If log2 [log7(x^2 – x + 37)] = 1, then what could be the value of x ? -Maths 9th

If log2 [log7(x^2 – x + 37)] = 1, then what could be the value of x ? -Maths 9th
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Answer :

(c) 4log2 [log7(x2 – x + 37)] = 1 ⇒ log7(x2 – x + 37) = 21 = 2 ⇒ x2 – x + 37 = 72 = 49 ⇒ x2 – x – 12 = 0 Now solve for x.
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