A sphere and a right circular cylinder -Maths 9th

A sphere and a right circular cylinder -Maths 9th
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Let the radius of sphere and cylinder be r and h be the height of cylinder. Then according to the question.  Volume of sphere = Volume of cylinder ⇒ 4/3πr3 = πr2h   ⇒ r = 3/4.h Diameter of the cylinder = 3/2.h Difference between the diameter and height of the cylinder = 3/2h - h = h/2 Percentage by which the diameter exceeds the height of cylinder  =  h/2/h x 100 = h/2 x 1/h x 100 = 50% Thus, the diameter of the cylinder exceeds its height by 50%.
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