`3 g` of an oxide of a metal is converted completely to `5 g` chloride. Equivalent weight of metal is:

1 Answer

Answer :

`3 g` of an oxide of a metal is converted completely to `5 g` chloride. Equivalent weight of metal is: A. 33.25 B. 3.325 C. 12 D. 20

Related questions

Description : 1.12 litre dry chlorine gas at STP was passed over a heated metal when 5.56 g of chloride of the metal was formed. What is the equivalent weight of th

Last Answer : 1.12 litre dry chlorine gas at STP was passed over a heated metal when 5.56 g of chloride of ... formed. What is the equivalent weight of the metal ?

Description : 74.5 g of a metallic chloride contains 35.5 g of chlorine. The equivalent weight of the metal is [CPMT 1986] (A) 19.5 (B) 35.5 (C) 39.0 (D) 78.0

Last Answer : (C) 39.0

Description : A metal oxide has `40%` oxygen. The equivalent weight of the metal is:

Last Answer : A metal oxide has `40%` oxygen. The equivalent weight of the metal is:

Description : If the equivalent mass of a metal is double that of oxygen then the weight of its oxide is ___ times greater than the weight of the metal.

Last Answer : If the equivalent mass of a metal is double that of oxygen then the weight of its oxide is ___ times greater than the ... A. 1.5 B. 2 C. 0.5 D. 3

Description : If 31.3 g of manganese(II) chloride 48.3 g of chlorine gas and 25.7 g of water react to produce manganese(IV) oxide and hydrochloric acid what is the limiting reactant and what mass of hydrochloric?

Last Answer : Need answer

Description : 1 mole of `OH^(-)` ions is obtained from 85 g of hydroxide of a metal. What is the equivalent weight of the metal ?

Last Answer : 1 mole of `OH^(-)` ions is obtained from 85 g of hydroxide of a metal. What is the equivalent weight of the metal ?

Description : X gm of metal gave Y gm of its oxide, so equivalent mass of metal is :

Last Answer : X gm of metal gave Y gm of its oxide, so equivalent mass of metal is : A. `(y-x)/(x)xx8` B. `(x)/((y-x))xx8` C. `(x)/(y)xx8` D. `(x+y)/(x)xx8`

Description : The equivalent weight of `MnSO_(4)` is half its molecular weight when it is converted to

Last Answer : The equivalent weight of `MnSO_(4)` is half its molecular weight when it is converted to A. `Mn_(2)O_(3)` B. ` ... . `MnO_(4)^(-)` D. `MnO_(4)^(-2)`

Description : When `HNO_(3)` is converted into `NH_(3)`, the equivalent weight of `HNO_(3)` will be:

Last Answer : When `HNO_(3)` is converted into `NH_(3)`, the equivalent weight of `HNO_(3)` will be: A. M/2 B. M/1 C. M/6 D. M/8

Description : When `N_(2)` is converted into `NH_(3)`, the equivalent weight of nitrogen will be:

Last Answer : When `N_(2)` is converted into `NH_(3)`, the equivalent weight of nitrogen will be: A. 1.67 B. 2.67 C. 3.67 D. 4.67

Description : An scan be easily converted to its decimal equivalent by multiplying each octal digit by positional weight: a. Binary number b. Octal number c. Hexadecimal number d. Decimal number

Last Answer : b. Octal number

Description : 0.98 g of the metal sulphate was dissolved in water and excess of barium chloride was added. The precipitated barium sulphate weighted 0.95 g. Calcula

Last Answer : 0.98 g of the metal sulphate was dissolved in water and excess of barium chloride was added. ... 95 g. Calculate the equivalent weight of the metal.

Description : If the equivalent weight of an element is 32, then the percentage of oxygen in its oxide is :

Last Answer : If the equivalent weight of an element is 32, then the percentage of oxygen in its oxide is : A. 16 B. 40 C. 32 D. 20

Description : The law of definite proportions is not applicable to nitrogen oxide because [EAMCET 1981] (A) Nitrogen’s atomic weight is not constant (B) Nitrogen’s molecular weight is variable (C) Nitrogen’s equivalent weight is variable (D) Oxygen’s atomic weight is variable

Last Answer : (C) Nitrogen’s equivalent weight is variable

Description : Two samples of lead oxide were separately reduced to metallic lead by heating in a current of hydrogen. The weight of lead from one oxide was half the weight of lead obtained from the other oxide. ... (B) Law of constant proportions (C) Law of multiple proportions (D) Law of equivalent proportions

Last Answer : (C) Law of multiple proportions

Description : A sulphide ore is first converted into its oxide before reduction. This is done because :

Last Answer : A sulphide ore is first converted into its oxide before reduction. This is done because : A ... oxide is generally less stable than the metal sulphide

Description : In the gaseous diffusion process of uranium enrichment, the natural uranium is converted into gaseous (A) Uranium oxide (B) Uranium hexafluoride (C) Uranium carbide (D) Uranium sulphate

Last Answer : (B) Uranium hexafluoride

Description : Benzenediazonium chloride can be converted into benzene on treatment with:

Last Answer : Benzenediazonium chloride can be converted into benzene on treatment with: A. `H_(3)PO_(3)` B. `H_(3)PO_(4)` C. `H_(3)PO_(2)` D. `HPO_(3)`

Description : Which of the following are used as chlorinating agents in organic synthesis of compounds ? (Like acid converted to acid chloride)

Last Answer : Which of the following are used as chlorinating agents in organic synthesis of compounds ? (Like acid converted to acid ... C. `PCl_(3)` D. `PCl_(5)`

Description : Which of the following are used as chlorinating agents in organic synthesis of compounds ? (Like acid converted to acid chloride)

Last Answer : Which of the following are used as chlorinating agents in organic synthesis of compounds ? (Like acid converted to acid ... C. `PCl_(3)` D. `PCl_(5)`

Description : Which of the following statements is false about toluene? (a) can be prepared by treating benzene with methyl chloride in the presence of AlCl3. (b) is converted to benzoic acid on refluxing with ... (d) can be nitrated with concentrated nitric acid to give a mixture of ortho and meta nitrotoluene.

Last Answer : can be nitrated with concentrated nitric acid to give a mixture of ortho and meta nitrotoluene

Description : Which of the following statements are false about benzene? (a) It is a planar molecule with bond angles 120°. (b) It is immiscible with water forming the lower layer. (c) It can be ... Ni catalyst. (d) It reacts with ethyl chloride in the presence of aluminium chloride to form ethylbenzene.

Last Answer : It is immiscible with water forming the lower layer

Description : To measure the quantity of `MnCl_(2)` dissolved in an queous solution, it was completely converted to `KMnO_(4)` using the reaction `MnCl_(2)+K_(2)S_(

Last Answer : To measure the quantity of `MnCl_(2)` dissolved in an queous solution, it was completely converted to `KMnO_(4)` ... g `mol^(-1)`: Mn=55,Cl=35.5)

Description : In guard cells when sugar is converted into starch, the stomatal pore (a) closes completely (b) opens partially (c) opens fully (d) remains unchanged.

Last Answer : a) closes completely

Description : Write the molecular formulae of: 1. Copper oxide 2. Iron (III) chloride 3. Sodium hydroxide 4. Iron (II) sulphide 5. Lead (II) oxide 6. Hydrogen nitrate (nitric ... Hydrogen sulphate (sulphuric acid) 8. Calcium hydroxide 9. Magnesium carbonate 10.Ammonium carbonate

Last Answer : 1. Copper oxide - CuO 2. Iron (III) chloride - FeCl3 3. Sodium hydroxide - NaOH 4. Iron (II) sulphide - FeS 5. Lead (II) oxide - PbO 6. Hydrogen nitrate (nitric acid) - HNO3 7. ... ) - H2SO4 8. Calcium hydroxide - Ca(OH)2 9. Magnesium carbonate - MgCO3 10.Ammonium carbonate - (NH4)2CO3

Description : Sodium chloride, potassium chloride, magnesium oxide are examples of molecules with (a) Covalent bonding (b) Ionic bonding (c) Metallic bonding (d) Hydrogen bonding

Last Answer : Ans:(b)

Description : Chemical name of common salt is – (1) Sodium Chloride (2) Sodium Bicarbonate (3) Sodium (4) Sodium Oxide

Last Answer : (1) Sodium Chloride Explanation: Sodium chloride, also known as salt, common salt, table salt or halite, is an ionic compound with the chemical formula NaCl, representing equal proportions of sodium and chlorine. In the form of table salt, it is commonly used as a condiment and food preservative.

Description : What product is formed when electricity is passed throughan aqueous solution of sodium chloride? (1) Sodium and water (2) Sodium oxide (3) Sodium and chlorine (4) Sodium hydroxide

Last Answer : (4) Sodium hydroxide Explanation: When electricity is passed through an aqueous solution of sodium chloride, it gives hydrogen, chlorine and sodium hydroxide as a product.

Description : Tear gas is – (1) Chloroprene (2) Carbonyl chloride (3) Nitrous oxide (4) Bleaching powder

Last Answer : (2) Carbonyl chloride Explanation: Tear gas, formally known as a lachrymatory agent or ladnymator (from lacrima meaning "tear" in Latin), is a non-lethal chemical weapon that ... temporary blindness, etc. Lachrymators are thought to act by attacking sulphydryl functional groups in enzymes.

Description : Write balanced chemical equations for the following word equations: (a) Iron + Chlorine → Iron (III) chloride (b) Magnesium + dil sulphuric acid → Magnesium sulphate + water (c) Magnesium + oxygen → ... oxide (d) Calcium oxide + water → Calcium hydroxide (e) Sodium + chlorine → Sodium chloride

Last Answer : (a) Iron + Chlorine → Iron (III) chloride 4Fe + 3Cl2 → 2F2Cl3 (b) Magnesium + dil sulphuric acid → Magnesium sulphate + water 2Mg + 2H2SO4 → 2MgSO4 + 2H2 (c) Magnesium + oxygen → Magnesium oxide 2Mg ... hydroxide CaO + H2O → Ca(OH)2 (e) Sodium + chlorine → Sodium chloride 2Na + Cl2 → 2NaCl

Description : The chemical name of Bleaching powder is (A)Calcium Chloride (B) Calcium Chloro-Oxide (C) Calcium Oxychloride (D) Hypochloride

Last Answer : (C) Calcium Oxychloride

Description : Thermal pyrolysis of ethylene dichloride produces (A) Trichloroethylene (B) Vinyl chloride (C) Ethanol amine (D) Ethylene oxide

Last Answer : (B) Vinyl chloride

Description : Setting time of cement increases by adding (A) Gypsum (B) Hydrogen peroxide (C) Calcium chloride (D) Sodium oxide

Last Answer : Answer: Option A

Description : Setting time of cement increases by adding (i)gypsum (ii)sodium oxide (iii)calcium chloride [ A ] i [ B ] i and ii [ C ] i and iii [ D ] i, ii and iii

Last Answer : [ A ] i

Description : Which of the following is produced when polyvinyl chloride is burned? w) Hydrogen Cyanide x) Hydrogen Chloride y) Nitrogen Oxide z) Oxygen

Last Answer : ANSWER: X -- HYDROGEN CHLORIDE 

Description : Chemical name of common salt is (1) Sodium Chloride (2) Sodium Bicarbonate (3) Sodium (4) Sodium Oxide

Last Answer : Sodium Chloride

Description : Tear gas is : (1) Chloroprene (2) Carbonyl chloride (3) Nitrous oxide (4) Bleaching powder

Last Answer : Carbonyl chloride

Description : Which can be converted to inferred equivalent CNF sentence? a) Every sentence of propositional logic b) Every sentence of inference c) Every sentence of first-order logic d) All of the mentioned

Last Answer : c) Every sentence of first-order logic

Description : The first law of thermodynamics may be expressed in the following equivalent  a. the net heat transfer id equal to the network  b. the sum of the total energy forms leaving the system boundary is ... neither be created nor destroyed but only converted from one form to another  d. all of the above

Last Answer : all of the above

Description : Determine the equivalent weight of the following ions : `(a) Na^(+) " " (b) Al^(3+) " " (c) NO^(+) " " Cl^(-)` `(e) CO_(3)^(2-) " " SO_(4)^(2-) " " (g

Last Answer : Determine the equivalent weight of the following ions : `(a) Na^(+) " " (b) Al^(3+) " " (c) NO^(+) " " Cl^(- ... " " SO_(4)^(2-) " " (g) PO_(4)^(3-)`

Description : A current of 4 amperes flowing for 45 minutes deposits 1.062 gm of metal at cathode. Calculate the equivalent weight of the metal. (Given 1 Faraday = 96500 C)

Last Answer : Given:  c : 4 amperes   t : 45 minutes : 45 x 60 = 2700 seconds   w : 1.062 gm   1 Faraday : 96500 C  To calculate: Eq. Weight (CE)  According to Faraday's first law:   w = z c t Therefore,  z = w / ct  ... g/c   Now, C.E. = 96500 x E.C.E.   C. E. = 96500 x 0.00009833  C.E. = 9.4888 gm

Description : In pentose phosphate pathway, D-ribulose5-phosphate is converted to D-ribose-5- phosphate by the enzyme: (A) Fumarase (B) Ketoisomerase (C) G-6-PD (D) Epimerase

Last Answer : Answer : B

Description : Two thick slices of bread, when completely oxidized by the body, can supply 200,000 cal of heat. How much work is this equivalent to?  a) 4,190,000 joules  b) 8,390,000 joules  c) 839, ... d) 419 000 joules Formula: J =Work/Heat J = mechanical equivalent of heat whose value is 4.19 joules/calorie

Last Answer : 419 000 joules

Description : During phototransduction: a. hyperpolarisation occurs due to closure of the sodium channels b. 11-cis-retinal molecules are converted to all-trans-retinal c. transducin, a G protein converts GDP to GTP d. all above

Last Answer : all above

Description : Statement -1 : Ores are generally converted into oxides , prior to reduction . Statement- 2 : Metal oxides can be easily reduced .

Last Answer : Statement -1 : Ores are generally converted into oxides , prior to reduction . Statement- 2 : Metal oxides ... -1 : is false , statement-2 : is true

Description : In which of the following method of purification metal is converted to its volatile compound which is decomposed to give pure metal?

Last Answer : In which of the following method of purification metal is converted to its volatile compound ... Heating with iodine C. Liquidation D. Distillation

Description : Thorium can be converted into U-233 in a __________ reactor. (A) Liquid metal cooled (B) Fast breeder (C) Thermal (D) Swimming pool

Last Answer : (B) Fast breeder

Description : During pudding (A) Molten metal is kept clear of the fuel (B) Carbon is converted into carbonic acid gas (C) Silicon forms a slag (D) All the above

Last Answer : Answer: Option D

Description : A solution containing 2.675 g of `CoCl_(3).6NH_(3)` (molar mass `= 267.5 g mol^(-1)`) is passed through a cation exchanger. The chloride ions obtained

Last Answer : A solution containing 2.675 g of `CoCl_(3).6NH_(3)` (molar mass `= 267.5 g mol^(-1)`) is passed through a ... _(3)]` D. `[CoCl(NH_(3))_(5)]Cl_(2)`

Description : The formation of the oxide `M_(x)O_(y)`per mole of `O_(2)` cinsumed is written a `(2x)/(y)M_((S))+O_(2(g))to(2)/(y)M_(x)O_(y)` the free energy change

Last Answer : The formation of the oxide `M_(x)O_(y)`per mole of `O_(2)` cinsumed is written ... from the following two reactions. Choose the correct statement