If the roots of a quadratic equation `ax^(2) + bx + c` are complex, then `b^(2) lt "____"`

If the roots of a quadratic equation `ax^(2) + bx + c` are complex, then `b^(2) lt "____"`
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If the roots of a quadratic equation `ax^(2) + bx + c` are complex, then `b^(2) lt "____"`
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The roots of a quadratic equation `ax^(2) + bx + c=0` are 1 and `c/a`, then `a + b = "_____"`.

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In quadratic equation ax^2 + bx + c = 0 , Identities the sum and product of Roots? -Maths 9th

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Last Answer : If the two roots of the quadratic equation ax2 + bx + c = 0 obtained by the quadratic formula be denoted by a and b, then we have α = \(\frac{-b+\sqrt{b^2-4ac}}{2a},\) β = \(\frac{-b-\sqrt{b^2-4ac}}{2a}\) ∴ Sum of roots ... then α + β = - (- \(\frac{5}{6}\)) = \(\frac{5}{6}\), ab = \(\frac{7}{6}\).

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In triangle ABC, angle B =35° , angle C =65° and the bisector of angle BAC meets BC in X. Arrange AX, BX and CX in descending order. -Maths 9th

Description : In triangle ABC, angle B =35° , angle C =65° and the bisector of angle BAC meets BC in X. Arrange AX, BX and CX in descending order. -Maths 9th

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In triangle ABC, angle B =35° , angle C =65° and the bisector of angle BAC meets BC in X. Arrange AX, BX and CX in descending order. -Maths 9th

Description : In triangle ABC, angle B =35° , angle C =65° and the bisector of angle BAC meets BC in X. Arrange AX, BX and CX in descending order. -Maths 9th

Last Answer : This answer was deleted by our moderators...

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If the expression ax^2 + bx + c is equal to 4, when x = 0, leaves a remainder 4 when divided by x + 1 and leaves a -Maths 9th

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Last Answer : Solution:- x - 1 = 0 x = 1 Let p(x) = Ax³ + Bx² - 36x + 22 p(1) = A(1)³ + B(1)² - (36 × 1) + 22 ⇒ A + B - 36 + 22 =0 ⇒ A + B - 14 = 0 ⇒ A + B = 14 ....... ... 22 p(1) = 2(1)³ + 12(1)² - (36 × 1) + 22 ⇒ 2 + 12 - 36 + 22 ⇒ 36 - 36 = 0

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Description : The values of a, b and c respectively for the expression f(x) = x^3 + ax^2 + bx + c, if f(1) = f(2) = 0 and f(4) = f(0) are : -Maths 9th

Last Answer : f′(x)=3x2+2ax+6 f(x)⇒f′(x)≥0 3x2+2ax+6≥0 ⇒D≤0 4[a2−3b]≤0 a2≤3b ∴P=6×6×6(16)×6​=3616​=94​ Answer.

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Last Answer : Let p(x) = ax³ + bx² + x - 6 A/C to question, (x + 2) is the factor of p(x) , and we know this is possible only when p(-2) = 0 So, p(2) = a(-2)³ + b(-2)² - 2 - 6 = 0 ⇒ ... --(2) solve equations (1) and (2), 4a = 0 ⇒a = 0 and b = 2 Then, equation will be 2x² + x - 6

3a plus 3b plus ax plus bx?

Description : 3a plus 3b plus ax plus bx?

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Description : What is the output of the following code AL= -28 decimal, BL=59 decimal IMUL BL AX=? , MSB=? a) AX= F98CH, MSB=1. b) AX= 1652, MSB=1. c) BX F9C8H, MSB=1. d) BX= 1652, MSB=1.

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Let p and q be the roots of the quadratic equation x^2 – (a – 2)x – a – 1 = 0. What is the minimum possible value of p^2 + q^2 ? -Maths 9th

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The quadratic equation `x^2-1088x+295680=0` has two positive integral roots whose greatest common divisor is 16. The least common multiple of the two

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For which value of `p` among the following, does the quadratic equation `3x^(2) + px + 1 = 0` have real roots ?

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