What is 0.20 x 0.023?

What is 0.20 x 0.023?
by

1 Answer

Answer :

0.2 x 0.023 = 0.0046
by
selected by

Related questions

The weight of 6.023 x 1022 atoms of carbon is – (1) 12 gms (2) 120 gms (3) 1.2 gms (4) 0.12 gms

Description : The weight of 6.023 x 1022 atoms of carbon is – (1) 12 gms (2) 120 gms (3) 1.2 gms (4) 0.12 gms

Last Answer : (1) 12 gms Explanation: The number is known as Avogadro 's Number which is the number of atoms in 12g of the isotope carbon-12. carbon atoms weigh = 12 grams.

How would you find the product in .023 x .04?

Description : How would you find the product in .023 x .04?

Last Answer : It is 0.00092

What is 700 x .023?

Description : What is 700 x .023?

Last Answer : The product is 16.1

The value of Avogadro Number is - (1) 6.023 x 1022 (2) 6.023 x 1023 (3) 6.023 x 1024 (4) 6.023 x 1025

Description : The value of Avogadro Number is - (1) 6.023 x 1022 (2) 6.023 x 1023 (3) 6.023 x 1024 (4) 6.023 x 1025

Last Answer : (2) 6.023 x 1023 Explanation: In chemistry and physics, the Avogadro constant is defined as the number of constituent particles (usually atoms or molecules) in one mole of a given substance. It has dimensions of reciprocal mol and its value is equal to.

The total number of protons in 10 g of calcium carbonate is `(N_(0) = 6.023 xx 10^(23))` :-

Description : The total number of protons in 10 g of calcium carbonate is `(N_(0) = 6.023 xx 10^(23))` :-

Last Answer : The total number of protons in 10 g of calcium carbonate is `(N_(0) = 6.023 xx 10^(23))` :- A. `1.5057 ... 3.0115 xx 10^(24)` D. `4.0956 xx 10^(24)`

Heat transfer co-efficient (h) for a fluid flowing inside a clean pipe is given by h = 0.023 (K/D) (DVρ/µ) 0.8 (CP .µ/k) 0.4 . This is valid for the value of NRe equal to (A) < 2100 (B) 2100-4000 (C) > 4000 (D) > 10000

Description : Heat transfer co-efficient (h) for a fluid flowing inside a clean pipe is given by h = 0.023 (K/D) (DVρ/µ) 0.8 (CP .µ/k) 0.4 . This is valid for the value of NRe equal to (A) < 2100 (B) 2100-4000 (C) > 4000 (D) > 10000

Last Answer : (D) > 10000

The Dittus-Boelter equation for convective heat transfer [(i.e. h = 0.023 (K/D) (Re) 0.8 (Pr) 0.4 ] cannot be used for (A) Low Reynold's number (B) Very low Grashoff number (C) Molten metals (D) All (A), (B) and (C)

Description : The Dittus-Boelter equation for convective heat transfer [(i.e. h = 0.023 (K/D) (Re) 0.8 (Pr) 0.4 ] cannot be used for (A) Low Reynold's number (B) Very low Grashoff number (C) Molten metals (D) All (A), (B) and (C)

Last Answer : (D) All (A), (B) and (C)

Heat transfer co-efficient equation for forced convection, Nu = 0.023 Re 0.8 . Pr n , is not valid, if the value of (A) n = 0.4 is used for heating (B) n = 0.3 is used for cooling (C) Reynolds number for the flow involved is > 10000 (D) Reynolds number for the flow involved is < 2100

Description : Heat transfer co-efficient equation for forced convection, Nu = 0.023 Re 0.8 . Pr n , is not valid, if the value of (A) n = 0.4 is used for heating (B) n = 0.3 is used for cooling (C) Reynolds number for the flow involved is > 10000 (D) Reynolds number for the flow involved is < 2100

Last Answer : (D) Reynolds number for the flow involved is < 2100

The weight of 6.023 × 1022 atoms of carbon is (1) 12 gms (2) 120 gms (3) 1.2 gms (4) 0.12 gms

Description : The weight of 6.023 × 1022 atoms of carbon is (1) 12 gms (2) 120 gms (3) 1.2 gms (4) 0.12 gms

Last Answer :  12 gms

The weight of 6.023 × 1022 atoms of carbon is –

Description : The weight of 6.023 × 1022 atoms of carbon is –

Last Answer : 1-2gram