`XeF_(6)` reacts with silica to form xenon compound X. The oxidation state of Xe in X is :

`XeF_(6)` reacts with silica to form xenon compound X. The oxidation state of Xe in X is :
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`XeF_(6)` reacts with silica to form xenon compound X. The oxidation state of Xe in X is :
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In `XeO_(3)` and `XeF_(6)` the oxidation state of `Xe` is

Description : In `XeO_(3)` and `XeF_(6)` the oxidation state of `Xe` is

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Oxidation number of Xe in `XeF_(5)^(-)` is :

Description : Oxidation number of Xe in `XeF_(5)^(-)` is :

Last Answer : Oxidation number of Xe in `XeF_(5)^(-)` is : A. `+1` B. `+2` C. `+3` D. `+4`

Among the following molecules, `(i)XeO_(3)(ii)XeOF_(4)(iii)XeF_(6)` those having same number of lone pairs on `Xe` are:

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Find the number of compounds among the following whose hydrolysis is a non-redox reaction. `XeF_(2),XeF_(4),XeF_(6),XeO_(2)F_(2),XeOF_(4),Xe,XeO_(3)`

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Total number of lone pairs on Xe in `XeF_(2), XeO_(3)F_(2), XeF_(4), XeF_(6)` is t,u,v & w respectively. Then

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The increasing d-character in hybridisation of Xe in `XeF_(2), XeF_(4), XeF_(6)` is

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The number of lone pairs of electrons present on Xe in `XeF_(2)` ?

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Xenon tetrafluoride, `XeF_(4)` is:

Description : Xenon tetrafluoride, `XeF_(4)` is:

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In `XeF_(4)` molecule, xenon undergoes

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The number of lone pairs of electrons on xenon atom in `XeF_(4)` molecule is

Description : The number of lone pairs of electrons on xenon atom in `XeF_(4)` molecule is

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`XeF_(4)` is a square planar molecule. The hybridisation of xenon atom in this molecule is

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`XeF_6` on partial hydrolysis with water produces a compound ‘X’. The same compound ‘X’ is formed when `XeF_6` reacts with silica. The compound ‘X’ Is

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Last Answer : `XeF_6` on partial hydrolysis with water produces a compound X'. The same compound X' is formed when `XeF_6` ... XeF_4` C. (3)`XeF_2` D. (4)`XeOF_4`

Sulphide ion reacts with `[Fe(CN)_(5)NO]` to form a purple coloured compound (X). In this reaction oxidation state of iron .

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Oxidation state of Xe in `Ba_(2)[XeO_(6)]` is

Description : Oxidation state of Xe in `Ba_(2)[XeO_(6)]` is

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Which of the following is formed when `O_(2)F_(2)` reacts with Xe ?

Description : Which of the following is formed when `O_(2)F_(2)` reacts with Xe ?

Last Answer : Which of the following is formed when `O_(2)F_(2)` reacts with Xe ? A. `XeF_(2)` B. `XeF_(4)` C. `XeF_(6)` D. None of these

Xenon reacts with `P+F_6` to form

Description : Xenon reacts with `P+F_6` to form

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Among noble gases, only xenon reacts with flourine to form stable xenon fluorides, because xenon

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Which of the following compound will not form during the hydrolysis of `XeF_(6)` ?

Description : Which of the following compound will not form during the hydrolysis of `XeF_(6)` ?

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Last Answer : Xenon hexa fluoride reacts with potassium fluoride to yield A. `[XeF_(4)]^(2+) [KF_(3)]^(2-)` B. `K^(+) [XeF_( ... (5)]^(+) [KF_(2)]^(-)` D. `XeF_(4)`

Asseration: The first real compound of the noble gases in `1962 "was" Xe^(+)[PtF_(6)]^(-)`. Reason: The discovery was based on the basis of comparable

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Last Answer : Asseration: The first real compound of the noble gases in `1962 "was" Xe^(+)[PtF_(6)]^(-)`. Reason: The discovery ... = 90^(@)` D. `A = B = 90^(@)`

Asseration: The first real compound of the noble gases in `1962 "was" Xe^(+)[PtF_(6)]^(-)`. Reason: The discovery was based on the basis of comparable

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In the preparation of compounds of Xe, Bartlett has taken `O_(2)^(+)Pt F_(6)^(-)` as a base compound. This is becase

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Last Answer : In the preparation of compounds of Xe, Bartlett has taken `O_(2)^(+)Pt F_(6)^(-)` as a base compound ... enthalpy. D. both Xe and `O_(2)` are gases.

`(A)+SbF_(5)to[XeF_(3)]^(+)[SbF_(6)]^(-)` Compound (A) is

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A compound reacts with sodium and liberates hydrogen and on oxidation gives ketone. The formula of the compound could be

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Which one of the following is a correct pair with respect to molecular formula of xenon compound and hybridisation state of xenon in it ?

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Which of the following compound is formed when `XeF_(4)` react with water ?

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The compound that cannot be formed by xenon is

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Which of the following xenon compound has the same number of lone pairs as in `I_(3)^(-)`? (near central atom)

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When `PtE_(6)` vapour mixed with an equal volume of Xe, the gases combined immediatedly at room temperature and produces a yellow solid X at `66^(@)C`

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Evaluate: `int(x+1)/(x(1+xe^x)^2)dx`

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Find the divergence of the vector F= xe -x i + y j – xz k a) (1 – x)(1 + e -x ) b) (x – 1)(1 + e -x ) c) (1 – x)(1 – e) d) (x – 1)(1 – e)

Description : Find the divergence of the vector F= xe -x i + y j – xz k a) (1 – x)(1 + e -x ) b) (x – 1)(1 + e -x ) c) (1 – x)(1 – e) d) (x – 1)(1 – e)

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A `C_(6)H_(12)O` compound does not react with `Br_(2)` in `C Cl_(4)`, produces a flammable gas on treatment with `LiAlH_(4)`, and reacts with `H_(2)Cr

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Give the molecular structures of : `XeF_(2),XeF_(4),XeF_(6)` `XeOF_(4) " and " XeO_(3)`

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`XeF_(6)` on reaction with CsF gives:

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Last Answer : `XeF_(6)` on reaction with CsF gives: A. `Cs[XeF_(7)]` B. `[XeF_(4)][CsF_(3)]` C. `XeF_(8)` D. `[XeF_(5)] [CsF_(2)]`

`XeF_(6)` dissolves in anhydrous `HF` to give a good conducting solution which contains:

Description : `XeF_(6)` dissolves in anhydrous `HF` to give a good conducting solution which contains:

Last Answer : `XeF_(6)` dissolves in anhydrous `HF` to give a good conducting solution which contains: A. `H^(+)` and ` ... +)` and `F^(-)` ions D. none of these

Assertion : `XeF_(6)` cannot be stored in the dry glass bottles Reason : `XeF_(6)` attacks the glass

Description : Assertion : `XeF_(6)` cannot be stored in the dry glass bottles Reason : `XeF_(6)` attacks the glass

Last Answer : Assertion : `XeF_(6)` cannot be stored in the dry glass bottles Reason : `XeF_(6)` attacks the glass

Which of the following does not exist ? a) `XeOF_(4)` b) `NeF_(2)` c) `XeF_(2)` d) `XeF_(6)`

Description : Which of the following does not exist ? a) `XeOF_(4)` b) `NeF_(2)` c) `XeF_(2)` d) `XeF_(6)`

Last Answer : Which of the following does not exist ? a) `XeOF_(4)` b) `NeF_(2)` c) `XeF_(2)` d) `XeF_(6)`

`XeF_(6)` on hydrolysis gives

Description : `XeF_(6)` on hydrolysis gives

Last Answer : `XeF_(6)` on hydrolysis gives A. `XeOF_(4)` B. `XeO_(2)F_(2)` C. `XeO_(3)` D. `XeO_(4)`

`XeF_(6)` can acts as

Description : `XeF_(6)` can acts as

Last Answer : `XeF_(6)` can acts as A. Fluoride donor only B. Fluoride acceptor only C. Either fluoride donor or acceptor D. Catalyst in nuclear reactions

The hydrolysis of `XeF_(6)` takes place in the following steps : `XeF_(6) rarr A rarr B rarr XeO_(3)`. Then the correct statement regarding A and B is

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Last Answer : The hydrolysis of `XeF_(6)` takes place in the following steps : `XeF_(6) rarr A rarr B rarr ... A is also obtained when `XeF_(6)` reacts with silica

`XeF_(6)` on complete hydroloysis gives

Description : `XeF_(6)` on complete hydroloysis gives

Last Answer : `XeF_(6)` on complete hydroloysis gives A. `XeO_(4)` B. `XeOF_(2)` C. `XeOF_(4)` D. `XeO_(3)`

Which of the following statements(s) is/are true for `XeF_(6)`?

Description : Which of the following statements(s) is/are true for `XeF_(6)`?

Last Answer : Which of the following statements(s) is/are true for `XeF_(6)`? A. Its partial hydrolysis gives `XeOF_( ... reaction with `XeO_(3)` gives `XeOF_(4)`.

`XeF_(6)` on complete hydroysis gives.

Description : `XeF_(6)` on complete hydroysis gives.

Last Answer : `XeF_(6)` on complete hydroysis gives. A. Xe B. `XeO_(2)` C. `XeO_(3)` D. `XeO_(4)`