Given that - `2C(s)+2O_(2)(g)rarr 2CO_(2)(g) Delta H = -787 KJ` `H_(2)(g)+ 1//2O_(2)(g)rarr H_(2)O(l) Delta =-286 KJ` `C_(2)H_(2)(g)+(5)/(2)O_(2)(g)ra

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Answer :

Given that - `2C(s)+2O_(2)(g)rarr 2CO_(2)(g) Delta H = -787 KJ` `H_(2)(g)+ 1//2O_(2)(g)rarr H_(2) ... 1802` KJ B. `-1802` KJ C. `-800` KJ D. `+237` KJ

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