What is the tangent line equation of the circle 2x2 plus 2y2 -8x -5y -1 equals 0 at the point 1 -1 on its circumference?

What is the tangent line equation of the circle 2x2 plus 2y2 -8x -5y -1 equals 0 at the point 1 -1 on its circumference?
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Circle equation: 2x^2 +2y^2 -8x -5y -1 = 0Divide all terms by 2: x^2 +y^2 -4x -2.5y -0.5 = 0Completing the squares: (x-2)^2 +(y-1.25)^2 = 6.0625Center of circle: (2, 1.25)Point of contact: (1, -1)Slope of radius: 9/4Slope of tangent line: -4/9Tangent equation: y--1 = -4/9(x-1) => 9y = -4x -5Tangent line equation in its general form: 4x+9y+5 = 0
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