Let a, b, c be the sides of the given triangle and s be its semi-perimeter. Then, s = (a + b + c)/2 ...(i) ∴ Area of the given triangle = root under ( √s(s - a)(s - b)(s - c)) = △, say According to the question, the sides of the new triangle will be 2a, 2b and 2c. Let s' be the semi-perimeter of the new triangle. s' = (2a + 2b + 2c)/2 = a + b + c ...(ii) From (i) and (ii), we get s' = 2s Area of new triangle = root under ( √ s' (s' - 2a)(s' - 2b)(s' - 2c)) = root under ( √2s(2s - 2a)(2s - 2b)(2s - 2c)) = root under ( √16s (s - a)(s - b)(s - c)) = 4 root under ( √ s(s - a)(s - b)(s - c)) = 4 △ Therefore, the required ratio is 4:1