Factorise: x3 +13x2 + 32x + 20. -Maths 9th

1 Answer

Answer :

Solution   :-

Related questions

Description : Using factor theorem, factorise the polynomial x3 + x2 - 4x - 4. -Maths 9th

Last Answer : Solution :-

Description : p(x)=x3+3x2+3x+1, g(x) = x+2 -Maths 9th

Last Answer : p(x) = x3+3x2+3x+1, g(x) = x+2 g(x) = 0 ⇒ x+2 = 0 ⇒ x = −2 ∴ Zero of g(x) is -2. Now, p(−2) = (−2)3+3(−2)2+3(−2)+1 = −8+12−6+1 = −1 ≠ 0 ∴By factor theorem, g(x) is not a factor of p(x

Description : Determine which of the following polynomials has (x + 1) a factor: (i) x3+x2+x+1 -Maths 9th

Last Answer : Solution: Let p(x) = x3+x2+x+1 The zero of x+1 is -1. [x+1 = 0 means x = -1] p(−1) = (−1)3+(−1)2+(−1)+1 = −1+1−1+1 = 0 ∴By factor theorem, x+1 is a factor of x3+x2+x+1

Description : Which of the following is a factor of (x+ y)3 – (x3 + y3) ? -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : Show that, x + 3 is a factor of 69 + 11c – x2 + x3 -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Last Answer : Let p(x) = x3 -2mx2 +16 Since, p(x) is divisible by (x+2), then remainder = 0 P(-2) = 0 ⇒ (-2)3 -2m(-2)2 + 16=0 ⇒ -8-8m+16=0 ⇒ 8 = 8 m m = 1 Hence, the value of m is 1 .

Description : Find the value of x3 +y3 -12xy + 64,when x+y = -4. -Maths 9th

Last Answer : Find the value of

Description : Which of the following is a factor of (x+ y)3 – (x3 + y3) ? -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : Show that, x + 3 is a factor of 69 + 11c – x2 + x3 -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : For what value of m is x3 -2mx2 +16 divisible by x + 2 ? -Maths 9th

Last Answer : Let p(x) = x3 -2mx2 +16 Since, p(x) is divisible by (x+2), then remainder = 0 P(-2) = 0 ⇒ (-2)3 -2m(-2)2 + 16=0 ⇒ -8-8m+16=0 ⇒ 8 = 8 m m = 1 Hence, the value of m is 1 .

Description : Find the value of x3 +y3 -12xy + 64,when x+y = -4. -Maths 9th

Last Answer : Find the value of

Description : p(x)=x3-2x2-4x-1, g(x)=x- -Maths 9th

Last Answer : NEED ANSWER

Description : p(x)=x3-2x2-4x-1, g(x)=x- -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : Find the value of x3-8y3-36xy-216 when x = 2y+6. -Maths 9th

Last Answer : Solution :-

Description : If x2 + 1/x2 = 34, find x3 + 1/x3 - 9. -Maths 9th

Last Answer : Solution :-

Description : If x-2 is a factor of x3-3x+5a then find the value of a -Maths 9th

Last Answer : -2/5 is value of a

Description : If x-2 is a factor of x3-3x+5a then find the value of a -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : factorize x3-2x2-x+2 -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : Find the value of x3+y3+12xy-64 when x=4 -Maths 9th

Last Answer : On the value of x we put the value 4 When it is in power 64+y3+12x4y-64 64+y3+48y-64 64-64+y3+48y 0+y(y2+48) Y(y2+48)

Description : Find the value of x3 + y3 + z3 – 3xyz if x2 + y2 + z2 = 83 and x + y + z = 15 -Maths 9th

Last Answer : Consider the equation x + y + z = 15 From algebraic identities, we know that (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) So, (x + y + z)2 = x2 + y2 + z2 + 2(xy + yz + xz) From the question, x2 + y2 + z2 ... y3 + z3 - 3xyz = 15(83 - 71) => x3 + y3 + z3 - 3xyz = 15 12 Or, x3 + y3 + z3 - 3xyz = 180

Description : x^4+x^2+25 factorise this -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : Factorise each of the following expressions: -Maths 9th

Last Answer : (i) 48x3 - 36x2 = 12.4 x2 x - 12.3x2 = 12x2 (4x - 3) (ii) 5x2 - 15xy = 5x (x-3y) (iii) 15x3y2z - 25xy2z3 = 5xy2z(3x2 - 5z2)

Description : Factorise this question -Maths 9th

Last Answer : (i) The greatest monomial that is a common factor of the three terms is 6xy. ∴ 30x3y + 24x2y2 - 6xy = 6xy (5x2 + 4xy - 1) (ii) Here the polynomial (a-b) is a common factor. ∴ 5x(a-b) + 6y(a-b) = (a-b) (5x + 6y)

Description : Factorise this question -Maths 9th

Last Answer : (i) 7a3 + 7a - 2a2 - 2 = 7a(a2 + 1) - 2 (a2 + 1) = (a2 + 1) (7a - 2) (ii) The term of 4ax + 3by - 3ay - 4bx can be rearranged and factorized . 4ax - 4bx - 3ay + 3by = 4x(a-b) - 3y(a-b) = (a-b) (4x - 3y) (iii) x3 + y3 + x2y + xy2 = x3 + x2y + xy2 + y3 = x2(x+y) + y2 (x+y) = (x+y) (x2+y2)

Description : Factorise this question -Maths 9th

Last Answer : (i) 9x2 + 30xy + 25y2 = (3x2 + 2(3x) (5y) + (5y)2 = (3x + 5y)2 (ii) 9x2 - 30xy + 25y2 = (3x)2 - 2(3x) (5y) + 5y2 = (3x - 5y)2

Description : Factorise : x2 + 9x +18 -Maths 9th

Last Answer : Factorisation

Description : Factorise : 2x3 -3x2 -17x + 30 -Maths 9th

Last Answer : Factorisation of following

Description : Factorise the following : 9x2 -12x+ 3 -Maths 9th

Last Answer : Factorise the following :

Description : Factorise the following : 9x2 +4y2 + 16z2 +12xy-16yz -24xz -Maths 9th

Last Answer : Factorise the following

Description : Factorise the following -Maths 9th

Last Answer : Factorise the following

Description : Factorise : 1 + 64x3 -Maths 9th

Last Answer : Factorisation

Description : Factorise: a3 -8b3 -64c3 -24abc -Maths 9th

Last Answer : Factorisation

Description : Without finding the cubes, factorise (x- 2y)3 + (2y – 3z)3 + (3z – x)3. -Maths 9th

Last Answer : We know that, a3 + b3 + c3 – 3 abc = (a + b + c)(a2 + b2 + c2 -ab-bc-ca) Also, if a + b + c = 0, then a3 + b3 + c3 = 3abc Here, we see that (x-2y) +(2y-3z)+ (3z-x) = 0 Therefore, (x-2y)3 + (2y-3z)3 + (3z-x)3 = 3(x-2y)(2y-3z)(3z-x).

Description : x^4+x^2+25 factorise this -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : Factorise each of the following expressions: -Maths 9th

Last Answer : (i) 48x3 - 36x2 = 12.4 x2 x - 12.3x2 = 12x2 (4x - 3) (ii) 5x2 - 15xy = 5x (x-3y) (iii) 15x3y2z - 25xy2z3 = 5xy2z(3x2 - 5z2)

Description : Factorise this question -Maths 9th

Last Answer : (i) The greatest monomial that is a common factor of the three terms is 6xy. ∴ 30x3y + 24x2y2 - 6xy = 6xy (5x2 + 4xy - 1) (ii) Here the polynomial (a-b) is a common factor. ∴ 5x(a-b) + 6y(a-b) = (a-b) (5x + 6y)

Description : Factorise this question -Maths 9th

Last Answer : (i) 7a3 + 7a - 2a2 - 2 = 7a(a2 + 1) - 2 (a2 + 1) = (a2 + 1) (7a - 2) (ii) The term of 4ax + 3by - 3ay - 4bx can be rearranged and factorized . 4ax - 4bx - 3ay + 3by = 4x(a-b) - 3y(a-b) = (a-b) (4x - 3y) (iii) x3 + y3 + x2y + xy2 = x3 + x2y + xy2 + y3 = x2(x+y) + y2 (x+y) = (x+y) (x2+y2)

Description : Factorise this question -Maths 9th

Last Answer : (i) 9x2 + 30xy + 25y2 = (3x2 + 2(3x) (5y) + (5y)2 = (3x + 5y)2 (ii) 9x2 - 30xy + 25y2 = (3x)2 - 2(3x) (5y) + 5y2 = (3x - 5y)2

Description : Factorise : x2 + 9x +18 -Maths 9th

Last Answer : Factorisation

Description : Factorise : 2x3 -3x2 -17x + 30 -Maths 9th

Last Answer : Factorisation of following

Description : Factorise the following : 9x2 -12x+ 3 -Maths 9th

Last Answer : Factorise the following :

Description : Factorise the following : 9x2 +4y2 + 16z2 +12xy-16yz -24xz -Maths 9th

Last Answer : Factorise the following

Description : Factorise the following -Maths 9th

Last Answer : Factorise the following

Description : Factorise : 1 + 64x3 -Maths 9th

Last Answer : Factorisation

Description : Factorise: a3 -8b3 -64c3 -24abc -Maths 9th

Last Answer : Factorisation

Description : Without finding the cubes, factorise (x- 2y)3 + (2y – 3z)3 + (3z – x)3. -Maths 9th

Last Answer : We know that, a3 + b3 + c3 – 3 abc = (a + b + c)(a2 + b2 + c2 -ab-bc-ca) Also, if a + b + c = 0, then a3 + b3 + c3 = 3abc Here, we see that (x-2y) +(2y-3z)+ (3z-x) = 0 Therefore, (x-2y)3 + (2y-3z)3 + (3z-x)3 = 3(x-2y)(2y-3z)(3z-x).

Description : factorise (x-2y)^3-(x+2y)^3 -Maths 9th

Last Answer : NEED ANSWER

Description : factorise the following 4x^2+20x+25 -Maths 9th

Last Answer : NEED ANSWER

Description : factorise (x-2y)^3-(x+2y)^3 -Maths 9th

Last Answer : Given ( x - 2y) 3 + (2y - 3z) 3 + ( 3z - x) 3 Let a = ( x - 2y), b =(2y - 3z), c= ( 3z - x) a + b + c = ( x - 2y)+(2y - 3z)+( 3z - x) = 0 Recall that if (a + b + c) = 0 then a 3 + b 3 + c 3 = 3abc Thus, ( x - 2y) 3 + (2y - 3z) 3 + ( 3z - x) 3 = 3( x - 2y)(2y - 3z)( 3z - x)

Description : factorise the following 4x^2+20x+25 -Maths 9th

Last Answer : 4x^2+20x+25 4x^2+10x+10x+25 2x(2x+5)+5(2x+5) (2x+5)(2x+5) 2x^2+2(2x)(5)+25 2x^2+20x+25