Description : Find p(0), p( 1) and p(-2) for the following polynomials -Maths 9th
Last Answer : (i) Given, polynomial is p(x) = 10x - 4x2 - 3 On putting x = 0,1 and - 2, respectively in Eq. (i), we get p(0) = 10(0)-4(0)2 -3 = 0-0-3= -3 p(1) = 10 (1) - 4 (1 )2 -3 = 10-4-3= 10-7= 3 and p(-2 ... = (-2 + 2)(-2 -2) =0 (-4) = 0 Hence, the values of p(0),p(1) and p(-2) are respectively,-4,-3 and 0.