Description : Sodium reacts with water to form sodium hydroxide and hydrogen gas. The balanced equation which represents the above reaction is (a) Na(s) + 2H20(l) → 2NaOH(aq) + 2H2(g) (b) 2Na(s) + 2H2O(l) → 2NaOH(aq) +H2(g) (c) 2Na(s) + 2H20(l) → NaOH(aq) + 2H2(g) (d) 2Na(s) + H20(l) - 2NaOH(aq) + 2H2(g)
Last Answer : Answer: (b)
Description : What Sodium (Na) and water (H2O) undergo a chemical reaction that produces sodium hydroxide (NaOH and hydrogen gas (H2). Which equation represents this chemical reaction?
Last Answer : 2Na+2H20->2Na0H+H2 ::::apex
Description : The common name for the com-pound having formal NaOH is – (1) Caustic soda (2) Caustic potash (3) Soda ash (4) Sodium hydroxide
Last Answer : (1) Caustic soda Explanation: Sodium hydroxide, also known as lye or caustic soda, has the molecular formula NaOH and is a highly caustic metallic base. It is a white solid available in pellets ... manufacture of pulp and paper, textiles, drinking water, soaps and detergents and as a drain cleaner.
Description : Explain the manufacture of Sodium Hydroxide (Caustic Soda), NaOH by castner kellner cell
Last Answer : Preperation--Sodium hydroxide is generally prepared commercially by the electrolysis of sodium chloride in Castner-Kellner cell. A brine solution is electrolysed using a mercury cathode and a carbon anode. Sodium ... The amalgam is treated with water to give sodium hydroxide and hydrogen gas.
Description : The common name for the compound having formal NaOH is (1) Caustic soda (2) Caustic potash (3) Soda ash (4) Sodium hydroxide
Last Answer : Caustic soda
Description : Which is the best reagent to convert isopropyl alcohol to isopropyl bromide ? `CH_(3)- overset(CH_(3))overset(|)(CH)- OH overset(?)rarr CH_(3) - overs
Last Answer : Which is the best reagent to convert isopropyl alcohol to isopropyl bromide ? `CH_(3)- overset(CH_(3))overset(|)(CH ... )` C. `Br_(2)` D. `CH_(3)MgBr`
Description : When formaldehyde and potassium hydroxide are heated, we get (1) Acetylene (2) Methyl alcohol (3) Methane (4) Ethyl formate
Last Answer : Methyl alcohol
Description : Benzoyl chloride on basic-hydrolysis (NaOH/H2O) gives : (a) Benzoic acid (b) Methyl benzoate (c) Sodium benzoate (d) Ethyl benzoate
Last Answer : Sodium benzoate
Description : When benzaldehyde is heated with concentrated NaOH, it gives : (a) Benzyl alcohol (b) Sodium benzoate (c) Benzoic acid (d) Benzyl alcohol + Sodium benzoate
Last Answer : Benzyl alcohol + Sodium benzoate
Description : When equal weight of methyl alcohol and ehtyl alcohol react with excess of sodium metal, the volume of `H_(2)` liberated is more in the case of
Last Answer : When equal weight of methyl alcohol and ehtyl alcohol react with excess of sodium metal, the volume of `H_(2 ... in both D. `H_(2)` is not liberated
Description : Ethyl bromide reacts with sodium methoxide to form (a) Diethyl ether (b) Ethyl methyl ether (c) Dimethyl ether (d) n-Propyl alcohol
Last Answer : Ethyl methyl ether
Description : Carbylamine test involves heating a mixture of (a) alcoholic KOH, methyl iodide, and sodium metal (b) alcoholic KOH, methyl iodide, and primary amine (c) alcoholic KOH, chloroform, and primary amine (d) alcoholic KOH, methyl alcohol, and primary amine
Last Answer : alcoholic KOH, chloroform, and primary amine
Description : The functional group present in CH 3 OH is
Last Answer : alcohol.
Description : Arrange the compounds in order of decreasing acidic strength : (I) `ClCH_(2)-CH_(2)-OH` (II) `Cl_(2)CH-CH_(2)-OH` (III) `Cl-CH_(2)-CH_(2)-CH_(2)-OH` (
Last Answer : Arrange the compounds in order of decreasing acidic strength : (I) `ClCH_(2)-CH_(2)-OH` (II) `Cl_(2)CH-CH_(2 ... IV gt III` D. `II gt I gt III gt IV`
Description : Write down the IUPAC names of the following compounds :- (A) `CH_(3)-underset(C_(2)H_(5))underset(|)(CH)-overset(CH_(3))overset(|)(CH)-underset(OH)und
Last Answer : Write down the IUPAC names of the following compounds :- (A) `CH_(3)-underset(C_(2)H_(5))underset(|)( ... )=CH-underset(CH_(3))underset(|)(CH)-C-=CH`
Description : `CH_(3)CH_(2)CH(OH)CH(CH_(3))_(2)+CH_(3)COCI overset("base")rarr CH_(3)CH_(2)CH(OCOCH_(3))CH(CH_(3))_(2)+HCI` In the above reaction, if the reactant a
Last Answer : `CH_(3)CH_(2)CH(OH)CH(CH_(3))_(2)+CH_(3)COCI overset("base")rarr CH_(3)CH_(2) ... the same configuration at the chiral atom D. be optically inactive
Description : The correct statement(s) about the compound `H_(3)C(HO)HC-CH=CH-CH(OH)CH_(3) (X)` is/are
Last Answer : The correct statement(s) about the compound `H_(3)C(HO)HC-CH=CH-CH(OH)CH_(3) (X)` is/are A ... is cis, the number of enantiomers possible for X is 2.
Description : Tartaric acid `[HO_(2)CCH(OH)CH(OH)CO_(2)H]` was an important compound in history of stereochemistry. Two naturally occuring forms of tartaric acid ar
Last Answer : Tartaric acid `[HO_(2)CCH(OH)CH(OH)CO_(2)H]` was an important compound in history ... . D. Optically inactive due to intramoleuclar hydrogen bonding.
Last Answer : Tartaric acid `[HO_(2)CCH(OH)CH(OH)CO_(2)H]` was an important compound in history of stereochemistry. Two ... form Q is A. B. C. D. none of these
Description : For the given compound `CH_(3)-underset(overset(|)(OH))(CH)-CH=CH-CH_(3).` (i) Total number of stereoisomers. (ii) Number of opticallly active stereoi
Last Answer : For the given compound `CH_(3)-underset(overset(|)(OH))(CH)-CH=CH-CH_(3).` ... number of fractions on fractional distillation of all stereoisomers.
Description : Condiser the reactions, (i) `(CH_(3))_(2)CH-CH_(2)Broverset(C_(2)H_(5)OH)rarr(CH_(3))_(2)CH-CH_(2)OC_(2)H_(5)+HBr` (ii) `(CH_(3))_(2)CH-CH_(2)Broverse
Last Answer : Condiser the reactions, (i) `(CH_(3))_(2)CH-CH_(2)Broverset(C_(2)H_(5)OH)rarr(CH_(3))_(2)CH-CH_(2)OC_(2)H_(5) ... N^(1))` D. `S_(N^(2)) and S_(N^(2))`
Description : The final major product of the reaction is: `Ph-overset(OH)overset(|)underset(Ph)underset(|)(C)-underset(" "NH_(2))underset(|)(CH)-CH_(3)overset(NaNO_
Last Answer : The final major product of the reaction is: `Ph-overset(OH)overset(|)underset(Ph)underset(|)(C)-underset(" " ... (" "CH_(3))underset(|)(C)-CH_(3)`
Description : `CH_(3)-CH_(2)-CH_(2)-underset(OH)underset(|)(CH)-CH_(3) underset(-H_(2)O)overset(H^(o+))rarr[F] overset(Br_(2)//C Cl_(4))rarrC_(5)H_(10)Br_(2)(G)` Ho
Last Answer : `CH_(3)-CH_(2)-CH_(2)-underset(OH)underset(|)(CH)-CH_(3) underset(-H_(2)O)overset(H^(o+))rarr[F] ... (including all stereoisomers) A. 2 B. 6 C. 3 D. 5
Description : The figure shows a hypothetical tetrapeptide portion of a protein with parts labelled A-D. Which one of the following options is correct? - HN - CH - CO - NH - CH - CO - NH - CH - CO - ... -terminal amino acid and D is N-terminal amino acid. (d) A is a sulphur containing amino acid methionine.
Last Answer : (a) D is the acidic amino acid-glutamic acid.
Description : Phenol reacts with methyl chloroformate in the presence of `NaOH` to form product A. A reacts with `Br_(2)` to form product B. A and B are respectivel
Last Answer : Phenol reacts with methyl chloroformate in the presence of `NaOH` to form product A. A reacts with `Br_(2)` ... A and B are respectively A. B. C. D.
Description : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to
Last Answer : A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein ... solution is `(NaOH=40, Na_(2)CO_(3)=106)`
Description : Oil of Wintergreen (Methyl salicylate) is obtained by treating salicylic acid with (a) Methane at 150°C (b) CH3OH and conc. H2SO4 (c) Methyl chloride (d) NaOH and then CH3OH
Last Answer : CH3OH and conc. H2SO4
Description : Which of the following reagents readily react with ethyl methyl ether? (a) NaOH (b) Conc HI (c) KMnO4 (d) H2O
Last Answer : Conc HI
Description : Which of the following alcohols will give a yellow precipitate of iodoform with iodine and dilute NaOH solution? (a) 1-Propanol (b) 2-Propanol (c) 1-Butanol (d) 2-Methyl-2-propanol
Last Answer : 2-Propanol
Description : Even though NaOH & KOH contains –OH group. It is not included in the group of organic substances. Why?
Last Answer : NaOH and KOH are strong bases which are ionic compound that contain OH ions. Alcohols are covalent compounds, even though they have on or more hydroxyl ( -OH ) functional group, they do not behave like bases. The – OH group attached to a carbon atom is a covalent bond.
Description : Which among the following is not a base? (a) NaOH (b) KOH ( c) NH4OH (d)C2H5 OH
Last Answer : (d)C2H5 OH
Description : 1 mol of `H_(3)PO_(2), H_(3)PO_(3)` and `H_(3)PO_(4)` will neutralise x mol `NaOH`, y mol of `Ca(OH)_(2)` and z mol of `Al(OH)_(3)` respectively (assu
Last Answer : 1 mol of `H_(3)PO_(2), H_(3)PO_(3)` and `H_(3)PO_(4)` will neutralise x mol `NaOH`, y mol of `Ca(OH)_(2)` and ... :1` B. `1:2:3` C. `3:2:1` D. `1:1:1`
Description : 22. \( H _{2} O \) can act either as an acid or base. Which of the following reaction best illustrate the behaviour of water as a base?(a) \( H _{2} O + NH _{3} \rightarrow OH ^{+}+ NH _{4}^{-} \)(b) \( H _{ ... O \rightarrow H _{3} O ^{+}+ Cl ^{-} \)(d) \( HCl + NaOH \rightarrow NaCl + H _{2} O \)
Last Answer : 22. \( H _{2} O \) can act either as an acid or base. Which of the following reaction best illustrate ... HCl + NaOH \rightarrow NaCl + H _{2} O \)
Description : `C_(6)H_(5)OH+CHCl_(3)+NaOH rarr` salicyladehyde The electrophile involved in the above reaction is.
Last Answer : `C_(6)H_(5)OH+CHCl_(3)+NaOH rarr` salicyladehyde The electrophile involved in the above reaction is. A. ... ` D. formly cation `(overset(o+)(C)HO)`
Description : Which of the following is a base (APEX)HI (hydroiodic acid)Ca(OH)2 (calcium hydroxide)H2CO3 (carbonic acid)HNO3 (nitric acid)?
Last Answer : Ca(OH)2 (calcium hydroxide) (Apex)
Description : 1 mole of `OH^(-)` ions is obtained from 85 g of hydroxide of a metal. What is the equivalent weight of the metal ?
Last Answer : 1 mole of `OH^(-)` ions is obtained from 85 g of hydroxide of a metal. What is the equivalent weight of the metal ?
Description : How many moles are in 98.3 grams of aluminum hydroxide Al(OH)3?
Last Answer : Need answer
Description : Write a note on the Physical Properties of Calcium Hydroxide (Slaked lime), Ca(OH)2
Last Answer : It is a white amorphous powder. It is sparingly soluble in water. The aqueous solution is known as lime water and a suspension of slaked lime in water is known as milk of lime.
Description : How is Calcium Hydroxide (Slaked lime), Ca(OH)2 Prepared?
Last Answer : Calcium hydroxide is prepared by adding water to quick lime, CaO.
Description : RNA does not contain (A) adenine (B) OH methyl cytosine (C) d-ribose (D) Uracil
Last Answer : Answer : B
Description : In beri beri there will be accumulation of _______ in blood. (A) Aceto acetic acid (B) β-OH butyric acid (C) Pyruvic acid (D) Methyl malonic acid
Last Answer : Answer : C
Description : All the following correctly describe the intermediate 3-OH-3-methyl glutaryl CoA except (A) It is generated enzymatically in the mitochondrial matrix (B) It is formed in the cytoplasm (C) It inhibits the first step in cholesterol synthesis (D) It is involved in the synthesis of ketone bodies
Description : All statements regarding 3-OH-3 methyl glutaryl CoA are true except (A) It is formed in the cytoplasm (B) Required in ketogenesis (C) Involved in synthesis of Fatty acid (D) An intermediate in cholesterol biosynthesis
Description : What is the IUPAC name for the following structure? CH3CH(CH3)CH2CH(OH)CH3 (a) 4-methyl-2-pentanol (b) 2-methyl-2-hexanol (c) 2-methyl-4-pentanol (d) 2-methyl-3-pentanol
Last Answer : 4-methyl-2-pentanol
Description : `CH_(3) - underset(CH_(3))underset(|)(CH) - CH = CH_(2) overset("Reagent R")rarr` Alcohol Which is true about alcohol and R ?
Last Answer : `CH_(3) - underset(CH_(3))underset(|)(CH) - CH = CH_(2) overset("Reagent R")rarr` Alcohol Which is true about ... ) - CH_(2)CH_(3)` dil. `H_(2)SO_(4)`
Description : A compound undergoes reduction with LiAlH4. It also dissolves in aqueous NaOH from which it can be recovered by addition of HCl. The compound is (a) a carboxylic acid (b) an ester (c) an acid anhydride (d) an alcohol
Last Answer : a carboxylic acid
Description : Isopropyl alcohol can be converted to acetone by treatment with (a) HCl/ZnCl2 (b) Na2Cr2O7/H2SO4 (c) NaOH (d) LiAlH4
Last Answer : Na2Cr2O7/H2SO4