When `HNO_(3)` is converted into `NH_(3)`, the equivalent weight of `HNO_(3)` will be:

1 Answer

Answer :

When `HNO_(3)` is converted into `NH_(3)`, the equivalent weight of `HNO_(3)` will be: A. M/2 B. M/1 C. M/6 D. M/8

Related questions

Description : When `N_(2)` is converted into `NH_(3)`, the equivalent weight of nitrogen will be:

Last Answer : When `N_(2)` is converted into `NH_(3)`, the equivalent weight of nitrogen will be: A. 1.67 B. 2.67 C. 3.67 D. 4.67

Description : What is the product when `C_(6)H_(5)CH_(2)NH_(2)` reacts with `HNO_(3)`?

Last Answer : What is the product when `C_(6)H_(5)CH_(2)NH_(2)` reacts with `HNO_(3)`?

Description : Assertion :- Equivalent weight of `NH_(3)` in the reaction `N_(2) rarrNH_(3)` is `17//3` while that of `N_(2)` is `28//6`. Reason :- `"Equivalent weig

Last Answer : Assertion :- Equivalent weight of `NH_(3)` in the reaction `N_(2) rarrNH_(3)` is `17//3` while ... is False. D. If both Assertion & Reason are False.

Description : Equivalent weight of `NH_(3)` in the change `N_(2)rarrNH_(3)` is :

Last Answer : Equivalent weight of `NH_(3)` in the change `N_(2)rarrNH_(3)` is : A. `(17)/(6)` B. 17 C. `(17)/(2)` D. `(17)/(3)`

Description : In the conversion `NH_(2)OH rarr N_(2)O`, the equivalent weight of `NH_(2)OH` will be:

Last Answer : In the conversion `NH_(2)OH rarr N_(2)O`, the equivalent weight of `NH_(2)OH` will be: A. M/4 B. M/2 C. M/5 D. M/1

Description : The equivalent weight of `MnSO_(4)` is half its molecular weight when it is converted to

Last Answer : The equivalent weight of `MnSO_(4)` is half its molecular weight when it is converted to A. `Mn_(2)O_(3)` B. ` ... . `MnO_(4)^(-)` D. `MnO_(4)^(-2)`

Description : `3 g` of an oxide of a metal is converted completely to `5 g` chloride. Equivalent weight of metal is:

Last Answer : `3 g` of an oxide of a metal is converted completely to `5 g` chloride. Equivalent weight of metal is: A. 33.25 B. 3.325 C. 12 D. 20

Description : An scan be easily converted to its decimal equivalent by multiplying each octal digit by positional weight: a. Binary number b. Octal number c. Hexadecimal number d. Decimal number

Last Answer : b. Octal number

Description : Which can be converted to inferred equivalent CNF sentence? a) Every sentence of propositional logic b) Every sentence of inference c) Every sentence of first-order logic d) All of the mentioned

Last Answer : c) Every sentence of first-order logic

Description : The first law of thermodynamics may be expressed in the following equivalent  a. the net heat transfer id equal to the network  b. the sum of the total energy forms leaving the system boundary is ... neither be created nor destroyed but only converted from one form to another  d. all of the above

Last Answer : all of the above

Description : Assertion :- Nitrous acid `(HNO_(2))` may act as an oxidising agent as well as a reducing agent. Reason :- The oxidation number of Nitrogen remains sa

Last Answer : Assertion :- Nitrous acid `(HNO_(2))` may act as an oxidising agent as well as a reducing agent. ... False. D. If both Assertion & Reason are False.

Description : In the reaction :- `C+4HNO_(3)rarrCO_(2)+2H_(2)O+4NO_(2)` `HNO_(3)` acts as :-

Last Answer : In the reaction :- `C+4HNO_(3)rarrCO_(2)+2H_(2)O+4NO_(2)` `HNO_(3)` acts as :- A. An oxidising agent B. An acid C. A reducing agent D. None of them

Description : `HNO_(2)` acts as an oxidant with which one of the following reagent :-

Last Answer : `HNO_(2)` acts as an oxidant with which one of the following reagent :- A. `KMnO_(4)` B. `H_(2)S` C. `K_(2)Cr_(2)O_(7)` D. `Br_(2)`

Description : What is the number of moles of O-atom in 126 amu of `HNO_(3)` ?

Last Answer : What is the number of moles of O-atom in 126 amu of `HNO_(3)` ? A. 2 B. `(2)/(N_(A))` C. 6 D. `(6)/(N_(A))`

Description : Aniline reacts with mixed acid (conc. `HNO_(3)` and conc. `H_(2)SO_(4)`) at 288 K to give P (51%), Q (47%) and R(2%). The major product (s) of the fol

Last Answer : Aniline reacts with mixed acid (conc. `HNO_(3)` and conc. `H_(2)SO_(4)`) at 288 K to give P ... of the following reaction sequence is (are) B. C. D.

Description : Para toluidine is treated with `HNO_(2)` at ice cold conditions and then boiled with water. The final product obtained is :

Last Answer : Para toluidine is treated with `HNO_(2)` at ice cold conditions and then boiled with water. The final ... acid B. p-cresol C. toluic acid D. phenol

Description : Upon long standing concetrated `HNO_(3)`

Last Answer : Upon long standing concetrated `HNO_(3)` A. remains colourless, but gives out NO B. turns yellow brown ... D. remains colourless, but gives `N_(2)O`

Description : iodine rects with connentrated `HNO_(3)` to yield Y along with other products , the oxidation state of iodine in Y , is :

Last Answer : iodine rects with connentrated `HNO_(3)` to yield Y along with other products , the oxidation state of iodine in Y , is : A. 7 B. 3 C. 1 D. 5

Description : Platinum metal (Pt) dissolves in aqua-regia but not in concentrated HCl ot `HNO_(3)` because

Last Answer : Platinum metal (Pt) dissolves in aqua-regia but not in concentrated HCl ot `HNO_(3)` because A. HCl ... (3)` together give `O_(2)` that oxidises Pt

Description : The nitrogen containing compound produced in the reaction of `HNO_(3)` with `P_(4)O_(10)`

Last Answer : The nitrogen containing compound produced in the reaction of `HNO_(3)` with `P_(4)O_(10)` A. ... bond D. react with Na metal producing a brown gas

Description : Which gas is evolved when `PbO_(2)` is treated with conc `HNO_(3)` ?

Last Answer : Which gas is evolved when `PbO_(2)` is treated with conc `HNO_(3)` ? A. `NO_(2)` B. `O_(2)` C. `N_(2)` D. `N_(2)O`

Description : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Last Answer : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Description : Number of acids having central atom in `+3` oxidation state among the following is (a) `HNO_(2)` (b) `HNO_(3)` (c) `H_(3)PO_(2)` (d) `H_(3)PO_(3)` (e)

Last Answer : Number of acids having central atom in `+3` oxidation state among the following is (a) `HNO_(2)` (b) `HNO_(3)` (c ... (2)S_(2)O_(8)` (k) `H_(2)SO_(4)`

Description : `N_(2)O_(4), (HPO_(2))_(2), H_(2)CO_(3), SO_(2), SO_(3), P_(4)O_(10) H_(2)SO_(4), N_(2)O_(3), HNO_(3), H_(3)PO_(3)`. (a) Among the above compounds, co

Last Answer : `N_(2)O_(4), (HPO_(2))_(2), H_(2)CO_(3), SO_(2), SO_(3), P_(4)O_(10) H_(2)SO_(4), N_(2)O_(3 ... `d pi - p pi` bond are y. Given the answer as `x + y`

Description : `HNO_(3)+P_(4)O_(10) to HPO_(3) + X` in the above reaction the product `X` is :

Last Answer : `HNO_(3)+P_(4)O_(10) to HPO_(3) + X` in the above reaction the product `X` is : A. `NO_(2)` B. `N_(2)O_(3)` C. `N_(2)O_(4)` D. `N_(2)O_(5)`

Description : Upon long standing concetrated `HNO_(3)`

Last Answer : Upon long standing concetrated `HNO_(3)` A. remains colourless, but gives out NO B. turns yellow brown ... D. remains colourless, but gives `N_(2)O`

Description : iodine rects with connentrated `HNO_(3)` to yield Y along with other products , the oxidation state of iodine in Y , is :

Last Answer : iodine rects with connentrated `HNO_(3)` to yield Y along with other products , the oxidation state of iodine in Y , is : A. 7 B. 3 C. 1 D. 5

Description : Platinum metal (Pt) dissolves in aqua-regia but not in concentrated HCl ot `HNO_(3)` because

Last Answer : Platinum metal (Pt) dissolves in aqua-regia but not in concentrated HCl ot `HNO_(3)` because A. HCl ... (3)` together give `O_(2)` that oxidises Pt

Description : The nitrogen containing compound produced in the reaction of `HNO_(3)` with `P_(4)O_(10)`

Last Answer : The nitrogen containing compound produced in the reaction of `HNO_(3)` with `P_(4)O_(10)` A. ... bond D. react with Na metal producing a brown gas

Description : Which gas is evolved when `PbO_(2)` is treated with conc `HNO_(3)` ?

Last Answer : Which gas is evolved when `PbO_(2)` is treated with conc `HNO_(3)` ? A. `NO_(2)` B. `O_(2)` C. `N_(2)` D. `N_(2)O`

Description : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Last Answer : Cold conc. `HNO_(3)` will completely dissolve: (i) Pb (ii) `Pb_(3)O_(4)` (iii) Fe (iv) Sn (v) Mg (vi) MgO (vii) Hg (viii) Au (ix) Ag (x) Pt

Description : Number of acids having central atom in `+3` oxidation state among the following is (a) `HNO_(2)` (b) `HNO_(3)` (c) `H_(3)PO_(2)` (d) `H_(3)PO_(3)` (e)

Last Answer : Number of acids having central atom in `+3` oxidation state among the following is (a) `HNO_(2)` (b) `HNO_(3)` (c ... (2)S_(2)O_(8)` (k) `H_(2)SO_(4)`

Description : `N_(2)O_(4), (HPO_(2))_(2), H_(2)CO_(3), SO_(2), SO_(3), P_(4)O_(10) H_(2)SO_(4), N_(2)O_(3), HNO_(3), H_(3)PO_(3)`. (a) Among the above compounds, co

Last Answer : `N_(2)O_(4), (HPO_(2))_(2), H_(2)CO_(3), SO_(2), SO_(3), P_(4)O_(10) H_(2)SO_(4), N_(2)O_(3 ... `d pi - p pi` bond are y. Given the answer as `x + y`

Description : `HNO_(3)+P_(4)O_(10) to HPO_(3) + X` in the above reaction the product `X` is :

Last Answer : `HNO_(3)+P_(4)O_(10) to HPO_(3) + X` in the above reaction the product `X` is : A. `NO_(2)` B. `N_(2)O_(3)` C. `N_(2)O_(4)` D. `N_(2)O_(5)`

Description : One litre of a solution contains 18.9 g of `HNO_(3)` and one litre of another solution contains 3.2 g of NaOH. In what volume ratio must these solutio

Last Answer : One litre of a solution contains 18.9 g of `HNO_(3)` and one litre of another solution contains 3.2 g of NaOH. In ... B. `8:3` C. `15:4` D. `4:15`

Description : Sodium extract is heated with concentrated `HNO_(3)` before testing for halogens because :

Last Answer : Sodium extract is heated with concentrated `HNO_(3)` before testing for halogens because : A. Ag reacts ... )` and hence do not interfere in the test.

Description : When a mixture containing phosphate is heated with conc. `HNO_(3)` and ammonium molybdated solution, a canary yellow precipitate is formed . The formu

Last Answer : When a mixture containing phosphate is heated with conc. `HNO_(3)` and ammonium molybdated solution, a canary yellow ... PO_(4). (NH_(4))_(2)MO_(4)`

Description : In the nitration of benzene with a mixture of conc. `HNO_(3)` and conc. `H_(2)SO_(4)`, the active species involved is :

Last Answer : In the nitration of benzene with a mixture of conc. `HNO_(3)` and conc. `H_(2)SO_(4)`, ... ion B. nitrate ion C. nitronium ion D. nitrogen dioxide

Description : `{:("Column" (I) , "Column"(II)), ((a) "Presence of halogen" , P. HNO_(3)//AgNO_(3)), ((b) "Presence of sulphur" , Q. Na_(2)[Fe(CN)_(5)NO]) , ((c) "Pr

Last Answer : `{:("Column" (I) , "Column"(II)), ((a) "Presence of halogen" , P. HNO_(3)//AgNO_(3)), ((b) "Presence ... (d) "Presence of" P "and" S , S. FeCl_(3)):}`

Description : Which of the following give nitrosonamine on treatment with `HNO_(2)`?

Last Answer : Which of the following give nitrosonamine on treatment with `HNO_(2)`? A. B. `H_(3)C-underset(CH_(3))underset(|)(CH)-CH_(2)-NH_(2)` C. D.

Description : Which of the following compounds react with `HNO_(2)`?

Last Answer : Which of the following compounds react with `HNO_(2)`? A. B. C. D.

Description : Which of the following compounds does not liberate `N_(2)` on treatement with `HNO_(2)`?

Last Answer : Which of the following compounds does not liberate `N_(2)` on treatement with `HNO_(2)`? A. `H_(3)C- ... `H_(3)C-underset(H)underset(|)(N)-CO_(3)`

Description : Phenol `underset("distillation")overset("Zinc")(rarr)(A)underset("conc."HNO_(3) "at 333K")overset("conc." HNO_(3))(rarr)(B)underset("NaOH")overset(Zn)

Last Answer : Phenol `underset("distillation")overset("Zinc")(rarr)(A)underset("conc."HNO_(3) "at 333K" ... -nitroaniline D. toluene, m-nitrobenzene and m-toulidine

Description : `"phenol" overset(conc.H_(2)SO_(4))rarrA overset(conc.HNO_(3))rarrB` Here A and B are respectively.

Last Answer : `"phenol" overset(conc.H_(2)SO_(4))rarrA overset(conc.HNO_(3))rarrB` Here A and B ... 4-dinitrophenol D. 3-Hydroxybenzene sulphonic acid, picric acid

Description : Phenol on treatment with conc. `HNO_(3)` gives

Last Answer : Phenol on treatment with conc. `HNO_(3)` gives A. picric acid B. o-and m-nitrophenols C. cresol D. resorcinol

Description : Anisole with conc. `HNO_(3)` and conc. `H_(2)SO_(4)` gives

Last Answer : Anisole with conc. `HNO_(3)` and conc. `H_(2)SO_(4)` gives A. Phenol B. Nitrobenzene C. O - and - P - Nitroanisole D. O- Nitroanisole

Description : Among the following the number of compounds that can act as dehydrating agent are …… `Conc. H_(2)SO_(4),"Anhyd". CaCl_(2),Conc. HNO_(3), CaO, CuSO_(4)

Last Answer : Among the following the number of compounds that can act as dehydrating agent are `Conc. H_(2)SO_(4),"Anhyd" ... CaO, CuSO_(4).5H_(2)O, P_(2)O_(5)`

Description : `NH_(3)` change into urea in presence of

Last Answer : `NH_(3)` change into urea in presence of A. Arginase enzyme B. Urinase enzyme C. Xanthine oxidase D. Uricase

Description : Liquid hydrocarbons are converted to low molecular weight gaseous hydrocarbons by a process known as (a) hydrogenation (b) reforming (c) cracking (d) reduction

Last Answer : Ans:(c)

Description : What is `NH_(3)` is

Last Answer : `NH_(3)` is A. Less toxic B. Toxic C. Highly toxic D. None