A client-server system uses a satellite network, with the satellite at a height of 40,000 kms. What is the best-case delay in response to a request? (Note that the speed of light in air is 3,00,000 km/second). (A) 133.33 m sec (B) 266.67 m sec (C) 400.00 m sec (D) 533.33 m sec

A client-server system uses a satellite network, with the satellite at a height of 40,000 kms. What is the best-case delay in response to a request? (Note that the speed of light in air is 3,00,000 km/second). (A) 133.33 m sec (B) 266.67 m sec (C) 400.00 m sec (D) 533.33 m sec
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1 Answer

Answer :

(D) 533.33 m sec

Explanation: The request has to go up and down, and the response has to go up and down. The total path length traversed is thus 160.000 km. The speed of light in air and vacuum is 300,000 km/sec, so the propagation delay alone is 160,000/300,000 sec or about 533 msec. 
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Description : Match the following HTTP status code to their respective definitions. i) 400 a) OK ii) 500 b) Not found iii) 200 c) Continue iv) 100 d) Internal server error A) i-b, ii-d, iii-a, iv-c B) i-a, ii-b, iii-c, iv-d C) i-b, ii-c, iii-a, iv-d D) i-b, ii-a, iii-c, iv-d

Last Answer : A) i-b, ii-d, iii-a, iv-c

A vertical column of water will be supported to what height by standard atmospheric pressure.  a. 33.9 ft  b. 45 ft  c. 67 ft  d. 25.46 ft ho= Po/Yo

Description : A vertical column of water will be supported to what height by standard atmospheric pressure.  a. 33.9 ft  b. 45 ft  c. 67 ft  d. 25.46 ft ho= Po/Yo

Last Answer : 33.9 ft

1/2of a certain travel is covered at the rate of 30km/hr, one-third at the rate of 40 km/hr and the rest at 35km/hr. Find the average speed for the whole travel. A) 33 1/3 B) 33 3/5 C) 34 3/7 D) None of these

Description : 1/2of a certain travel is covered at the rate of 30km/hr, one-third at the rate of 40 km/hr and the rest at 35km/hr. Find the average speed for the whole travel. A) 33 1/3 B) 33 3/5 C) 34 3/7 D) None of these

Last Answer : B) let the total travel be X km.  Then X/2 km at the speed of 30 km/hr and X/3 km at 40 km/hr and the rest distance( X - X/2 - X/3) =1/6 X at the speed of 35km/hr. Total time taken during the travel ... 2*30 hrs+ X/3*40hrs+ X/6*35hrs = 5X/168 hrs Average speed =X/(5x/168) = 168/5 =33 3/5km hr

A client of yours would like to expand with a small bistro in front of her catering kitchen. What do you tell her is one advantage to a peer-to-peer network over a client-server network in her case?

Description : A client of yours would like to expand with a small bistro in front of her catering kitchen. What do you tell her is one advantage to a peer-to-peer network over a client-server network in her case?

Last Answer : Peer-to-peer networking is less expensive and easier to upkeep.

Suppose list1 is [2445, 133, 12454, 123], what is max(list1) ? a) 2445 b) 133 c) 12454 d) 123

Description : Suppose list1 is [2445, 133, 12454, 123], what is max(list1) ? a) 2445 b) 133 c) 12454 d) 123

Last Answer : c) 12454