What are the points of intersection between the line 3x -y equals 5 and the curve 2x squared plus y squared equals 129?

What are the points of intersection between the line 3x -y equals 5 and the curve 2x squared plus y squared equals 129?
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If: 3x-y = 5 then y^2 = (3x_5)^2 => 9x^2 -30x+25If: 2x^2 + y^2 = 129 then y^2 = 129-2x^2So: 9x^2 -30x+25 = 129-2x^2Transposing terms: 11x^2 -30x -104 = 0Factorizing the above: (11x-52)(x+2) = 0 meaning x = 52/11 or x= -2By substituting x into the original equation intersections areat: (52/11, 101/11) and (-2, -11)
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