Radius of the sphere (r1) = 5 cm Radius of the base of cone (r2) = 4 cm Let r сm be the height of the cone. Surface area of sphere = 4 πr2 ⇒ 4 π(5)2 = 100 π cm2 Curved surface area of cone = πrl = 4 πl cm2 where l is the slant height of the cone. According to the statement, 100 π = 5(4 πl) ⇒ l = 5 cm Now, h2 = l2 - r2 = 52 – 42 = 32 ⇒ h = 3 cm ∴ Volume of cone = 1/3 πr2h = 1/3 x 22/7 x 42 x 3 = 352/7 cm3 = 50.29 cm3 (Approximately)