What is the vertex of the graph of the function below y x2 - 8x plus 12?

What is the vertex of the graph of the function below y x2 - 8x plus 12?
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Description : Which two points satisfy y -x2 plus 2x plus 4 and x plus y 4?

Last Answer : Without any equality signs the given expression can't form anyequations and so therefore determining the values of x and y is notpossible.

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Description : If z equals yf x2 - y2 show that ydz divided by dx plus xdz divided by dy equals xz divided by y?

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Description : If the perimeter of a square is 8x plus 6 what is its area?

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Description : What is the tangent line equation of the circle 2x2 plus 2y2 -8x -5y -1 equals 0 at the point 1 -1 on its circumference?

Last Answer : Circle equation: 2x^2 +2y^2 -8x -5y -1 = 0Divide all terms by 2: x^2 +y^2 -4x -2.5y -0.5 = 0Completing the squares: (x-2)^2 +(y-1.25)^2 = 6.0625Center of circle: (2, 1.25)Point of contact: (1 ... 9Tangent equation: y--1 = -4/9(x-1) => 9y = -4x -5Tangent line equation in its general form: 4x+9y+5 = 0

How do you factorise 8x plus 6?

Description : How do you factorise 8x plus 6?

Last Answer : j

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Description : How do you factorise 8x plus 12m?

Last Answer : It is: 4(2x+3m) when factorised

What is (3x plus 5) plus (-8x-10)?

Description : What is (3x plus 5) plus (-8x-10)?

Last Answer : It is equivalent to: 3x+6+5 = 3x+11

How do you factorise 8x plus 6?

Description : How do you factorise 8x plus 6?

Last Answer : j

How do you factorise 8x plus 12m?

Description : How do you factorise 8x plus 12m?

Last Answer : It is: 4(2x+3m) when factorised

What is (3x plus 5) plus (-8x-10)?

Description : What is (3x plus 5) plus (-8x-10)?

Last Answer : It is equivalent to: 3x+6+5 = 3x+11

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Description : How do you re-write x squared plus 5x - 3 in vertex form?

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What is the length of a tangent line from the point 7 -2 to a point when it touches the circle x2 plus y2 -10 equals 49?

Description : What is the length of a tangent line from the point 7 -2 to a point when it touches the circle x2 plus y2 -10 equals 49?

Last Answer : x² + y² - 10 = 49→ x² + y² = 59= (x - 0)² + (y - 0)² = (√59)²→ circle has centre (0, 0) - the origin - and radius √59The point (7, -2) has a distance from the centre of the circleof:√((7 - 0)² + (-2 - 0)²) = √(7² + (-2)²) = √(49 + 4) = √53

What is the length of the circle radius if the circle is x2 plus y2 equals 1?

Description : What is the length of the circle radius if the circle is x2 plus y2 equals 1?

Last Answer : The center of the circle is at (0, 0) and its radius is thesquare root of 1 which is 1

What is the length of the circles radius for the circle x2 plus y2 169.?

Description : What is the length of the circles radius for the circle x2 plus y2 169.?

Last Answer : If x^2 plus y^2 = 169 then the center of the circle is at (0, 0)and its radius is the square root of 169 which is 13

What is the distance from a point on the x axis to the centre of a circle when a tangent line at the point 3 4 meets the circle of x2 plus y2 -2x -6y plus 5 equals 0?

Description : What is the distance from a point on the x axis to the centre of a circle when a tangent line at the point 3 4 meets the circle of x2 plus y2 -2x -6y plus 5 equals 0?

Last Answer : Circle equation: x^2 +y^2 -2x -6y +5 = 0Completing the squares: (x-1)^2 +(y-3)^2 = 5Centre of circle: (1, 3)Tangent line meets the x-axis at: (0, 5)Distance from (0, 5) to (1, 3) = 5 units using the distanceformula

If the equation x2 minus ax plus 2b equals 0 has prime roots where a and b are positive integers then a minus b is equal to?

Description : If the equation x2 minus ax plus 2b equals 0 has prime roots where a and b are positive integers then a minus b is equal to?

Last Answer : I think you mean the roots are prime numbers.Let the two roots be primes p and qThen the equation factorises to (x - p)(x - q) = 0 which can beexpanded to give:x² - (p + q)x + pq = 0Which comparing ... = 2(It doesn't matter if the other prime is even (2) or not as itcancels out from a - b.)

What is the equation of the tangent line that meets the circle x2 -4x plus y2 -6y equals 4 at the point 6 4?

Description : What is the equation of the tangent line that meets the circle x2 -4x plus y2 -6y equals 4 at the point 6 4?

Last Answer : Circle equation: x^2 -4x +y^2 -6y = 4Completing the squares: (x-2)^2 +(y-3)^2 = 17Point of contact: (6, 4)Center of circle: (2, 3)Slope of radius: 1/4Slope of tangent line: -4Tangent equation: y-4 = -4(x-6) => y = -4x+28Tangent line equation in its general form: 4x+y-28 = 0

What is the length of the tangent line from the point 8 2 to a point where it meets the circle x2 plus y2 -4x -8y -5 equals 0?

Description : What is the length of the tangent line from the point 8 2 to a point where it meets the circle x2 plus y2 -4x -8y -5 equals 0?

Last Answer : Equation of circle: x^2 +y^2 -4x -8y -5 = 0Completing the squares: (x-2)^2 +(y-4)^2 = 25 which is radiussquaredCenter of circle: (2, 4)Tangent line originates from: (8, ... angle triangleUsing Pythagoras theorem: distance^2 minus radius^2 = 15Therefore length of tangent line is the square root of 15

What is the center and the radius of the circle x2 plus y2 -4x -6y -3 equals 0?

Description : What is the center and the radius of the circle x2 plus y2 -4x -6y -3 equals 0?

Last Answer : Equation of circle: x^2 +y^2 -4x -6y -3 = 0Completing the squares: (x-2)^2 +(y-3)^2 = 16 square unitsTherefore center of circle is at (2, 3) and its radius is 4units

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Description : If f(x) x2 plus x find f(-3)?

Last Answer : -1

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Description : How do you Find From First Principle The Derivative Of 1(x2) plus 1 With Respect To Xx?

Last Answer : "First principles" in this context means that you:* Calculate the value of the function, at some point "x+h" * Calculate the value of the function, at some point "x" * Subtract the first result minus the second result * Divide all this ... As a formula: F(x)' = lim (as h --> 0) [F(x+h) - F(x)] / h

How do you graph y equals x squared plus 1?

Description : How do you graph y equals x squared plus 1?

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Description : Find the equation of tangents of the following curves at the given points: (i) Curve`x^(2) = 25` at point (3, 4) (ii) Curve `y = 2x^(3) + 2x^(2) - 8x+

Last Answer : Find the equation of tangents of the following curves at the given points: (i) Curve`x^(2) = 25` at point (3, 4) ... 2)(x-1) = 4x^(2)` at point (5, 5)

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Description : What if yx plus 5 were changed to yx plus 9 how would the graph of the new function compare with the first one?

Last Answer : If you mean y = x+5 and y = x+9 then both slopes will beparallel but with different y intercepts

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Description : What if yx plus 5 were changed to yx plus 9 how would the graph of the new function compare with the first one?

Last Answer : If you mean y = x+5 and y = x+9 then both slopes will beparallel but with different y intercepts

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Last Answer : Let A(x1, y1) = (3, 4), B(x2, y2) ≡ (0, 5), C(x3, y3) ≡ (2, -1)and D(x4, y4) ≡ (3, -2) be the vertices of quadrilateral ABCD.Area of quad. ABCD = \(rac{1}{2}\) |{(x1 y2 - x2 y1) + (x2y3 - x3y2) + (x3y4 - x4y3) ... ) + (12 + 6)}|= \(rac{1}{2}\) |{15 - 11 + 0 + 18}| = \(rac{1}{2}\)x 22 = 11 sq. units.

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Last Answer : (c) (5, 0) or (1, 4) Let the third vertex of the triangle be P(a, b). Since it lies on the line x + y = 5, a + b = 5 ...(i) Also, given area of triangle formed by the points (2, -1), (3, 2) and (a, b) = 4 ... b) - (-3a + b) = 5 + 15⇒ 4a = 20 ⇒ a = 5 ⇒ b = 0. ∴ The points are (1, 4) and (5, 0).