A die is rolled three times. The probability of getting a larger number than the previous number each time is: -Maths 9th

A die is rolled three times. The probability of getting a larger number than the previous number each time is: -Maths 9th
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1 Answer

Answer :

(b) \(rac{5}{24}\)Total number of ways three die can be rolled = 6 × 6 × 6 = 216 A larger number than the previous number can be got in the three throws as (1, 2, 3), (1, 2, 4), (1, 2, 5) (1, 2, 6), (1, 3, 4), (1, 3, 5) (1, 3, 6), (1, 4, 5) (1, 4, 6) (1, 5, 6) (2, 3, 4), (2, 3, 5), (2, 3, 6) (2, 4, 5), (2, 4, 6), (2, 5, 6), (3, 4, 5), (3, 4, 6) (3, 5, 6), (4, 5, 6). ∴ Total number of favourable cases = 20∴ Required probability =\(rac{20}{216}\) = \(rac{5}{24}\).
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Related questions

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Description : Now it was Ravi‘s turn. He rolled the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is greater than 8? a. 1 b. 5/36 c. 1/18 d. 5/18

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Description : A die is thrown six times and number on it is noted as given below : -Maths 9th

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Description : A die is thrown six times and number on it is noted as given below : -Maths 9th

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Description : Can the experimental probability of an event be a negative number? -Maths 9th

Last Answer : No, because the number of trials in which the event can happen cannot be negative and the total number of trials is always positive.

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