How many does 72 go into 12?

Description : A ball moving with uniform velocity comes to rest in a distance of 72 m in 6 s. Its initial velocity and retardation are (a) 12 m/s and 2 m/s2 (b) 12 m/s and 4 m/s2 (c) 24 m/s and 8 m/s2 (d) 24 m/s and 4 m/s2

Last Answer : Ans:(d)

As shown in the illustration if the applied voltage is 12 VDC, the resistance of R1 is 10 ohms, and R2 is 10 ohms what is the total power consumed by R1? EL-0036 A. 3.6 watts B. 72 watts C. 7.2 watts D. 36 watts

Description : As shown in the illustration if the applied voltage is 12 VDC, the resistance of R1 is 10 ohms, and R2 is 10 ohms what is the total power consumed by R1? EL-0036 A. 3.6 watts B. 72 watts C. 7.2 watts D. 36 watts

Last Answer : Answer: A

As shown in the illustration if the applied voltage is 12 VDC, the resistance of R1 is 10 ohms, and R2 is 10 ohms what is the total power consumed by the circuit? EL-0036 A. 3.6 watts B. 72 watts C. 7.2 watts D. 36 watts

Description : As shown in the illustration if the applied voltage is 12 VDC, the resistance of R1 is 10 ohms, and R2 is 10 ohms what is the total power consumed by the circuit? EL-0036 A. 3.6 watts B. 72 watts C. 7.2 watts D. 36 watts

Last Answer : Answer: C

As shown in the illustration if the applied voltage is 12 VDC, the resistance of R1 is 110 ohms, and R2 is 10 kohms what is the total power consumed by the circuit? EL-0036 A. 3.6 watts B. 72 watts C. .0011286 watts D. .014243 watts

Description : As shown in the illustration if the applied voltage is 12 VDC, the resistance of R1 is 110 ohms, and R2 is 10 kohms what is the total power consumed by the circuit? EL-0036 A. 3.6 watts B. 72 watts C. .0011286 watts D. .014243 watts

Last Answer : Answer: D

Sumati did some preliminary experiment with the lenses and found out that the magnification of the eyepiece (L 2 ) is 3. If in her experiment with L 2 she found an image at 24 cm from the lens, at what distance did she put the object? (a) 72 cm (b) 12 cm (c) 8 cm (d) 6 cm

Description : Sumati did some preliminary experiment with the lenses and found out that the magnification of the eyepiece (L 2 ) is 3. If in her experiment with L 2 she found an image at 24 cm from the lens, at what distance did she put the object? (a) 72 cm (b) 12 cm (c) 8 cm (d) 6 cm

Last Answer : (c) 8 cm

Calculate the phase constant of a wave with frequency 12 rad/s and velocity 3×10 8 m/s(in 10 -8 order) a) 0.5 b) 72 c) 4 d) 3

Description : Calculate the phase constant of a wave with frequency 12 rad/s and velocity 3×10 8 m/s(in 10 -8 order) a) 0.5 b) 72 c) 4 d) 3

Last Answer : c) 4

The bound charge density and free charge density are 12 and 6 units respectively. Calculate the susceptibility. a) 1 b) 0 c) 2 d) 72

Description : The bound charge density and free charge density are 12 and 6 units respectively. Calculate the susceptibility. a) 1 b) 0 c) 2 d) 72

Last Answer : c) 2

72 session of UN general Assembly held on? a. September 12 to 24, 2017 B. September 12 to 25, 2017 C. September 13 to 26, 2017 D. September 11 to 24, 2017

Description : 72 session of UN general Assembly held on? a. September 12 to 24, 2017 B. September 12 to 25, 2017 C. September 13 to 26, 2017 D. September 11 to 24, 2017

Last Answer : B. September 12 to 25, 2017

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Description : Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Last Answer : Sum of present ages of A, B and C is 72 years. sum of their ages (4 years ago) = 72 – (3 × 4) = 60 years 4 years ago, ratio of ages of A, B and C was 1 : 2 :3. A’s age, 4 years ago = (1/6) ×60 = 10 years A’s present age = 10 + 4 = 14 years Answer: d)

In how many different ways can the letters of the word DESIGN be arranged so that the vowels are at the two ends? a) 48 b) 66 c) 12 d) 72 e) 96

Description : In how many different ways can the letters of the word DESIGN be arranged so that the vowels are at the two ends? a) 48 b) 66 c) 12 d) 72 e) 96

Last Answer : Total ways = 4 ! x 2 ! = 4 × 3 × 2 x 2= 48 Answer: a)

I. 56x^2 – 127x + 72 = 0 II. 6y^2 – 17y + 12 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Description : I. 56x^2 – 127x + 72 = 0 II. 6y^2 – 17y + 12 = 0 1 : if x ≥ y 2 : if x ≤ y 3 : if x > y 4 : if x < y 5 : if x = y or relationship cannot be established

Last Answer : 4 : if x < y

Which is the number that comes next in the following sequence? 2, 6, 12, 20, 30, 42, 56, ………… (A) 60 (B) 64 (C) 72 (D) 70

Description : Which is the number that comes next in the following sequence? 2, 6, 12, 20, 30, 42, 56, ………… (A) 60 (B) 64 (C) 72 (D) 70

Last Answer : (C) 72

Rubika can do the 12 times the actual work in 72 days while sathya can do the one-half of the original work in 6 days. In how many days will both working together complete the 6 times of the original work? a) 20 days b) 25 days c) 30 days d) 35 days

Description : Rubika can do the 12 times the actual work in 72 days while sathya can do the one-half of the original work in 6 days. In how many days will both working together complete the 6 times of the original work? a) 20 days b) 25 days c) 30 days d) 35 days

Last Answer : C Efficiency of Rubika = 16.666% Efficiency of sathya = 4.166% Total efficiency of rubika and sathya =(16+4) =20% Actual work 100/20=5 So, they can do actual work in 5 days So, 6 times work requires 30 days.

X,Y and Z can do a certain job in 72,108 and 144 days respectively. They started the job but X left 16 days before the completion of the job while Y left 24 days before the completion. The number of days for which Z worked is. a) 12 days b) 24 days c) 36 days d) 48 days

Description : X,Y and Z can do a certain job in 72,108 and 144 days respectively. They started the job but X left 16 days before the completion of the job while Y left 24 days before the completion. The number of days for which Z worked is. a) 12 days b) 24 days c) 36 days d) 48 days

Last Answer : D Suppose the work was finished in a' days Then X's (a - 16) day's work + Y's (a - 24) days + Z's a days work = 1 (a-16)/72 + (a-24)/108 + a/144 =1 lcm of 72,108,144 is 432 (6(a-16) + 4( ... = 432 6a - 96 +4a - 96 =3a = 432 13a - 192 = 432 13a = 624 => a =48 Therefore Z worked in 48 days.

can 60 go into 72?

Description : can 60 go into 72?

Last Answer : how many tims can 60 go into 72

How many 2 can go into 72?

Description : How many 2 can go into 72?

Last Answer : 36

How many time dose 3 go into 72?

Description : How many time dose 3 go into 72?

Last Answer : 78

How many time dose 3 go into 72?

Description : How many time dose 3 go into 72?

Last Answer : 78