Which substance is used as antiknock compound? -Do You Know?

Which substance is used as antiknock compound? -Do You Know?
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An anti-knocking agent is the substance which is used to reduce the engine knocking. It increases the octane number of the fuel. It helps in auto-ignition by raising the temperature and pressure. TEL is tetraethyl Lead which is used as an Anti-Knocking compound.
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Related questions

Which substance is used as antiknock compound? —

Description : Which substance is used as antiknock compound? —

Last Answer : TEL

Tetra ethyle lead (TEL) is - (1) a catalyst in burning fossil fuel (2) an antioxidant (3) areductant (4) an antiknock compound

Description : Tetra ethyle lead (TEL) is - (1) a catalyst in burning fossil fuel (2) an antioxidant (3) areductant (4) an antiknock compound

Last Answer : (4) an antiknock compound Explanation: Tetraethyl lead was extensively used as an additive to gasoline, wherein it served as an effective antiknock agent and prevented exhaust valve and seat wear. ... needed. Typical formulations called for 1 part of prepared TEL to 1260 parts untreated gasoline.

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Last Answer : Tetraethyllead

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Last Answer :  an antiknock compound

An antiknock for petrol is - (1) sodium hydroxide (2) ethanol (3) sodium benzoate (4) lead tetraethyl

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Last Answer : (4) lead tetraethyl Explanation: The organic compound that is used as an antiknock agent in petroleum is tetraethyl lead. This is a lead based organic compound.

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Last Answer : its antiknock properties

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Last Answer : Answer: C

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Description : 0.257g of organic substance was heated with conc. sulphuric acid and then distilled with excess of strong alkali .the ammonia gas evolved was absorbed in 50ml of .1M HCl which required 23.2ml of c for neutralization at the end of the process. Determine the % of nitrogen in the compound ?

Last Answer : A. Vol of 0 .1M HCl taken = 50ml Vol of .1MNaOH used for neutralization of unused acid=23.2ml Now, 23.2 ml of .1MNaOH =23.2ml of .1MHCl Vol of .1MHCl unused=23.2ml Vol of .1MHCl required ... NH3 solution contain nitrogen = 14*26.8/10*1000 Percentage of Nitrogen=14*26.8*100/10*1000*.257 =14.6%

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