The percent composition of the elements in AgNO2 are: 70% Ag, 9% N, and 21% O.To determine the percent composition of each element, divide the molar mass of each element by the molar mass of the compound and multiply by 100.The molar mass of AgNO2 is 154 g/mol. The molar mass of Ag is 108 g/mol, the molar mass of N is 14 g/mol, and the molar mass of 2 O atoms is 32 g/mol.Percent composition of Ag:(108 g/mol Ag)/(154 g/mol AgNO2) x 100 = 70% AgPercent composition of N:(14 g/mol N)/(154 g/mol AgNO2) x 100 = 9% NPercent composition of O:(32 g/mol O)/(154 g/mol AgNO2) x 100 = 21% O