Find the equation of the line which passes through the point of intersection of the lines 2x – y + 5 = 0 -Maths 9th

Find the equation of the line which passes through the point of intersection of the lines 2x – y + 5 = 0 -Maths 9th
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(a) 45º 3x + y – 7 = 0 ⇒ y = –3x + 7 ⇒ Slope (m1) = –3 x + 2y + 9 = 0 ⇒ y = \(rac{-x}{2}\) - \(rac{9}{2}\) ⇒ Slope (m2) = \(-rac{1}{2}\)If θ is the angle between the given lines, then tan θ = \(\big|rac{m_1-m_2}{1+m_1m_2}\big|\) = \(\bigg|rac{-3-\big(rac{1}{2}\big)}{1+(-3)\big(-rac{1}{2}\big)}\bigg|\) = \(\bigg|rac{-rac{5}{2}}{1+rac{3}{2}}\bigg|\)= \(\bigg|rac{-rac{5}{2}}{rac{5}{2}}\bigg|\) = 1∴ θ = 45°.
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