The polynomial, `sqrt(3)x^(2) + 2x +1` is a `"______"` expression.

1 Answer

Answer :

The polynomial, `sqrt(3)x^(2) + 2x +1` is a `"______"` expression.

Related questions

Description : Zero of the polynomial p(x)=2x+5 is -Maths 9th

Last Answer : (b) Given, p(x) = 2x+5 For zero of the polynomial, put p(x) = 0 ∴ 2x + 5 = 0 ⇒ -5/2 Hence, zero of the polynomial p(x) is -5/2.

Description : Zero of the polynomial p(x)=2x+5 is -Maths 9th

Last Answer : (b) Given, p(x) = 2x+5 For zero of the polynomial, put p(x) = 0 ∴ 2x + 5 = 0 ⇒ -5/2 Hence, zero of the polynomial p(x) is -5/2.

Description : Find the value of k if (x-2)is a factor of polynomial p(x) = 2x(cube) - 6x(square) + 5x + k. -Maths 9th

Last Answer : Solution :-

Description : Check whether polynomial p(x) = 2x(cube) - 9x(square) + x + 12 is a multiple of 2x-3 or not. -Maths 9th

Last Answer : Solution :-

Description : Find the value of the polynomial p(x) = x^3-3x^2-2x+6 at x = underroot 2 -Maths 9th

Last Answer : In this chapter, we shall proceed with recalling some of the constructions already learnt in the earlier classes and deal with some more. Here in this section, we will construct some of these ... be done? 2. Always explain the construction. Write the sequence of steps that are actually taken.

Description : f(x) = x^4 – 2x^3 + 3x^2 – ax + b is a polynomial such that when it is divided by (x – 1) and (x + 1), the remainders are respectively 5 and 19. -Maths 9th

Last Answer : answer:

Description : If the sum of the zeroes of the polynomial p(x) = (k2 – 14) x2 – 2x – 12 is 1, then find the value of k. -Maths 9th

Last Answer : p(x) = (k2 – 14) x2 – 2x – 12 Here a = k2 – 14, b = -2, c = -12 Sum of the zeroes, (α + β) = 1 …[Given] ⇒ − = 1 ⇒ −(−2)2−14 = 1 ⇒ k2 – 14 = 2 ⇒ k2 = 16 ⇒ k = ±4

Description : The value of quadratic polynomial f (x) = 2x 2 – 3x- 2 at x = -2 is ...... (a) 12 (b) 15 (c) -12 (d) 16

Last Answer : (a) 12

Description : `int_(1)^(2) (x)/(sqrt(1+2x^(2)))dx`

Last Answer : `int_(1)^(2) (x)/(sqrt(1+2x^(2)))dx`

Description : `int_(0)^(1) (x sin^(-1)x)/(sqrt(1+2x)^(2))dx`

Last Answer : `int_(0)^(1) (x sin^(-1)x)/(sqrt(1+2x)^(2))dx`

Description : `int(2x+5)/(sqrt(x^(2)+3x+1))dx`

Last Answer : `int(2x+5)/(sqrt(x^(2)+3x+1))dx`

Description : `int(x+1)/(sqrt(2x^(2)+x-3))dx`

Last Answer : `int(x+1)/(sqrt(2x^(2)+x-3))dx`

Description : Evaluate: `int(2x+5)/(sqrt(x^2+2x+5)) dx`

Last Answer : Evaluate: `int(2x+5)/(sqrt(x^2+2x+5)) dx`

Description : Evaluate: `int(2x-5)sqrt(2+3x-x^2)dx`

Last Answer : Evaluate: `int(2x-5)sqrt(2+3x-x^2)dx`

Description : Evaluate: (i) `int(e^x)/(sqrt(4-e^(2x))) dx` (ii) `int(x^2)/(sqrt(1-x^6)) dx`

Last Answer : Evaluate: (i) `int(e^x)/(sqrt(4-e^(2x))) dx` (ii) `int(x^2)/(sqrt(1-x^6)) dx`

Description : `int(2x-1)/(sqrt(x^(2)-x-1))dx`

Last Answer : `int(2x-1)/(sqrt(x^(2)-x-1))dx`

Description : `int (x^(2) +2x -5)/(sqrt(x))dx`

Last Answer : `int (x^(2) +2x -5)/(sqrt(x))dx`

Description : `lim_(x rarr 1) (sqrt(x+1)-sqrt(5x-3))/(sqrt(2x+3)-sqrt(4x+1))=`_________.

Last Answer : `lim_(x rarr 1) (sqrt(x+1)-sqrt(5x-3))/(sqrt(2x+3)-sqrt(4x+1))=`_________.

Description : If `f(x)={x}+{x+[(x)/(1+x^(2))]}+{x+[(x)/(1+2x^(2))]}+{x+[(x)/(1+3x^(2))]}.......+{x+[(x)/(1+99x^(2))]}`, then values of `[f(sqrt(3))]` is where `[*]`

Last Answer : If `f(x)={x}+{x+[(x)/(1+x^(2))]}+{x+[(x)/(1+2x^(2))]}+{x+[(x)/(1+3x^(2))]} ... represent fractional part function) A. `5050` B. `4950` C. `17` D. `73`

Description : Solve the following inequlities `(i) sqrt(x-1) lt x-3` `(ii) sqrt(x-3) gt sqrt(7-x)` `(iii) sqrt (x^(2)+4x+9) gt x +2` `(iv) 4-x lt sqrt(2x-x^(2))` `(

Last Answer : Solve the following inequlities `(i) sqrt(x-1) lt x-3` `(ii) sqrt(x-3) gt sqrt(7-x)` `(iii) sqrt (x^(2)+4x+ ... (ix) (|x+2|-|x|)/(sqrt(8-x^(3))) ge 0`

Description : Show that 2x+1 is a factor of polynomial 2x(cube) - 11x(square) - 4x + 1. -Maths 9th

Last Answer : Solution :-

Description : `" if " int (sin 2x- cos 2x) dx=(1)/(sqrt(2)) sin (2x-k)+c " then " k=?`

Last Answer : `" if " int (sin 2x- cos 2x) dx=(1)/(sqrt(2)) sin (2x-k)+c " then " k=?` A. `-(5pi)/(4)` B. `(pi)/(4)` C. `-(pi)/(4)` D.

Description : `int_(0)^(pi//2) sqrt(1- cos 2x) dx`

Last Answer : `int_(0)^(pi//2) sqrt(1- cos 2x) dx`

Description : `int_(0)^(pi//2) sqrt(1- cos 2x) dx`

Last Answer : `int_(0)^(pi//2) sqrt(1- cos 2x) dx`

Description : `int_(0)^(pi//6) sqrt(1-sin 2x) dx`

Last Answer : `int_(0)^(pi//6) sqrt(1-sin 2x) dx`

Description : `int(1)/(sqrt(2x^(2)+3x-2))dx`

Last Answer : `int(1)/(sqrt(2x^(2)+3x-2))dx`

Description : `int(1)/(sqrt(1+cos 2x))dx`

Last Answer : `int(1)/(sqrt(1+cos 2x))dx`

Description : `int sqrt(2x-1) dx`

Last Answer : `int sqrt(2x-1) dx`

Description : If the expression (px^3 + x^2 – 2x – q) is divisible by (x – 1) and (x + 1), then the values of p and q respectively are ? -Maths 9th

Last Answer : Let f(x)=px3+x2−2x−q Since f(x) is divisible by (x−1) and (x+1) so x=1 and −1 must make f(x)=0. Therefore, p+1−2−q=0, i.e., p−q=1; and −p+1+2−q=0, i.e., p+q=3 Thus p=2 and q=1

Description : If `lim_(x rarr 0) [(2x^(2)+3x+b)/(x^(2)+4x+3)]=2`, then the value of b is ______.

Last Answer : If `lim_(x rarr 0) [(2x^(2)+3x+b)/(x^(2)+4x+3)]=2`, then the value of b is ______.

Description : The roots of the equation `2x^(2) + 3x + c = 0` (where `x lt 0`) could be `"______"`.

Last Answer : The roots of the equation `2x^(2) + 3x + c = 0` (where `x lt 0`) could be `"______"`.

Description : If `2x -3 = 13`, then x = ______

Last Answer : If `2x -3 = 13`, then x = ______

Description : What is 2x plus 8y use the greatest common factor and the distributive property to write equivalent expression factored form?

Last Answer : Does it look like I fing care Jesus

Description : What is an equivalent expression to 8 plus 7y plus 2x plus 4y plus 4?

Last Answer : Feel Free to Answer

Description : What are two phrases for the expression 110 divided by 2x?

Last Answer : 55

Description : How many terms are in the expression 2x 8 - 2y 1?

Last Answer : A term can be a signed number, a variable, or a constant multiplied by a variable or variables. Each term in an algebraic expression is separated by a + sign or J sign. In , the terms are ... term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.

Description : For the equation `2x^(2) - 3x + 5 = 0` sum of the roots is `"______"`.

Last Answer : For the equation `2x^(2) - 3x + 5 = 0` sum of the roots is `"______"`.

Description : If the equation `3x^(2) - 2x-3 = 0`has roots `alpha`, and `beta` then `alpha.beta = "______"`.

Last Answer : If the equation `3x^(2) - 2x-3 = 0`has roots `alpha`, and `beta` then `alpha.beta = "______"`.

Description : Determine the remainder when polynomial p(x) is divided by x - 2 . -Maths 9th

Last Answer : p(x) = x4 - 3x2 + 2x - 5 According to remainder theorem, the required remainder will be = p(2) p(x) = x4 - 3x2 + 2x - 5 ∴ p(2) = 24 - 3(2)2 + 2(2) - 5 =16 - 12 + 4 - 5 = 3

Description : The value of the polynomial 5x – 4x2 + 3, when x = -1 is -Maths 9th

Last Answer : (a) Let p (x) = 5x – 4x2 + 3 …(i) On putting x = -1 in Eq. (i), we get p(-1) = 5(-1) -4(-1)2 + 3= - 5 - 4 + 3 = -6

Description : If x + 1 is a factor of the polynomial 2x2 + kx, then the value of k is -Maths 9th

Last Answer : (c) Let p(x) = 2x2 + kx Since, (x + 1) is a factor of p(x), then p(-1)=0 2(-1)2 + k(-1) = 0 ⇒ 2-k = 0 ⇒ k= 2 Hence, the value of k is 2.

Description : x + 1 is a factor of the polynomial -Maths 9th

Last Answer : (b) Let assume (x + 1) is a factor of x3 + x2 + x+1. So, x = -1 is zero of x3 + x2 + x+1 (-1)3 + (-1)2 + (-1) + 1 = 0 ⇒ -1+1-1 + 1 = 0 ⇒ 0 = 0 Hence, our assumption is true.

Description : Find the value of the polynomial 3x3 – 4x2 + 7x – 5, when x = 3 and also when x = -3. -Maths 9th

Last Answer : Let p(x) =3x3 – 4x2 + 7x – 5 At x= 3, p(3) = 3(3)3 – 4(3)2 + 7(3) – 5 = 3×27-4×9 + 21-5 = 81-36+21-5 P( 3) =61 At x = -3, p(-3)= 3(-3)3 – 4(-3)2 + 7(-3)- 5 = 3(-27)-4×9-21-5 = -81-36-21-5 = -143 p(-3) = -143 Hence, the value of the given polynomial at x = 3 and x = -3 are 61 and -143, respectively.

Description : Find the zeroes of the polynomial p(x)= (x – 2)2 – (x+ 2)2. -Maths 9th

Last Answer : Given, polynomial is p(x) = (x – 2)2 – (x+ 2)2 For zeroes of polynomial, put p(x) = 0 (x – 2)2 – (x+ 2)2 = 0 (x-2 + x+2)(x-2-x-2) = 0 [using identity, a2-b2 =(a-b)(a + b)] ⇒ (2x)(-4) = 0

Description : By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial x4 + 1 and x-1. -Maths 9th

Last Answer : Actual division method

Description : Determine which of the following polynomial has x – 2 a factor -Maths 9th

Last Answer : first option is the correct answer for the given question solution is as follows:- let x-2=0 then, x=2 put x in (i) 3(2)(2)+6(2)-24=0 12+12-24=0 {use BODMAS rule for solution}... 24-24=0 0=0 this verifies our answer

Description : The polynomial p{x = x4 -2x3 + 3x2 -ax+3a-7 when divided by x+1 leaves the remainder 19. -Maths 9th

Last Answer : p(x) is divided by x+ 2 =

Description : Determine the remainder when polynomial p(x) is divided by x - 2 . -Maths 9th

Last Answer : p(x) = x4 - 3x2 + 2x - 5 According to remainder theorem, the required remainder will be = p(2) p(x) = x4 - 3x2 + 2x - 5 ∴ p(2) = 24 - 3(2)2 + 2(2) - 5 =16 - 12 + 4 - 5 = 3

Description : The value of the polynomial 5x – 4x2 + 3, when x = -1 is -Maths 9th

Last Answer : (a) Let p (x) = 5x – 4x2 + 3 …(i) On putting x = -1 in Eq. (i), we get p(-1) = 5(-1) -4(-1)2 + 3= - 5 - 4 + 3 = -6

Description : If x + 1 is a factor of the polynomial 2x2 + kx, then the value of k is -Maths 9th

Last Answer : (c) Let p(x) = 2x2 + kx Since, (x + 1) is a factor of p(x), then p(-1)=0 2(-1)2 + k(-1) = 0 ⇒ 2-k = 0 ⇒ k= 2 Hence, the value of k is 2.