What gauge aluminum is .030?

What gauge aluminum is .030?
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In a 200-ml sample of 0.030 M Na3P04 what is the concentration of Na plus?

Description : In a 200-ml sample of 0.030 M Na3P04 what is the concentration of Na plus?

Last Answer : 200 mL sample of 0,030 M Na3P04 contain 0,414 g sodium; the concentration of Na is 2,07 g/L.

What is .030 thickness?

Description : What is .030 thickness?

Last Answer : Feel Free to Answer

Is 0.300 greater than 0.030?

Description : Is 0.300 greater than 0.030?

Last Answer : 0.300 is greater than 0.030

The specific gravity of urine normally ranges from (A) 0.900–0.999 (B) 1.003–1.030 (C) 1.000–1.001 (D) 1.101–1.120

Description : The specific gravity of urine normally ranges from (A) 0.900–0.999 (B) 1.003–1.030 (C) 1.000–1.001 (D) 1.101–1.120

Last Answer : B

What is the purpose of either 'setpoint module' (6000F090/030) shown in the illustration? EL-0094 A. Program the 'signal conditioner' as to how to vary its input. B. Supply 0 - 10 volts to the 'signal conditioner'. C. Initiate logging of measured information at set intervals; for example, each hour. D. Obtain an input from the 'signal conditioner' and, if outside set limits, signals the 'annunciator'.

Description : What is the purpose of either 'setpoint module' (6000F090/030) shown in the illustration? EL-0094 A. Program the 'signal conditioner' as to how to vary its input. B. Supply 0 - 10 volts to ... . Obtain an input from the 'signal conditioner' and, if outside set limits, signals the 'annunciator'.

Last Answer : Answer: D

Assume a frequency range of 405.0125 MHz to 405.0875 MHz and 25 kHz channeling plan, determine the center frequency of the second channel from the lower limit. A. 405.030 MHz B. 405.025 MHz C. 405.050 MHz D. 405.075 MHz

Description : Assume a frequency range of 405.0125 MHz to 405.0875 MHz and 25 kHz channeling plan, determine the center frequency of the second channel from the lower limit. A. 405.030 MHz B. 405.025 MHz C. 405.050 MHz D. 405.075 MHz

Last Answer : C. 405.050 MHz

The back staff reading on a B.M. of R.L. 500.000 m is 2.685 m. If foresight reading on a point is 1.345 m, the reduced level of the point, is (A) 502.685 m (B) 501.345 m (C) 501.340 m (D) 504.030 m

Description : The back staff reading on a B.M. of R.L. 500.000 m is 2.685 m. If foresight reading on a point is 1.345 m, the reduced level of the point, is (A) 502.685 m (B) 501.345 m (C) 501.340 m (D) 504.030 m

Last Answer : (C) 501.340 m

A level when set up 25 m from peg A and 50 m from peg B reads 2.847 on a staff held on A and 3.462 on a staff held on B, keeping bubble at its centre while reading. If the reduced levels of A and B are 283.665 m and 284.295 m respectively, the collimation error per 100 m is (A) 0.015 m (B) 0.030 m (C) 0.045 m (D) 0.060 m

Description : A level when set up 25 m from peg A and 50 m from peg B reads 2.847 on a staff held on A and 3.462 on a staff held on B, keeping bubble at its centre while reading. If the reduced levels of A and B are 283.665 m ... collimation error per 100 m is (A) 0.015 m (B) 0.030 m (C) 0.045 m (D) 0.060 m

Last Answer : (D) 0.060 m

A dumpy level is set up with its eye-piece vertically over a peg . The height from the top of peg to the centre of the eye-piece is 1.540 m and the reading on peg is 0.705 m. The level is then setup over . The height of the eye-piece above peg is 1.490 m and a reading on is 2.195 m. The difference in level between and is (A) 2.900 m (B) 3.030 m (C) 0.770 m (D) 0.785 m

Description : A dumpy level is set up with its eye-piece vertically over a peg . The height from the top of peg to the centre of the eye-piece is 1.540 m and the reading on peg is 0.705 m. The level is then setup over . The height ... in level between and is (A) 2.900 m (B) 3.030 m (C) 0.770 m (D) 0.785 m

Last Answer : (C) 0.770 m

Refer to CAP697 MRJT1 Fig. 4.3.1 Given: Estimated zero fuel mass 50t; estimated landing mass at destination 52t; final reserve fuel 2t; alternate fuel 1t; flight to destination distance 720nm, true course 030, W/V 340/30; cruise: LRC, at FL330 outside air temperature -30C. Find estimated trip fuel and time. a. 4,800kg / 01hr 45min b. 4,400kg / 02hr 02min c. 4,750kg / 02hr 00min d. 4,600kg / 02hr 05min

Description : Refer to CAP697 MRJT1 Fig. 4.3.1 Given: Estimated zero fuel mass 50t; estimated landing mass at destination 52t; final reserve fuel 2t; alternate fuel 1t; flight to destination distance 720nm, true course 030, W/V ... b. 4,400kg / 02hr 02min c. 4,750kg / 02hr 00min d. 4,600kg / 02hr 05min

Last Answer : a. 4,800kg / 01hr 45min