In a rectangular field of dimension 60 m x 50 m, -Maths 9th

In a rectangular field of dimension 60 m x 50 m, -Maths 9th
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Answer :

Area of rectangular field = length x breadth = 60 x 50 = 3,000 m2 Now, a = 50 m, b = 45 m, c = 35 m s = (a + b + c)/2 = (50 + 45 + 35)/2   = 130/2  = 65 m By Heron's formula : ∴  Area of triangle = root under(√s(s - a)(s - b)(s - c)) = root under(√65(65 - 50)(65 - 45)(65 - 35)  = root under(√65 x 15 x 20 x 30) = root under (√13 x 5 x 5 x 3 x 5 x 2 x 2 x 5 x 2 x 3)  = 5 x 5 x 3 x 2 (root under(√13 x 2))   = 150√26  =  764.85 m2 ( approximately ) Hence, the remaining area  = Area of rectangle - Area of triangle = 3,000 - 764.85   = 2,235.15 m2
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