Cyclic trimer structure of `SO_(3)` contains:

Cyclic trimer structure of `SO_(3)` contains:
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Cyclic trimer structure of `SO_(3)` contains: A. `"6 S==O"` bonds and three S-O-S bonds B. `"3 S= ... ==O"` bonds and six S-O-S bonds D. None of these
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Asseration: Cyclic trimer of `SO_(3)` possesses have six membered hetero-cyclic chains made up of `S` and `O`-atoms Reason: Cyclic trimer of `SO_(3)`

Description : Asseration: Cyclic trimer of `SO_(3)` possesses have six membered hetero-cyclic chains made up of `S` and `O`-atoms Reason: Cyclic trimer of `SO_(3)`

Last Answer : Asseration: Cyclic trimer of `SO_(3)` possesses have six membered hetero-cyclic chains made up of `S` and ` ... SO_(3)` is referred as `gamma-SO_(3)`.

Asseration: Cyclic trimer of `SO_(3)` possesses have six membered hetero-cyclic chains made up of `S` and `O`-atoms Reason: Cyclic trimer of `SO_(3)`

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Asseration: Cyclic trimer of `SO_(3)` possesses have six membered hetero-cyclic chains made up of `S` and `O`-atoms Reason: Cyclic trimer of `SO_(3)`

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Which form is cyclic trimer of `SO_(3)`

Description : Which form is cyclic trimer of `SO_(3)`

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Description : The number of S-S bonds in sulphur trioxide trimer `(S_(3)O_(9))` is

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The number of S-S bonds in sulphur trioxide trimer `(S_(3)O_(9))` is

Description : The number of S-S bonds in sulphur trioxide trimer `(S_(3)O_(9))` is

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The number of S-S bonds in sulphur trioxide trimer `(gamma-form)` is:

Description : The number of S-S bonds in sulphur trioxide trimer `(gamma-form)` is:

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The number of S-S bonds in sulphur trioxide trimer `(S_(3)O_(9))` is

Description : The number of S-S bonds in sulphur trioxide trimer `(S_(3)O_(9))` is

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The total number of cyclic structure as well as stereoisomers possible for a compound with the molecular formula `C_(5)H_(10)` is:

Description : The total number of cyclic structure as well as stereoisomers possible for a compound with the molecular formula `C_(5)H_(10)` is:

Last Answer : The total number of cyclic structure as well as stereoisomers possible for a compound with the molecular formula `C_(5)H_(10)` is:

The total number of cyclic structure as well as stereoisomers possible for a compound with the molecular formula `C_(5)H_(10)` is:

Description : The total number of cyclic structure as well as stereoisomers possible for a compound with the molecular formula `C_(5)H_(10)` is:

Last Answer : The total number of cyclic structure as well as stereoisomers possible for a compound with the molecular formula `C_(5)H_(10)` is:

cAMP is so called because it is formed during (A) TCA cycle (B) Urea cycle (C) Rhodopsin cycle (D) It has a cyclic structure

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Benzene undergoes substitution reaction more easily than addition reaction because (a) it has a cyclic structure (b) it has three double bonds (c) it has six hydrogen atoms (d) there is delocalization of electrons

Description : Benzene undergoes substitution reaction more easily than addition reaction because (a) it has a cyclic structure (b) it has three double bonds (c) it has six hydrogen atoms (d) there is delocalization of electrons

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Benzene undergoes substitution reaction more easily than addition reaction because (a) it has a cyclic structure (b) it has three double bonds (c) it has six hydrogen atoms (d) there is delocalization of electrons

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If two opposite sides of a cyclic quadrilateral are parallel , then prove that - (a) remaining two sides are equal (b) both the diagonals are equal -Maths 9th

Description : If two opposite sides of a cyclic quadrilateral are parallel , then prove that - (a) remaining two sides are equal (b) both the diagonals are equal -Maths 9th

Last Answer : Let ABCD be quadrilateral with ab||cd Join be. In triangle abd and CBD, Angle abd=angle cdb(alternate angles) Anglecbd=angle adb(alternate angles) Bd=bd(common) Abd=~CBD by asa test Ad=BC by cpct Since ad ... c(from 1) Ad =bc(proved above) Triangle adc=~bcd by sas test Ac=bd by cpct Hence proved

If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

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Last Answer : Given ΔABC is an isosceles triangle such that AB = AC and also DE || SC. To prove Quadrilateral BCDE is a cyclic quadrilateral. Construction Draw a circle passes through the points B, C, D and E.

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Description : If a pair of opposite sides of a cyclic quadrilateral are equal, then prove that its diagonals are also equal. -Maths 9th

Last Answer : Given Let ABCD be a cyclic quadrilateral and AD = BC. Join AC and BD. To prove AC = BD Proof In ΔAOD and ΔBOC, ∠OAD = ∠OBC and ∠ODA = ∠OCB [since, same segments subtends equal angle to the circle] AB = BC [ ... is DOC on both sides, we get ΔAOD+ ΔDOC ≅ ΔBOC + ΔDOC ⇒ ΔADC ≅ ΔBCD AC = BD [by CPCT]

If non-parallel sides of a trapezium are equal, prove that it is cyclic. -Maths 9th

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If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle. -Maths 9th

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Last Answer : Given, ABCD is a cyclic quadrilateral. DP and QB are the bisectors of ∠D and ∠B, respectively. To prove PQ is the diameter of a circle. Construction Join QD and QC.

If two opposite sides of a cyclic quadrilateral are parallel , then prove that - (a) remaining two sides are equal (b) both the diagonals are equal -Maths 9th

Description : If two opposite sides of a cyclic quadrilateral are parallel , then prove that - (a) remaining two sides are equal (b) both the diagonals are equal -Maths 9th

Last Answer : Let ABCD be quadrilateral with ab||cd Join be. In triangle abd and CBD, Angle abd=angle cdb(alternate angles) Anglecbd=angle adb(alternate angles) Bd=bd(common) Abd=~CBD by asa test Ad=BC by cpct Since ad ... c(from 1) Ad =bc(proved above) Triangle adc=~bcd by sas test Ac=bd by cpct Hence proved

If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Description : If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Last Answer : Given ΔABC is an isosceles triangle such that AB = AC and also DE || SC. To prove Quadrilateral BCDE is a cyclic quadrilateral. Construction Draw a circle passes through the points B, C, D and E.

If a pair of opposite sides of a cyclic quadrilateral are equal, then prove that its diagonals are also equal. -Maths 9th

Description : If a pair of opposite sides of a cyclic quadrilateral are equal, then prove that its diagonals are also equal. -Maths 9th

Last Answer : Given Let ABCD be a cyclic quadrilateral and AD = BC. Join AC and BD. To prove AC = BD Proof In ΔAOD and ΔBOC, ∠OAD = ∠OBC and ∠ODA = ∠OCB [since, same segments subtends equal angle to the circle] AB = BC [ ... is DOC on both sides, we get ΔAOD+ ΔDOC ≅ ΔBOC + ΔDOC ⇒ ΔADC ≅ ΔBCD AC = BD [by CPCT]

If non-parallel sides of a trapezium are equal, prove that it is cyclic. -Maths 9th

Description : If non-parallel sides of a trapezium are equal, prove that it is cyclic. -Maths 9th

Last Answer : Given ABCD is a trapezium whose non-parallel sides AD and BC are equal.

If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle. -Maths 9th

Description : If bisectors of opposite angles of a cyclic quadrilateral ABCD intersect the circle, circumscribing it at the points P and Q, prove that PQ is a diameter of the circle. -Maths 9th

Last Answer : Given, ABCD is a cyclic quadrilateral. DP and QB are the bisectors of ∠D and ∠B, respectively. To prove PQ is the diameter of a circle. Construction Join QD and QC.

If diagonals of a cyclic quadrilateral are diameters of the circle through the vertices of the quadrilateral,prove that it is a rectangle. -Maths 9th

Description : If diagonals of a cyclic quadrilateral are diameters of the circle through the vertices of the quadrilateral,prove that it is a rectangle. -Maths 9th

Last Answer : Solution :- Let, ABCD be a cyclic quadrilateral such that its diagonal AC and BD are the diameters of the circle though the vertices A,B,C and D. As angle in a semi-circle is 900 ∴ ∠ABC = 900 and ∠ADC = 900 ∠DAB = 900 ... Hence, ABCD is a rectangle.

Prove that quadrilateral formed by angle bisectors of a cyclic quadrilateral is also cyclic. -Maths 9th

Description : Prove that quadrilateral formed by angle bisectors of a cyclic quadrilateral is also cyclic. -Maths 9th

Last Answer : Solution :- Given: A cyclic quadrilateral ABCD in which the angle bisectors AR, BR, CP O and DP of internal angles A, B, C and D respectively form a quadrilateral PQRS. To prove: PQRS ... the sum of a pair of opposite angles of quadrilateral PQRS is 180°. Therefore, quadrilateral PQRS is cyclic.

If A, B, C, D are the successive angles of a cyclic quadrilateral, then what is cos A + cos B + cos C + cos D equal to: -Maths 9th

Description : If A, B, C, D are the successive angles of a cyclic quadrilateral, then what is cos A + cos B + cos C + cos D equal to: -Maths 9th

Last Answer : answer:

Explain CYCLIC QUADRILATERAL and their porperties. -Maths 9th

Description : Explain CYCLIC QUADRILATERAL and their porperties. -Maths 9th

Last Answer : answer:

Let ABCD be a cyclic quadrilateral. Show that the incentres of the triangles ABC, BCD, CDA and DAB form a rectangle. -Maths 9th

Description : Let ABCD be a cyclic quadrilateral. Show that the incentres of the triangles ABC, BCD, CDA and DAB form a rectangle. -Maths 9th

Last Answer : answer:

The diagonals AC and BD of a cyclic quadrilateral ABCD intersect at P. Let O be the circumcentre of ∆APB and H be the orthocentre -Maths 9th

Description : The diagonals AC and BD of a cyclic quadrilateral ABCD intersect at P. Let O be the circumcentre of ∆APB and H be the orthocentre -Maths 9th

Last Answer : answer:

ABCD is a cyclic quadrilateral such that AC ⊥ BD. AC meet BD at E. Prove that EA^2 + EB^2 + EC^2 + ED^2 = 4R^2, -Maths 9th

Description : ABCD is a cyclic quadrilateral such that AC ⊥ BD. AC meet BD at E. Prove that EA^2 + EB^2 + EC^2 + ED^2 = 4R^2, -Maths 9th

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A cyclic parallelogram having unequal adjacent sides is necessarily a: -Maths 9th

Description : A cyclic parallelogram having unequal adjacent sides is necessarily a: -Maths 9th

Last Answer : answer:

In the given figure, ΔABC is an equilateral triangle and ABDC is a cyclic quadrilateral, then find the measure of ∠BDC. -Maths 9th

Description : In the given figure, ΔABC is an equilateral triangle and ABDC is a cyclic quadrilateral, then find the measure of ∠BDC. -Maths 9th

Last Answer : △ABC is an equilateral triangle. ∠BAE=60 ABEC is a cyclic quadrilateral. We know, ∠BAC+∠BEC=180 =>∠BEC=180−60 =120 We know that the angles subtended by an arc on the circumference on the same side are equal. Therefore, ∠ABC=∠BDC =>∠BDC=60

What is the role of water in non-cyclic photophosphorylation? -Biology

Description : What is the role of water in non-cyclic photophosphorylation? -Biology

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Difference between cyclic and noncyclic photophosphorylation. -Biology

Description : Difference between cyclic and noncyclic photophosphorylation. -Biology

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Site of non-cyclic photophosphorylation? -Biology

Description : Site of non-cyclic photophosphorylation? -Biology

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What does cyclic photophosphorylation yield? -Biology

Description : What does cyclic photophosphorylation yield? -Biology

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What is non-cyclic photophosphorylation? -Biology

Description : What is non-cyclic photophosphorylation? -Biology

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What is cyclic photophosphorylation? -Biology

Description : What is cyclic photophosphorylation? -Biology

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What is produced as a result of the cyclic light dependent reaction? -Biology

Description : What is produced as a result of the cyclic light dependent reaction? -Biology

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How Geometric Equilibrium is Created in Cyclic Compounds ?

Description : How Geometric Equilibrium is Created in Cyclic Compounds ?

Last Answer : : Geometric similarity is seen in the cyclic compound. In the case of cyclic compounds, in the three-dimensional structure of a molecule, identical atoms or radicals are formed on one side, sis ... isosomes are formed. For example , two geometric isotopes of 1-2-dimethyl cyclopropane are possible.

Non-cyclic photophosphorylation results in production of

Description : Non-cyclic photophosphorylation results in production of

Last Answer : Non-cyclic photophosphorylation results in production of A. ATP B. NADPH C. ATP nd NADPH D. ATP, NADPH , and `O_(2)`

Which one is produced during cyclic photo phosphorylation ?

Description : Which one is produced during cyclic photo phosphorylation ?

Last Answer : Which one is produced during cyclic photo phosphorylation ? A. ATP and `NADPH_(2)` B. ATP only C. ATP and `O_(2)` D. `NADPH_(2)`

The first electron acceptor in photosystem-I of cyclic photophosphorylation is

Description : The first electron acceptor in photosystem-I of cyclic photophosphorylation is

Last Answer : The first electron acceptor in photosystem-I of cyclic photophosphorylation is A. Cytochrome B. Plastocyanin C. Ferrodoxin D. Plastoquinone

Cyclic photophosphorylation releases

Description : Cyclic photophosphorylation releases

Last Answer : Cyclic photophosphorylation releases A. ATP and `NADPH_(2)` B. ATP , `NADPH_(2) ` and oxygen C. ATP only D. `NADPH_(2)` only

During menstrual cycle, the cyclic changes take place in

Description : During menstrual cycle, the cyclic changes take place in

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Which layer of uterus undergoes cyclic changes during menstrual cycle

Description : Which layer of uterus undergoes cyclic changes during menstrual cycle

Last Answer : Which layer of uterus undergoes cyclic changes during menstrual cycle A. Myometrium B. Endometrium C. Perimetrium D. All the above.