an intercept 3 on the x-axis d. Makes an intercept 3 on the y-axis b 9) In equation, y = mx+c, m is: a. Intercept b. Slope c. Solution of the equation d. None of the above b 10) If x and y are both positive solutions of equation ax+by+c=0, always lie in the: a. First quadrant b. Second quadrant c. Third quadrant d. Fourth quadrant a