A cistern can be filled in 25 minutes. There is a leakage which can empty it in 50 minutes. In how many minutes cistern can be filled? a) 20 mints b) 25mints c) 45 mints d) 50 mints

A cistern can be filled in 25 minutes. There is a leakage which can empty it in 50 minutes. In how many minutes cistern can be filled? a) 20 mints b) 25mints c) 45 mints d) 50 mints
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1 Answer

Answer :

D

Efficiency of filling faucet= 100/25 = 4%

⇒ Efficiency of leakage faucet = 100/50= 2%

⇒ Net filling efficiency = (4-2)%

=2%

So, t cistern can be filled in = 100/2

= 50 minutes
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Pump A can fill the empty bunker in 6 hours, but due to a leak in the bottom it is filled in 7.5 hours, if the bunker is full and then Pump A is closed then in how many hours the leak can empty it? a) 30 hours. b) 45 hours. c) 50 hours. d) 35 hours.

Description : Pump A can fill the empty bunker in 6 hours, but due to a leak in the bottom it is filled in 7.5 hours, if the bunker is full and then Pump A is closed then in how many hours the leak can empty it? a) 30 hours. b) 45 hours. c) 50 hours. d) 35 hours.

Last Answer : A Efficiency of A = 16.666% Effective of leak = 13.333%when there is leakage So, efficiency of leakage =( Efficiency of A- Effective of leak) =16.666%-13.333%= 3.333% It means due to leakage a full bunker will be empty in 30 hours.

P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each one of them finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60

Description : P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each ... finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60 

Last Answer : B Time taken by (P + Q) to finish the job = 24days. (P + Q)'s 1 day's job = 1/24 Time taken by (Q +R) to finish the job = 30days. (Q + R)'s 1 day's job = 1/30 Time taken by (R + P) to finish the ... - {(P + Q)'s 1 day's job } = (1/20 -1/24)=1/120 Hence, R alone can finish the job in 120 days.

A officer undertakes to complete a job in 250 days. He employs 300 male for 50 days and they complete 1/2 of the work . He then reduces the number of male to 100, who work for 120 days, after which there are 20 days holidays. How many male must be employed for the remaining period to finish the work? a) 25 b) 50 c) 45 d) 35

Description : A officer undertakes to complete a job in 250 days. He employs 300 male for 50 days and they complete 1/2 of the work . He then reduces the number of male to 100, who work for 120 days, after which there ... male must be employed for the remaining period to finish the work? a) 25 b) 50 c) 45 d) 35

Last Answer : B 300 male in 50 days do = 1/2work 1 male in 1 day does = ½*1/50*1/300 work 100 male in 120 days do = ½ *1/50*1/300 *100*120 =2/5 work Total work done = ½ + 2/5 =(5+4)/10=9/10 ... is done in 50 days by 300 male 1/10 work is done in 60 days by =300*50*1*2/10*60 =50 male

A motor bike tyre has two punctures. The 1st puncture alone would have made the tyre flat in 27 minutes and the 2nd alone would have done it in 18 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat? a) 20 4/3 minutes b) 15 4/7 minutes c) 10 4/5 minutes d) 25 4/3 minutes

Description : A motor bike tyre has two punctures. The 1st puncture alone would have made the tyre flat in 27 minutes and the 2nd alone would have done it in 18 minutes. If air leaks out at a constant rate, how long does it take ... flat? a) 20 4/3 minutes b) 15 4/7 minutes c) 10 4/5 minutes d) 25 4/3 minutes

Last Answer : C 1st puncture made the tyre flat in 27 mins 2nd puncture made the tyre flat in 18 mins 1 minute’s work of both the punctures = (1/27 + 1/18) =(2+3)/54 =5/54 So, both the punctures will make the tyre flat in 54/5 mins =>10 4/5 minutes

Adam and Smith are working on a project. Adam takes 18 hrs to type 108 pages on a computer, while Smith takes 15 hrs to type 120 pages. How much time will they take, working together on two different computers to type a project of 360 pages? a) 23 hrs 24 min b) 45 hrs 42 min c) 25 hrs 42 min d) 42 hrs 45 min

Description : Adam and Smith are working on a project. Adam takes 18 hrs to type 108 pages on a computer, while Smith takes 15 hrs to type 120 pages. How much time will they take, working together on two different computers to type a ... ? a) 23 hrs 24 min b) 45 hrs 42 min c) 25 hrs 42 min d) 42 hrs 45 min

Last Answer : C Number of pages typed by Adam=108 Number of pages typed by Adam in 1 hour = 108/18=6 Number of pages typed by Smith =120 Number of pages typed by Smith in 1 hour = 120/15 =8 Number of pages typed by both in ... (6 + 8) = 14 Time taken by both to type 360 pages, = (360 * 1/14) =25 hrs 42 min

Two faucet can separately fill a cistern 30minutes and 45 minutes respectively and when the waste faucet is open, they can together fill it in 54 minutes. The waste faucet can empty the full cistern in? A) 27 min B) 23 min C) 23 min D) 29 min

Description : Two faucet can separately fill a cistern 30minutes and 45 minutes respectively and when the waste faucet is open, they can together fill it in 54 minutes. The waste faucet can empty the full cistern in? A) 27 min B) 23 min C) 23 min D) 29 min 

Last Answer : A 1/30 + 1/45 - 1/x = 1/54 1/x=1/30+1/45-1/54 1/x=9+6-5/270 1/x=10/270 1/x=1/27 x = 27

Faucet A basically used as inlet pipe and Faucet B is used as outlet pipe. Faucet A and B both are opened simultaneously, all the time. When Faucet A fills the tank and Faucet B empty the tank, it will take thrice the time than when both the pipes fill the tank. When Faucet B is used for filling the tank, its efficiency remains constant. What is the ratio of efficiency of Faucet A and Faucet B respectively? a) 1:2 b) 2:1 c) 1:3 d) 3:1

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Last Answer : B Efficiency when both pipes used to fill = A + B And efficiency when Faucet A is used to fill and Faucet B is used to empty the tank = A-B So (A+B)/(A-B)=3/1 A/B+1/(A/B-1)=3/1 A/B+1=3(A/B-1) 3A/B-A/B=4 2A/B=4 A/B=2 Thus, the ratio of efficiency of Faucet A and B =2:1

Hanisha can do a work in 25 days, while sudha can do the same work in 50 days. They started the work jointly.Few days sughana also joined them and thus all of them completed the whole work in 12 days. All of them were paid total Rs.900. What is the Share of sughana? a) 252 b) 346 c) 454 d).359

Description : Hanisha can do a work in 25 days, while sudha can do the same work in 50 days. They started the work jointly.Few days sughana also joined them and thus all of them completed the whole work in 12 days. All of them were paid total Rs.900. What is the Share of sughana? a) 252 b) 346 c) 454 d).359

Last Answer : A Efficiency of Hanisha = 1/100*25 =25/100=1/4=>4% Efficiency of sudha = 2% Thus, in 12 days working together they will complete only 72% of the work. [(4+2)*12] =72 Hence, the remaining work will ... which is =(100-72)=28% Thus, sughana will get 28% of Rs. 900, =28/100*900 which is Rs.252

6 boys and 5girls can do a job in 8 days. When 7 boys and 10 girls work on the same job, the work gets completed in 5 days. How many days will a boy take to do the job, if he works alone on it? a) A.25 b) B.50 c) C.75 d) D.100

Description : 6 boys and 5girls can do a job in 8 days. When 7 boys and 10 girls work on the same job, the work gets completed in 5 days. How many days will a boy take to do the job, if he works alone on it? a) A.25 b) B.50 c) C.75 d) D.100

Last Answer : D Let the amount of work done by a boy in a day be B′ and the amount of work done by a girl in a day be G′. Therefore, 6 boys and 5 girls will do 6B+5G amount of work in a day. If 6 boys and 5 ... 1/100 i.e. a boy does 1/100th of the work in a day. Hence he will take 100 days to do the work.

8 men and 8 boys can finish a piece of work in 10 days. 9 women and 7 boys can finish the same work in 10 days. Also 7 men and 6 women can finish the same work in 10 days. In how many days 1man, woman and one boy can finish the work, at their double efficiency? a) 25 days b) 20 days c) 15 days d) 10 days

Description : 8 men and 8 boys can finish a piece of work in 10 days. 9 women and 7 boys can finish the same work in 10 days. Also 7 men and 6 women can finish the same work in 10 days. In how many days 1man, ... boy can finish the work, at their double efficiency? a) 25 days b) 20 days c) 15 days d) 10 days

Last Answer : A Efficiency of 8 men and 8 boys = 10% Efficiency of 9 women and 7boys = 10% Efficiency of 7 men and 6 women = 10% So, Efficiency of 15 men, 15women and 15boys = 30% So, efficiency of 1 man ... efficiency Efficiency of 1 man, 1 woman and 1 boy = 4% Required number of days = 100/4=25 days

Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Description : Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Last Answer : D Work done by pranesh in 4 days = 1/60 *4 =1/15 Remaining work = 1-1/15 =(15 - 1)/15 =14/15 Now 14/15 work done by sarvesh in 28 days Whole work will be done by sarvesh in(28*15 /14) = 2* 15 =30 ... 's work = 1/60 + 1/30 = (1+2) /60 = 3/60 =1/20 Hence both will finish the work in 20 days

A tap can fill a cistern in 11hours, but due to a leakage it took 13hours to fill the cistern. If the cistern is full, in what time will the cistern become empty due to leakage ? A) 73.30hrs B) 77.50hrs C) 71.5 hrs D) 72.30hrs E) None of these

Description : A tap can fill a cistern in 11hours, but due to a leakage it took 13hours to fill the cistern. If the cistern is full, in what time will the cistern become empty due to leakage ? A) 73.30hrs B) 77.50hrs C) 71.5 hrs D) 72.30hrs E) None of these

Last Answer : C 1/11-1/13 = 13-11/143 =>2/143 =>1/71.5 =>71.5hours

P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Description : P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Last Answer : B Work done by P,Q & R in 8 days = 1/20 * 8 =2/5 Remaining work = (1 - 2/5) = 3/5 Now 3/5 work is done by Q & R in 20 days Whole work will be done by Q & R in(20*5/3) =100/3 days (P+Q+R ... (Q+R)'s 1 day work =1/20 - 3/100 =5-3/100 =2/100 =1/50 P alone could complete the work in 50 days..

60 girls can do a work in 48 days. 48 boys can finish the same work in 45 days. What is the ratio between the capacity of a boys and girls? a) 2:1 b) 3:6 c) 2:4 d) 4:3

Description : 60 girls can do a work in 48 days. 48 boys can finish the same work in 45 days. What is the ratio between the capacity of a boys and girls? a) 2:1 b) 3:6 c) 2:4 d) 4:3

Last Answer : D  Total number of girls =60 Total number of boys =48 (60*48) girls can complete the work in 1 day 2880 girls can complete the work in 1 day 1 girls 1 day work =1/2880 (48*45) boys can complete the work ... day 1 boys 1 day work =1/2160 So required ratio =1/2160 : 1/2880 =2880 : 2160 =4:3

P and Q finished a work in 36 days; Q and R can do it in 60 days; P and R can do it in 45 days. In what time can P alone do it. a) 30 days b) 60 days c) 90 days d) 120 days

Description : P and Q finished a work in 36 days; Q and R can do it in 60 days; P and R can do it in 45 days. In what time can P alone do it. a) 30 days b) 60 days c) 90 days d) 120 days

Last Answer : B (P+Q)'s 1 day work = 1/36 ---1 (Q+R)'s 1 day work = 1/60 ----2 (P+R)'s 1 day work = 1/45 ----3 Adding 1 & 2 & 3 we get 2(P+Q+R)'s 1 day work = 1/36 + 1/60+ 1/45 =(5+3+4)/180 = 12/ ... +R)'s 1 day work - (Q+R)'s 1 days work = 1/30 - 1/60 = 2-1/60 = 1/60 P alone can do the work in 60 days.

M do a piece of work in 45 days and N can finish it in 40 days. They work together for 5 days and then M leaves. In how many days will N finish the remaining work? a) 30 5/9 b) 29 4/9 c) 31 3/5 d) 29 5/9

Description : M do a piece of work in 45 days and N can finish it in 40 days. They work together for 5 days and then M leaves. In how many days will N finish the remaining work? a) 30 5/9 b) 29 4/9 c) 31 3/5 d) 29 5/9

Last Answer : A Time taken by M to finish the work = 45 days. M's 1 day's work = 1/45 Time taken by N to finish the work = 40 days. N's 1 day's work = 1/40 (M + N)'s 1 day's work = (1/40+1/45) = ... be done by N in (55/72*40) days = 30and 5/9 days. Hence, the remaining work is done by B in 30 and 5/9 days.

A task is done by 46 persons not all of them have the same capacity to task. Every day exactly 2 persons, do the task with no pair of persons working together twice. Even after all possible pairs have worked once, all the persons together works for two more days to finish the task. Find the number of days in which all the persons together will finish the whole task? a) 44 b) 45 c) 46 d) 47

Description : A task is done by 46 persons not all of them have the same capacity to task. Every day exactly 2 persons, do the task with no pair of persons working together twice. Even after all possible pairs have worked ... in which all the persons together will finish the whole task? a) 44 b) 45 c) 46 d) 47

Last Answer : D 46 persons task in pairs, with no same pair of persons working together. Each person will be working with other 45 which means each persons will work for 45 days in pair. Let the time taken by each ... +1/T46)= 1/47 If all the persons work together they will finish the whole task in 47 days.

A large cistern can be filled by 2 pipes P & Q in 120 mins and 80 mins respectively. How many mins will it take to fill the cistern from empty state if Q is used for half the time and P & Q fil it together for the other half? A) 2hrs B) 1hr C) 3hrs D) 4hrs

Description : A large cistern can be filled by 2 pipes P & Q in 120 mins and 80 mins respectively. How many mins will it take to fill the cistern from empty state if Q is used for half the time and P & Q fil it together for the other half? A) 2hrs B) 1hr C) 3hrs D) 4hrs

Last Answer : B Part filled by (P+Q) in 1 min = 1/120 + 1/80 =2+3/240 = 5/240 = 1/48 Suppose the cistern is filled in x mins then, x/2 (1/48 + 1/80) = 1 x/2(5+3/240)=1 8x/480 = 1 x=480/8 x= 60 mins or 1 hr

8 male can finish a work in 6 days.12 female can complete the same work in 9 days. 6 male and 4 female started working and after 4 days 3 more female joined them. How many days will they now take to complete the remaining work? a) 76/41 days b) 25/62days c) 3/31days d) 4/77days

Description : 8 male can finish a work in 6 days.12 female can complete the same work in 9 days. 6 male and 4 female started working and after 4 days 3 more female joined them. How many days will they now take to complete the remaining work? a) 76/41 days b) 25/62days c) 3/31days d) 4/77days

Last Answer : A 1 male's 1 day work = 1/48 1 female's 1 day work = 1/108 Work done in 4 days = 4 (6/48 +4/108) =4(1/8+1/27) =1/2+4/27 =(27+8)/54 =35/54 Remaining work = (1 - 35/54) = 19/ ... (27+14)/216 =41/216 Now 41/216 work is done by them in 1 day Therefore time taken = 216/41 * 19/54 = 76/41 days

P, Q and R together earn Rs.420 per day, while P and R together earn Rs.296 and Q and R together earn Rs.164. The daily earning of R is : a) Rs.50 b) Rs.80 c) Rs.40 d) Rs.60

Description : P, Q and R together earn Rs.420 per day, while P and R together earn Rs.296 and Q and R together earn Rs.164. The daily earning of R is : a) Rs.50 b) Rs.80 c) Rs.40 d) Rs.60

Last Answer : D (P+Q+R)’s earning = Rs. 420 (P+R)’s earning=Rs 296 (Q+R)’s earning=Rs 164 Q’s daily earning = Rs. (420 ⎯296) = Rs.124 P’s daily earning = Rs. (420 ⎯164) = Rs.236 Now (P+Q)’s earning=Rs 360 R’s daily earning = Rs. [420 ⎯360] = Rs.60

Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Description : Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Last Answer : C Praneetha's 10 day's work + Pooja 14 day's work + Priya's 26 days work = 1 (Praneetha's +pooja's) 10 day's work + (pooja + priya)'s 4 day's work +priya's 22 days work = 1 =>10/24 + 4/32 + priya' ... 13/24 =11/24 Priya's 1 day's work = 11/24 * 1/22 =1/48 Priya can finish the work in 48 days.

M & N do a certain work in 40 days and 24 days respectively. M started the work alone and then after 8 days N joined him till the completion of the work. How long did the work last? a) 16days b) 18days c) 20 days d) 22 days

Description : M & N do a certain work in 40 days and 24 days respectively. M started the work alone and then after 8 days N joined him till the completion of the work. How long did the work last? a) 16days b) 18days c) 20 days d) 22 days

Last Answer : C Work done by M in 8 days = 1/40*8 =1/5 Remaining work = 1-1/5 = 4/5 (M+N)’s 1 day work = 1/40 + 1/24 =(3+5)/120 =8/120 =1/15 Now 1/15 work is done by M & N in 1 day. So 4/5 work will be done by X and Y is, =15 / 1 * 4/5 =12 days Hence total time taken = 12+8 = 20 days

4 male and 6 female do a piece of work in 20 days while 6 male and 4 female can do the same work in16 days. In how many days can 4 male and 2 female do the work? a) 3 62/142 b) 2 18/124 c) 4 81/165 d) 1 67/133

Description : 4 male and 6 female do a piece of work in 20 days while 6 male and 4 female can do the same work in16 days. In how many days can 4 male and 2 female do the work? a) 3 62/142 b) 2 18/124 c) 4 81/165 d) 1 67/133

Last Answer : D Let 1 male's 1 day's work = x 1 female's 1 day's work = y Then 4x + 6y = 1/20 ---------->A 80x + 120y = 1 -----------1 6x + 4y = 1/16 ----------B 96x + 64y = ... (1/400) =132/200+1/200 = 133/200 So 4 male and 2 female together can finish the work in 200/133 = 1 67 /133 days

A tube can fill a cistern in 18hrs.After half the cistern is filled, three more similar tubes are opened. What is the total time taken to fill the cistern completely ? A) 9hrs 52min B) 10hrs 15 min C) 9hrs 45 min D) 10hrs 30min

Description : A tube can fill a cistern in 18hrs.After half the cistern is filled, three more similar tubes are opened. What is the total time taken to fill the cistern completely ? A) 9hrs 52min B) 10hrs 15 min C) 9hrs 45 min D) 10hrs 30min

Last Answer : Time taken to fill half of the cistern = 18/2 = 9 hrs After half the cistern is filled , three more similar tubes are opened. We know that one tube can in 18 hrs can fill = V litres(i.e. fully fill a cistern) ... V/2 will be 2 hrs 15 min Total time = 9 hrs + 2 hrs + 15 min = 11 hrs 15 min

3 faucet A,B,C can fill a cistern from empty to full in 45mins, 35mins, and 25 mins respectively. When the cistern is empty all the 3 faucets are opened. A,B,c discharge chemical solutions A,B,C respectively. What is the proportion of solution C in the liquid in the tank after 5 mins? A) 63/143 B) 72/151 c) 67/173 D) 81/167

Description : 3 faucet A,B,C can fill a cistern from empty to full in 45mins, 35mins, and 25 mins respectively. When the cistern is empty all the 3 faucets are opened. A,B,c discharge chemical solutions A,B,C respectively. What is ... the liquid in the tank after 5 mins? A) 63/143 B) 72/151 c) 67/173 D) 81/167

Last Answer : A Part filled by (A+B+C) in 5 mins = 5(1/45 +1/35 + 1/25) = 5 (35+45+63/1575) = 143/315 Part filled by c in 5 mins = 5/25 = 1/5 Required ratio = 1/5 * 315/143 =63/143.

Three pipes, A, B, & C are attached to a tank. A & B can fill it in 20 & 30 minutes respectively while C can empty it in 15 minutes. If A, B & C are kept open successively for 1 minute each, how soon will the tank be filled?

Description : Three pipes, A, B, & C are attached to a tank. A & B can fill it in 20 & 30 minutes respectively while C can empty it in 15 minutes. If A, B & C are kept open successively for 1 minute each, how soon will the tank be filled?

Last Answer : Answer: 167 minutes.

A Bunker has a leak which would empty the completely filled bunker in 20 hours. If the bunker is full of water and a tap is opened which admits 4 litres of water per minutes in the bunker, how many litres does the bunker holds? A) 2400 B) 4500 C) 4800 D) 7200

Description : A Bunker has a leak which would empty the completely filled bunker in 20 hours. If the bunker is full of water and a tap is opened which admits 4 litres of water per minutes in the bunker, how many litres does the bunker holds? A) 2400 B) 4500 C) 4800 D) 7200

Last Answer : C Leak emptied the bunker per hour = 100/20 = 5% of water per hour; Quantity of water emptied per hour = 4*60 = 240; Thus, 5% = 240 liter; Hence, capacity of water, 100% = 240*100/5= 4800 liter.

Madhesh does half work as much as vinith in three eighth of the time. If together they take a day to complete the work, how much time shall vinith take to do it? a) 21 b) 22 c) 23 d) 24

Description : Madhesh does half work as much as vinith in three eighth of the time. If together they take a day to complete the work, how much time shall vinith take to do it? a) 21 b) 22 c) 23 d) 24

Last Answer : A Suppose vinith takes x days to do the work Madhesh takes (2*3/8 x) = 6/8x i.e., 3/4x days to do it (madhesh + vinith’s) 1 day work = 1/9 Therefore 1/x +4/3x = 1/9 (3+4) / 3x = 1/9 7/3x = 1/9 3x = 9*7 X = 63/ 3 =21 Vinith takes 21 days to do the work.

48 boys complete a work in 36 days. After they have worked for 24 days, 24 more boys join them. How many days will they take to complete the remaining work? a) 8 days b) 6 days c) 4 days d) 3 days

Description : 48 boys complete a work in 36 days. After they have worked for 24 days, 24 more boys join them. How many days will they take to complete the remaining work? a) 8 days b) 6 days c) 4 days d) 3 days

Last Answer : A 1 boy’s 1 day’s work = 1/(36*48) =1/1728 48 boy’s 24 day’s work=48*24/1728=2/3 Remaining work = 1-2/3=1/3 72 boy’s 1 day’s work =72/1728=1/24 1/24 work is done by them in 1 day. So, 1/3 work is done by them in 24/3= 8 days

A and B together can complete a work in 24 days. A alone can complete it in 40 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work? a) 24 days b) 15 days c) 21 days d) 19 days

Description : A and B together can complete a work in 24 days. A alone can complete it in 40 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work? a) 24 days b) 15 days c) 21 days d) 19 days

Last Answer : A B’s 1 day’s work = (1/24 -1/40) =(5-3)/120 =2/120=>1/60 Now, (A + B)’s 1 day’s work = (1/40 +1/60) =(3+2)/120 =5/120 So, A and B together will complete the work in 120/5 = 24 days.

Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6

Description : Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6 

Last Answer : D 6 days before the completion of the work Rakchita left the work means in last 6 days only Shreya has worked alone So, in last 6 days worked done by Shreya = 6*1/42=6/42=1/7 So, the rest = 1-1/7 =6/7 So 6/7work was done by Rakchita and Shreya worked together=6/7*70/10 =420/70=6 days

P and Q undertake to do a piece of job for Rs.1200. P alone can do it in 12 days while Q alone can do it in 16 days. With the help of R , they finish it in 6 days. Find the share of P,Q & R. a) 400,600,200 b) 200,400,600 c) 450,400,250 d) 600,450,150

Description :  P and Q undertake to do a piece of job for Rs.1200. P alone can do it in 12 days while Q alone can do it in 16 days. With the help of R , they finish it in 6 days. Find the share of P,Q & R. a) 400,600,200 b) 200,400,600 c) 450,400,250 d) 600,450,150

Last Answer : D R;s 1 day work = 1/6 – (1/12 + 1/16) =1/6 – 1/12 – 1/16 = (8-4-3)/48 = 1/48 P:Q:R = ratio of 1 day work = 1/12:1/16 : 1/48 =4:3:1 P’s share = Rs(1200*4/8) =Rs.600 Q’s share = Rs(1200 * 3/8) =Rs.450 R’s share = Rs(1200 * 1/8) =Rs.150

2 male, 6 female, and 8 girls can do a work in 192 hrs, 4 male and 16 girls can do it in 160 hrs, 4 male and 6 female can do it in 240 hrs.10 male and 24 girls can do it in. a) A.87 3/ 11 hrs b) B.78 4 /11 hrs c) C.88 6 /12 hrs d) 80 4 /5 hrs

Description : 2 male, 6 female, and 8 girls can do a work in 192 hrs, 4 male and 16 girls can do it in 160 hrs, 4 male and 6 female can do it in 240 hrs.10 male and 24 girls can do it in. a) A.87 3/ 11 hrs b) B.78 4 /11 hrs c) C.88 6 /12 hrs d) 80 4 /5 hrs

Last Answer : A Let 1 males 1 hr work = x 1 female 1 hour work = y 1 girl 1 hour work = z Then 2x + 6y + 8z = 1/192 ------>1 4x + 16z = 1/160 --------->2 4x + 6y = 1/240 ------------->3 Adding 2 and ... 1/192 + 1/160 =(5+6) / 960 = 11/960 10 male and 24 girls can do work in 960/11 hrs i.e., 87 3 /11 hrs

If 24 women and 32 girls can do a piece of work in 5 days; 26 women and 48 girls can do it in 4 days then the ratio of the daily work done by a women to that of a girl is. a) 2:1 b) 1:3 c) 3:1 d) 1:2

Description : If 24 women and 32 girls can do a piece of work in 5 days; 26 women and 48 girls can do it in 4 days then the ratio of the daily work done by a women to that of a girl is. a) 2:1 b) 1:3 c) 3:1 d) 1:2

Last Answer : A Let 1 women's 1 day work = x 1 girl's 1 day work = y Then 24x+32y = 1/5 =>6x+8y = 1/20 ------->1 26x + 48y = 1 / 4 => 13x + 24y = 1/8 -------->2 Multiply 1 by 3 18x + 24y = 3/20 13x + ... 200 = (10 - 6)/ 200 = 4/200 8y = 1/50 Y=1/400 Required ratio = x:y = 1/200: 1/400 =400:200 =2:1

A sum of amount of money is adequate to pay peter’s salary for 42 days and Harish’s salary for 56 days. The same money is adequate to pay the salary of both for. a) 12 days b) 24 days c) 36 days d) 48 days

Description : A sum of amount of money is adequate to pay peter’s salary for 42 days and Harish’s salary for 56 days. The same money is adequate to pay the salary of both for. a) 12 days b) 24 days c) 36 days d) 48 days

Last Answer : B Let the total money be Rs.x Peter’s 1 day salary = Rs. x/42 Harish 1 day salary = Rs. x/56 (peter+harish)’s 1 day salary = Rs(x/42+x/56) =(4x+3x)/168 =7x/168 =x/24 Money is adequate to pay the salary of both for 24 days.

6 male , 8 female and 12 children can complete a work in 14 days .a female does twice the work of a male does and a child does half the work a male does . how many female alone can complete this work in 14 days? a) 15 b) 10 c) 12 d) 14

Description :  6 male , 8 female and 12 children can complete a work in 14 days .a female does twice the work of a male does and a child does half the work a male does . how many female alone can complete this work in 14 days? a) 15 b) 10 c) 12 d) 14

Last Answer :  D Let 1 female ‘s 1 day work= x Then 1 male’s 1 day work =x/2 And 1 child’s 1 day work =x/4 So 6x/2 + 8x +12x/4 =1/14 3x+8x+3x = 1/14 14x = 1/14 X=196 1 female alone can complete the work in 196 days So, to complete the work in 14 days number of female required = 14.

Arul can do a certain work in 9 days while Ravi can do the same work in 7 days. Both of them complete the work together and get Rs.288. what is the share of Arul? a) Rs.124 b) RS.126 c) Rs.128 d) Rs.130

Description : Arul can do a certain work in 9 days while Ravi can do the same work in 7 days. Both of them complete the work together and get Rs.288. what is the share of Arul? a) Rs.124 b) RS.126 c) Rs.128 d) Rs.130

Last Answer : B Arul’s 1 day work = 1/9 Ravi’s 1 day work = 1/7 Arul’s salary : Ravi’s salary = Arul’s 1 day work : Ravi’s 1 day work = 1/9 : 1/7 = 7 :9 Arul’s share = Rs.(7/16 *288) =Rs.126

A bakery P can sold 500 breads in 4 hours, bakery Q can sold the same number of bread in 5 hrs while bakery R can sold them in 6 hrs. All the bakeries are opened at 8 a.m while bakery P is closed at 9 p.m and the remaining 2 bakeries complete their target. Approximately at what time will the work be finished? a) 10 b) 8 c) 12 d) 6

Description : A bakery P can sold 500 breads in 4 hours, bakery Q can sold the same number of bread in 5 hrs while bakery R can sold them in 6 hrs. All the bakeries are opened at 8 a.m while bakery P is closed ... complete their target. Approximately at what time will the work be finished? a) 10 b) 8 c) 12 d) 6

Last Answer : A (P+Q+R)'s 1 hour work = (1/4 +1/5+ 1/6) =(15+12+10)/60 =37/60 Remaining work = 1- 37/60 = 23/60 (Q+R)'s 1 hour work = (1/5 +1/6) =11/30 Now 11/30 work is done by Q and R ... R in(30/11*23/60) =23/22 hrs = 1hr So the work will be finished approximately 1 hr after 9.am i.e., around 10 a.m

Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Description : Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Last Answer : A Let sai's 1 day work = x Ram's 1 day work = y Then x+y = 1/10 ===>1 and 2x +2y /3 = 1/6 (6x+2y )/3 = 1/6 6x + 2y =1/2 ====>2 Multiply 1 by 6 =>6x+6y = 6/10 2 = ... /10 - 1/40 = 4-1/10 =3/40 Sai's 1 day work = 3/40 So sai alone could complete the work in 40/3 days.

Vinay can do a work in 28 days. Vikram is 75% more efficient than vinay. The number of days taken by vikram to do the same piece of work. a) 12 days b) 14 days c) 16 days d) 18 days

Description : Vinay can do a work in 28 days. Vikram is 75% more efficient than vinay. The number of days taken by vikram to do the same piece of work.  a) 12 days b) 14 days c) 16 days d) 18 days

Last Answer : C Given a certain work done by vinay = 28 days Efficient percentage of vikram = 75% Ratio of time taken by vinay and vikram = 175 : 100 = 7:4 Suppose vikram takes ‘x’ days to do the work. 7:4 :: 28 : x 7x = 4*28 X= 4*28/7 X= 4*4 = 16 days So vikram takes 16 days to do the work.

M & N can do a work together in 12 days. M is 2 ½ time as efficient as N. the same work can be done by M alone in. a) 84/5 b) 6/84 c) 82/5 d) 6/82

Description : M & N can do a work together in 12 days. M is 2 ½ time as efficient as N. the same work can be done by M alone in. a) 84/5 b) 6/84 c) 82/5 d) 6/82

Last Answer : A M’s 1 day work = 2 ½ = 5/2 N’s 1 day work = 1 Ratio of M and N = 5/2 : 1= 5:2 Let M’s and N’s 1 day work be 5x and 2x respectively. Then 5x+2x = 1/12 7x=1/12 X= 1/(12*7) X=1/84 M’s 1 day work = 1/84 * 5 = 5/84 Hence M alone can finish the work in 84/5 days.

Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Description : Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Last Answer : C Karthik’s 1 day work : Raghu’s 1 day work = 2:1 (Karthik + Raghu)’s 1 day work = 1/42 Divide 1/42 in the ratio 2:1 Therefore karthick’s 1 day work = 1/42 * 2/3 =1/63 Hence karthik alone can finish the work in 63 days.

X and Y can do a job in 24 days, Y & Z can do the same job in 36 days. X,Y,Z together can finish it in 18 days. X and Z together will do it in. a) 24 b) 36 c) 12 d) 26

Description : X and Y can do a job in 24 days, Y & Z can do the same job in 36 days. X,Y,Z together can finish it in 18 days. X and Z together will do it in. a) 24 b) 36 c) 12 d) 26

Last Answer : A (X+Y+Z) s 1 day work =1/18 (X+Y)'s 1 day work = 1/24 (Y+Z)'s 1 day work = 1/36 (X+Z)'s 1 day work = 2[X+Y+Z]'s 1 day work - [(X+Y)'s 1 day work + (Y+Z)'s 1 day work]= 2 [1/18]- (1/24 + ... /24 + 1/36) = 1/9 -1/24 - 1/36 =(8-3-2)/72 =3/72 = 1/24 So X & Z together will do the work in 24 days

X,Y and Z can do a certain job in 72,108 and 144 days respectively. They started the job but X left 16 days before the completion of the job while Y left 24 days before the completion. The number of days for which Z worked is. a) 12 days b) 24 days c) 36 days d) 48 days

Description : X,Y and Z can do a certain job in 72,108 and 144 days respectively. They started the job but X left 16 days before the completion of the job while Y left 24 days before the completion. The number of days for which Z worked is. a) 12 days b) 24 days c) 36 days d) 48 days

Last Answer : D Suppose the work was finished in a' days Then X's (a - 16) day's work + Y's (a - 24) days + Z's a days work = 1 (a-16)/72 + (a-24)/108 + a/144 =1 lcm of 72,108,144 is 432 (6(a-16) + 4( ... = 432 6a - 96 +4a - 96 =3a = 432 13a - 192 = 432 13a = 624 => a =48 Therefore Z worked in 48 days.

Nandhu, naren and abishek can do a piece of work in 10,15, and 30 days respectively. In how many days can Nandhu do the work if he is assisted by naren and abishek on alternate days? a) 6.6 days b) 7.5 days c) 8.4 days d) 9.1 days

Description : Nandhu, naren and abishek can do a piece of work in 10,15, and 30 days respectively. In how many days can Nandhu do the work if he is assisted by naren and abishek on alternate days? a) 6.6 days b) 7.5 days c) 8.4 days d) 9.1 days 

Last Answer : B Nandhu's 1 day work = 1/10 Naren's 1 day work = 1/15 Abishek's 1 day work =1/30 Nandhu's 2 day's work =(1/10*2) =1/5 (nandhu + naren+abishek)'s 1 day work = 1/10+1/15+1/30 =3+2+1/30 =6/30 ... +1/5 = 2/5 Now 2/5 work is done in 3 days Whole work will be done in 3 *5/2 = 15/2 = 7.5 days

Rishwi can finish a work in 6 days working 4 hours a day. Dhiviksha can complete the same work in 4 days working 5 hrs a day. If both rishwi and dhiviksha work together, working 4 hrs a day, in how many days can they finished the work? a) 30/11 b) 11/120 c) 11/30 d) 30/13

Description : Rishwi can finish a work in 6 days working 4 hours a day. Dhiviksha can complete the same work in 4 days working 5 hrs a day. If both rishwi and dhiviksha work together, working 4 hrs a day, in how many days can they finished the work? a) 30/11 b) 11/120 c) 11/30 d) 30/13

Last Answer : A Rishwi can complete the work in (6*4) = 24 hrs Dhiviksha can complete the work in (4*5) = 20 hrs Rishwi's 1 hr work = 1/24 Dhiviksh's 1 hr work = 1/20(Rishwi and dhivikasha)'s 1 hr work = (1/24 ... fininsh the work in (120/11)hrs Number of days of 4 hrs each = 120/11*1/4 =120/44 =30/11 days

90 persons can complete a job in 32 days. 12 days after they started working, 60 more persons joined them. How many days will they now take to complete the remaining work? a) 10 days b) 12 days c) 14 days d) 16 days

Description : 90 persons can complete a job in 32 days. 12 days after they started working, 60 more persons joined them. How many days will they now take to complete the remaining work? a) 10 days b) 12 days c) 14 days d) 16 days

Last Answer : B (90 * 32) persons can complete the work in 1 day. 1 person 1 day's work = 1/(90 *32) i.e., 1/2880 90 person's 12 day's work = 1/32 * 12 = 3/8 Remaining work =(1- 3/8) = 5/8 150 persons 1 ... 5/96 work is done by them in 1 day . Therefore 5/8 work is done by them, = (96/5*5/8) =12 days.

Arfath is thrice as good workman as deekshith and together they finish a piece of work in 27 days. In how many days will arfath alone finish the work? a) 9 days b) 10 days c) 11 days d)12 days

Description :  Arfath is thrice as good workman as deekshith and together they finish a piece of work in 27 days. In how many days will arfath alone finish the work? a) 9 days b) 10 days c) 11 days d)12 days

Last Answer : A Arfath’s 1 days work = 3 Deekshith 1 day’s work = 1 Arfath 1 day’s work : Deekshith 1 days work = 3:1 (Arfath + deekshith )’s 1 day’s work = 1/27 Divide 1/27 in the ratio 3:1 Arfath’s 1 days work = 1/27 *3/1 = 3/27 =1/9 Hence Arfath’s alone can finish the work in 9 days

After finishing the work by Aswin for 9 days, Ajay finds that only 1/4 of the work has been done. He employs Ajay who is 80% as efficient as Aswin. How many days more would Ajay take to complete the work? a) 32 b) 28 c) 34 d) 26

Description : After finishing the work by Aswin for 9 days, Ajay finds that only 1/4 of the work has been done. He employs Ajay who is 80% as efficient as Aswin. How many days more would Ajay take to complete the work? a) 32 b) 28 c) 34 d) 26

Last Answer : C Aswin has completed 1/4 of the work in 9 days Then he can complete the total work in 1/4 ---- 9 1 ---- ? = 36 days But given Ajay is only 80% as efficient as Aswin Ajay = 1/36*80/100=1/45 Ajay can ... work can be completed in 1 ------ 45 3/4 ------ ? =3/4*45 =33.75=34 days (approx.)

X does half as much work as Yand Z does half as much work as X and Y together. If Z alone can finish the work in 120 days, then together ,all will finish the work in ? a) 14 1/2 b) 40 c) 24 1/2 d)17 1/3

Description : X does half as much work as Yand Z does half as much work as X and Y together. If Z alone can finish the work in 120 days, then together ,all will finish the work in ? a) 14 1/2 b) 40 c) 24 1/2 d)17 1/3

Last Answer : B Z alone can finish the work in 120 days. As given Z does half as much work as X and Y together => (X + Y) can do it in 60 days (X+ Y)s 1 days wok = 1/60. X's 1 days work : Y's 1 days Work = 1 ... (1/90) + (1/120) =(2+4+3)/360 =9/360 = 1/40 All the three together will finish it in 40 days