Which one of the following is a correct implementation of the metapredicate “not” in PROLOG (Here G represents a goal) ? (A) not(G):– !, call(G), fail. not(G). (B) not(G):– call(G), !, fail. not(G). (C) not(G):– call(G), fail, !. not(G). (D) not(G):– call(G), fail. not(G):– !.

Which one of the following is a correct implementation of the metapredicate

“not” in PROLOG (Here G represents a goal) ?

(A) not(G):– !, call(G), fail.

not(G).

(B) not(G):– call(G), !, fail.

not(G).

(C) not(G):– call(G), fail, !.

not(G).

(D) not(G):– call(G), fail.

not(G):– !.


by

1 Answer

Answer :

(B) not(G):– call(G), !, fail.

not(G).
by

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