In above numerical what will be the frequency corresponding to the peak amplitude A 14.18rad/sec B 24.13rad/sec C 20.22rad/sec D 22.32rad/sec

In above numerical what will be the frequency corresponding to the peak
amplitude
A 14.18rad/sec
B 24.13rad/sec
C 20.22rad/sec
D 22.32rad/sec
by

1 Answer

Answer :

A 14.18rad/sec
by

Related questions

Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 21 rad/sec B 25.62 rad/sec C 20.22 Hz D 3.15 Hz

Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 21 rad/sec B 25.62 rad/sec C 20.22 Hz D 3.15 Hz

Last Answer : B 25.62 rad/sec

If frequency of excitation of a forced vibration system with negligible damping is very close to natural frequency of the system, then the system will A) Execute harmonic motion of large amplitude B) Beat with a very high peak amplitude C) Perform aperiodic motion D) None of the above

Description : If frequency of excitation of a forced vibration system with negligible damping is very close to natural frequency of the system, then the system will A) Execute harmonic motion of large amplitude B) Beat with a very high peak amplitude C) Perform aperiodic motion D) None of the above

Last Answer : A) Execute harmonic motion of large amplitude

If ωmax is the frequency at which the peak amplitude occurs and ωn is the natural frequency of the system then In a forced vibration system with damping, the higher the damping, A) More will be the difference between ωn and ωmax B) Less will be the difference between ωn and ωmax C) The difference of ωn and ωmax is independent of damping in this system D) The difference between ωn and ωmax will be zero

Description : If ωmax is the frequency at which the peak amplitude occurs and ωn is the natural frequency of the system then In a forced vibration system with damping, the higher the damping, A) More will be ... and ωmax is independent of damping in this system D) The difference between ωn and ωmax will be zero

Last Answer : A) More will be the difference between ωn and ωmax

Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 25.62 rad/sec B 20.78 rad/sec C 14.4 rad/sec D 15.33 rad/sec

Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. A 25.62 rad/sec B 20.78 rad/sec C 14.4 rad/sec D 15.33 rad/sec

Last Answer : A 25.62 rad/sec

Calculate natural frequency of damped vibration, if damping factor is 0.52 and A natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. ( A )25.62 rad/sec ( B )20.78 rad/sec ( C )14.4 rad/sec ( D )15.33 rad/sec

Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and A natural frequency of the system is 30 rad/sec which consists of machine supported on springs and dashpots. ( A )25.62 rad/sec ( B )20.78 rad/sec ( C )14.4 rad/sec ( D )15.33 rad/sec

Last Answer : ( A )25.62 rad/sec

Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequ the system is 30 rad/sec which consists of machine supported on springs and dashpots. a. 25.62 rad/secb. 20.78 rad/sec c. 14.4 rad/sec d. 15.33 rad/sec

Description : Calculate natural frequency of damped vibration, if damping factor is 0.52 and natural frequ the system is 30 rad/sec which consists of machine supported on springs and dashpots. a. 25.62 rad/secb. 20.78 rad/sec c. 14.4 rad/sec d. 15.33 rad/sec

Last Answer : a. 25.62 rad/sec

Determine natural frequency of a system, which has equivalent spring stiffness of 43200 N/m and mass of 12 kg. A 40.22 rad/sec B 40 Hz C 60 Hz D 60 rad/sec

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 43200 N/m and mass of 12 kg. A 40.22 rad/sec B 40 Hz C 60 Hz D 60 rad/sec

Last Answer : D 60 rad/sec

In above numerical what will be the new time period if the spring constant is decreased by 50%. A 0.5 sec B 0.353 sec C 0.125 sec D 0.533 sec

Description : In above numerical what will be the new time period if the spring constant is decreased by 50%. A 0.5 sec B 0.353 sec C 0.125 sec D 0.533 sec

Last Answer : B 0.353 sec

Transmissibility in a support excitation system is defined by A) Ratio of absolute amplitude of the mass to the excitation amplitude of the support B) Reciprocal of (a) C) Ratio of the force transmitted to the foundation, to the equivalent force corresponding to maximum displacement excitation D) None of the above

Description : Transmissibility in a support excitation system is defined by A) Ratio of absolute amplitude of the mass to the excitation amplitude of the support B) Reciprocal of (a) C) Ratio of the ... the foundation, to the equivalent force corresponding to maximum displacement excitation D) None of the above

Last Answer : B) Reciprocal of (a)

Calculate damped natural frequency, if a spring mass damper system is subjected to periodic disturbing force of 30 N. Damping coefficient is equal to 0.76 times of critical damping coefficient and undamped natural frequency is 5 rad/sec A. 3.99 rad/sec B. 2.13 rad/sec C. 4.12 rad/sec D. 3.24 rad/sec

Description : Calculate damped natural frequency, if a spring mass damper system is subjected to periodic disturbing force of 30 N. Damping coefficient is equal to 0.76 times of critical damping coefficient and undamped natural frequency is 5 rad/sec A. 3.99 rad/sec B. 2.13 rad/sec C. 4.12 rad/sec D. 3.24 rad/sec

Last Answer : D. 3.24 rad/sec

A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Description : A 1 kg mass is suspended by a spring having a stiffness of 0.4 N/mm. Determine the natural frequency. A 20 rad/sec B 30 rad/sec C 20 Hz D 30 Hz

Last Answer : B 30 rad/sec

A body is executing simple harmonic motion of amplitude 1 cm. Its velocitywhile passing through the central point is 10 mm/sec. Its frequency will be a.2.99 rps b.2.22 rps c.1 rps d.1.59 rps e.1.77 rps

Description : A body is executing simple harmonic motion of amplitude 1 cm. Its velocitywhile passing through the central point is 10 mm/sec. Its frequency will be a.2.99 rps b.2.22 rps c.1 rps d.1.59 rps e.1.77 rps

Last Answer : c. 1 rps

A single degree of freedom spring-mass system is subjected to a harmonic force of constant amplitude. For an excitation frequency of √3k/m , the ratio of the amplitude of steady state response to the static deflection of the spring is __________ A. 0.2 B. 0.5 C. 0.8 D. None of the above

Description : A single degree of freedom spring-mass system is subjected to a harmonic force of constant amplitude. For an excitation frequency of √3k/m , the ratio of the amplitude of steady state response to the static deflection of the spring is __________ A. 0.2 B. 0.5 C. 0.8 D. None of the above

Last Answer : B. 0.5

In damped free vibrations, which parameters indicate vibrations? A) Natural frequency B) Rate of decay of amplitude C) Both a. and b. D) None of the above

Description : In damped free vibrations, which parameters indicate vibrations? A) Natural frequency B) Rate of decay of amplitude C) Both a. and b. D) None of the above

Last Answer : C) Both a. and b.

In the case of steady state forced vibration at a resonance, the amplitude of vibration is A) Inversely proportional to damping coefficient B) Inversely proportional to damping ratio C) Inversely proportional to resonant frequency D) Directly proportional to resonant frequency

Description : In the case of steady state forced vibration at a resonance, the amplitude of vibration is A) Inversely proportional to damping coefficient B) Inversely proportional to damping ratio C) Inversely proportional to resonant frequency D) Directly proportional to resonant frequency

Last Answer : B) Inversely proportional to damping ratio

If the amplitude of harmonic motion is large, its frequency A) Will always be high B) Will always be less C) Can have any value D) Will be zero

Description : If the amplitude of harmonic motion is large, its frequency A) Will always be high B) Will always be less C) Can have any value D) Will be zero

Last Answer : C) Can have any value

When the frequency of external exciting force is equal to the natural frequency of the vibration of the system A. The amplitude of vibration is zero B. The amplitude of vibration is significantly small C. The amplitude of vibration is very large D. The amplitude does not change

Description : When the frequency of external exciting force is equal to the natural frequency of the vibration of the system A. The amplitude of vibration is zero B. The amplitude of vibration is significantly small C. The amplitude of vibration is very large D. The amplitude does not change

Last Answer : C. The amplitude of vibration is very large

The motion of particle is represented by, x = Asin(wt) in which A stands for A. Amplitude B. Wavelength C. Frequency D. Damping

Description : The motion of particle is represented by, x = Asin(wt) in which A stands for A. Amplitude B. Wavelength C. Frequency D. Damping

Last Answer : A. Amplitude

The number of cycles per unit time is called _________ A. Period B. Frequency C. Amplitude D. Wavelength

Description : The number of cycles per unit time is called _________ A. Period B. Frequency C. Amplitude D. Wavelength

Last Answer : B. Frequency

In damped free vibrations, which parameters indicate vibrations? a. Natural frequency b. Rate of decay of amplitude c. Both a. and b. d. None of the above

Description : In damped free vibrations, which parameters indicate vibrations? a. Natural frequency b. Rate of decay of amplitude c. Both a. and b. d. None of the above

Last Answer : c. Both a. and b.

A spring mass system has time period of oscillation of 0.25 sec. What will be the natural frequency of the system? A 1 Hz B 2 rad sec C 4 rad/sec D 4 Hz

Description : A spring mass system has time period of oscillation of 0.25 sec. What will be the natural frequency of the system? A 1 Hz B 2 rad sec C 4 rad/sec D 4 Hz

Last Answer : D 4 Hz

Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 –3 m 3. Natural frequency of the system = 60 rad/sec A. 100.5 x 10 3 N-s/m B. 80 x 10 3 N-s/m C. 42 x 10 3 N-s/m D. None of the above

Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m B. 80 x 10 3 N-s/m C. 42 x 10 3 N-s/m D. None of the above

Last Answer : C. 42 x 10 3 N-s/m

In spring mass experiment, the natural frequency of 10 kg mass was found to be 12 rad/sec. the stiffness of the spring is A. 800 N/m B. 1200 N/m C. 1440 N/m D. 2000 N/m

Description : In spring mass experiment, the natural frequency of 10 kg mass was found to be 12 rad/sec. the stiffness of the spring is A. 800 N/m B. 1200 N/m C. 1440 N/m D. 2000 N/m

Last Answer : C. 1440 N/m

The unit of natural frequency is A. Rad/sec B. Hz C. Both D. No unit

Description : The unit of natural frequency is A. Rad/sec B. Hz C. Both D. No unit

Last Answer : C. Both

Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 –3 m 3. Natural frequency of the system = 60 rad/sec a. 100.5 x 10 3 N-s/m b. 80 x 10 3 N-s/m c. 42 x 10 3 N-s/m d. None of the above

Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m b. 80 x 10 3 N-s/m c. 42 x 10 3 N-s/m d. None of the above

Last Answer : c. 42 x 10 3 N-s/m

find the value of logarithmic decrement of a vibratory system if its natural frequency is 10rad/sec, its mass is 10kg and its damping constant is 100N.s/m a) 36.27 b)362.7 c)0.3627 d)3.627

Description : find the value of logarithmic decrement of a vibratory system if its natural frequency is 10rad/sec, its mass is 10kg and its damping constant is 100N.s/m a) 36.27 b)362.7 c)0.3627 d)3.627

Last Answer : d)3.627

A car weighing 1000kg deflects its springs by 0.4cm under its load. Determine the natural frequency of 2 car in vertical direction take g=10N/m a) 25 rad/sec b)50 rad/sec c) 2 rad/sec d)none

Description : A car weighing 1000kg deflects its springs by 0.4cm under its load. Determine the natural frequency of 2 car in vertical direction take g=10N/m a) 25 rad/sec b)50 rad/sec c) 2 rad/sec d)none

Last Answer : b)50 rad/sec

A spring-mass system has a natural frequency of 10 rad/sec. When the spring constant is reduced by 800 N/m, the frequency is altered by 45 percent. Find the mass and spring constant of the original system. a)11.47kg and 1147.95N/m b)8.95kg and 895.25N/m c) 7.265kg and 726.5N/m d)None

Description : A spring-mass system has a natural frequency of 10 rad/sec. When the spring constant is reduced by 800 N/m, the frequency is altered by 45 percent. Find the mass and spring constant of the original system. a)11.47kg and 1147.95N/m b)8.95kg and 895.25N/m c) 7.265kg and 726.5N/m d)None

Last Answer : a)11.47kg and 1147.95N/m

Calculate the value of critical damping coefficient if a vibrating system has mass of 4kg and stiffness of 100N/m A 20 N-sec/m B 40 N-sec/m C 60 N-sec/m D 80 N-sec/m

Description : Calculate the value of critical damping coefficient if a vibrating system has mass of 4kg and stiffness of 100N/m A 20 N-sec/m B 40 N-sec/m C 60 N-sec/m D 80 N-sec/m

Last Answer : B 40 N-sec/m

In a 2-mass 3 spring vibrating system the two masses each are of 9.8 kg coupling spring is having a stiffness of 3430 N/m whereas the other two springs have each a stiffness of 8820 N/m. The two natural frequencies in rad /sec are A) 10 & 20 B) 20 & 30 C) 30 & 40D) 40 & 50

Description : In a 2-mass 3 spring vibrating system the two masses each are of 9.8 kg coupling spring is having a stiffness of 3430 N/m whereas the other two springs have each a stiffness of 8820 N/m. The two natural frequencies in rad /sec are A) 10 & 20 B) 20 & 30 C) 30 & 40D) 40 & 50

Last Answer : C) 30 & 40

A rotary system has a damping coefficient of 40 N-m-sec/rad. The damping torque at a velocity of 2 rad/s, will be A) 20 N-m B) 40 N-m C) 80 N-m D) 100 N-m

Description : A rotary system has a damping coefficient of 40 N-m-sec/rad. The damping torque at a velocity of 2 rad/s, will be A) 20 N-m B) 40 N-m C) 80 N-m D) 100 N-m

Last Answer : C) 80 N-m

From above numerical find the static deflection A 0.0245 mm B 0.0025 mm C 0.0245 m D 0.0245 cm

Description : From above numerical find the static deflection A 0.0245 mm B 0.0025 mm C 0.0245 m D 0.0245 cm

Last Answer : C 0.0245 m

A carrier signal has ______. A. Constant peak amplitude B. The information C. Frequency range 20-20000 Hz D. A varying amplitude

Description : A carrier signal has ______. A. Constant peak amplitude B. The information C. Frequency range 20-20000 Hz D. A varying amplitude

Last Answer : A. Constant peak amplitude

A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. A. 5.14 Hz B. 9.14 Hz C. 11.14 Hz D. 28.14 Hz

Description : A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. A. 5.14 Hz B. 9.14 Hz C. 11.14 Hz D. 28.14 Hz

Last Answer : C. 11.14 Hz

A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. (A) 5.14 Hz (B) 9.14 Hz (C) 11.14 Hz (D) 28.14 Hz

Description : A system has a mass of 0.5 kg and spring stiffness of 2452 N/m. Find the natural frequency of the system. (A) 5.14 Hz (B) 9.14 Hz (C) 11.14 Hz (D) 28.14 Hz

Last Answer : (C) 11.14 Hz

f the mass is of 10 Kg, find the natural frequency in Hz of the free longitudinal vibrations. The displacement is 0.01mm. a) 44.14 b) 49.85 c) 43.43 d) 46.34

Description : f the mass is of 10 Kg, find the natural frequency in Hz of the free longitudinal vibrations. The displacement is 0.01mm. a) 44.14 b) 49.85 c) 43.43 d) 46.34

Last Answer : b) 49.85

Find the natural frequency in Hz of the free longitudinal vibrations if the displacement is 2mm. a) 11.14 b) 12.38 c) 11.43 d) 11.34

Description : Find the natural frequency in Hz of the free longitudinal vibrations if the displacement is 2mm. a) 11.14 b) 12.38 c) 11.43 d) 11.34

Last Answer : a) 11.14

what is the whole numerical expression for 22 plus 14

Description : what is the whole numerical expression for 22 plus 14

Last Answer : 22+14=36 B-)

In damped vibrations, the amplitude of the resulting vibration gradually reduces. This is due to the reason that an amount of energy is always dissipated to overcome the ________ * 1 point (A) Frictional resistance (B) Work done(C) Fluid pressure (D) Air pressure

Description : In damped vibrations, the amplitude of the resulting vibration gradually reduces. This is due to the reason that an amount of energy is always dissipated to overcome the ________ * 1 point (A) Frictional resistance (B) Work done(C) Fluid pressure (D) Air pressure

Last Answer : (A) Frictional resistance

When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as * 1 point (A) simple pendulum (B) torsional pendulum (C) compound pendulum (D) second’s pendulum

Description : When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as * 1 point (A) simple pendulum (B) torsional pendulum (C) compound pendulum (D) second’s pendulum

Last Answer : (C) compound pendulum

Which of the following instruments measure the amplitude of a vibrating body? (A) Vibrometers (B) Seismometer (C) Both (a) and (b) (D) None of these

Description : Which of the following instruments measure the amplitude of a vibrating body? (A) Vibrometers (B) Seismometer (C) Both (a) and (b) (D) None of these

Last Answer : (C) Both (a) and (b)

In steady state forced vibrations, the amplitude of vibrations at resonance is _____________ damping coefficient. A equal to B directly proportional to C inversely proportional to D independent of

Description : In steady state forced vibrations, the amplitude of vibrations at resonance is _____________ damping coefficient. A equal to B directly proportional to C inversely proportional to D independent of

Last Answer : C inversely proportional to

When there is a reduction in amplitude over every cycle of vibration, then the body is said to have A Free vibration B Forced vibration C Damped vibration D None of the mentioned

Description : When there is a reduction in amplitude over every cycle of vibration, then the body is said to have A Free vibration B Forced vibration C Damped vibration D None of the mentioned

Last Answer : C Damped vibration

In under damped vibrating system, if x 1 and x 2 are the successive values of the amplitude on the same side of the mean position, then the logarithmic decrement is equal to A x 1 /x 2 B log (x 1 /x 2 ) C loge (x 1 /x 2 ) D log (x 1 .x 2 )

Description : In under damped vibrating system, if x 1 and x 2 are the successive values of the amplitude on the same side of the mean position, then the logarithmic decrement is equal to A x 1 /x 2 B log (x 1 /x 2 ) C loge (x 1 /x 2 ) D log (x 1 .x 2 )

Last Answer : C loge (x 1 /x 2 )

What is meant by node point? A. The point at which amplitude of vibration is maximum B. The point at which amplitude of vibration is minimum C. The point at which amplitude of vibration is zero D. None of the above

Description : What is meant by node point? A. The point at which amplitude of vibration is maximum B. The point at which amplitude of vibration is minimum C. The point at which amplitude of vibration is zero D. None of the above

Last Answer : C. The point at which amplitude of vibration is zero

A vibrating system having mass 1kg, a spring of stiffness 1000N/m and damping factor of 0.632 and it is put to harmonic excitation of 10N. Find the amplitude at resonance. A 0.079 B 7.9C 0.056 D 0.00791

Description : A vibrating system having mass 1kg, a spring of stiffness 1000N/m and damping factor of 0.632 and it is put to harmonic excitation of 10N. Find the amplitude at resonance. A 0.079 B 7.9C 0.056 D 0.00791

Last Answer : D 0.00791

Calculate logarithmic decrement if the amplitude of the vibrating body reduces to half in two cycles A 0.346 B 0.693 C 0.301 D 0.150

Description : Calculate logarithmic decrement if the amplitude of the vibrating body reduces to half in two cycles A 0.346 B 0.693 C 0.301 D 0.150

Last Answer : A 0.346

During resonance A the Vibrations remains unaffected B no vibration occurs C low amplitude of vibration occurs D high amplitude of vibration occurs

Description : During resonance A the Vibrations remains unaffected B no vibration occurs C low amplitude of vibration occurs D high amplitude of vibration occurs

Last Answer : D high amplitude of vibration occurs

In steady state forced vibrations, the amplitude of vibrations at resonance is __________ damping coefficient. A. Equal to B. Directly proportional to C. Inversely proportional toD. Independent of

Description : In steady state forced vibrations, the amplitude of vibrations at resonance is __________ damping coefficient. A. Equal to B. Directly proportional to C. Inversely proportional toD. Independent of

Last Answer : C. Inversely proportional to