The sum of products expansion for the function F(x, y, z) = (x + y)z’ is given as (A) x’y’z + xyz’ + x’yz’ (B) xyz + xyz’ + xy’z’ (C) xy’z’ + x’y’z’ + xyz’ (D) xyz’ + xy’z’ + x’yz’

1 Answer

Answer :

(D) xyz’ + xy’z’ + x’yz’

Explanation:

Use Boolean identities to expand the product and simplify.

F(x, y, z)=(x + y)z’

 =xz’+yz’ Distributive law

 =x1z’+1yz’ Identity law

 =x(y+y’)z’+(x+x’)yz’ Unit property

=xyz’+xy’z’+xyz’+x’yz’ Distributive law

 =xyz’+xy’z’+x’yz’ Idempotent law 

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