The sides of a triangle are in the ratio of 3 : 4 : 5 and its perimeter is 510 m. What is the measure of its greatest side? -Maths 9th

The sides of a triangle are in the ratio of 3 : 4 : 5 and its perimeter is 510 m. What is the measure of its greatest side? -Maths 9th
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Let the sides of triangle be 3x,4x,5x Perimeter =3x + 4x + 5x=144 cm 12x=144 ∴x=12  Then sides of triangle are 3x=3×12=36 cm,  4x=4×12=48 cm,   5x=5×12=60 cm. Now, Semi perimeter, s=2 Sum of sides of triangle​=236+48+60​=72 cm Using Heron's formula, Area of triangle =s (s−a)(s−b)(s−c)​= 72(72−36)(72−48)(72−60)​= 72 × 36 × 24 × 12​ = 864 cm2
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Last Answer : Cost of painting =

A rhombus shaped sheet with perimeter 40 cm and one diagonal 12 cm, is painted on both sides at the rate of Rs. -Maths 9th

Description : A rhombus shaped sheet with perimeter 40 cm and one diagonal 12 cm, is painted on both sides at the rate of Rs. -Maths 9th

Last Answer : Cost of painting =