if xylogxy/x+y, yzlogyz/y+z and zxlogzx/z+x are mutually equal, then show that x^x= y^y=z^z -Maths 9th

if xylogxy/x+y, yzlogyz/y+z and zxlogzx/z+x are mutually equal, then show that x^x= y^y=z^z -Maths 9th
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if xylogxy/x+y, yzlogyz/y+z and zxlogzx/z+x are mutually equal, then show that x^x= y^y=z^z -Maths 9th

Description : if xylogxy/x+y, yzlogyz/y+z and zxlogzx/z+x are mutually equal, then show that x^x= y^y=z^z -Maths 9th

Last Answer : NEED ANSWER

If x+y=10 and x=z then show that z+y=10 by using appropriate eculids axioms? -Maths 9th

Description : If x+y=10 and x=z then show that z+y=10 by using appropriate eculids axioms? -Maths 9th

Last Answer : This answer was deleted by our moderators...

If x+y =10 and x=z then show that z+y =10 -Maths 9th

Description : If x+y =10 and x=z then show that z+y =10 -Maths 9th

Last Answer : It is given that x+y =10 Also x= z Therefore, x+y =10 Z+y =10 ( x = z)

If x+y=10 and x=z then show that z+y=10 by using appropriate eculids axioms? -Maths 9th

Description : If x+y=10 and x=z then show that z+y=10 by using appropriate eculids axioms? -Maths 9th

Last Answer : This answer was deleted by our moderators...

If x+y =10 and x=z then show that z+y =10 -Maths 9th

Description : If x+y =10 and x=z then show that z+y =10 -Maths 9th

Last Answer : It is given that x+y =10 Also x= z Therefore, x+y =10 Z+y =10 ( x = z)

Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Description : Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Last Answer : NEED ANSWER

Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Description : Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th

Last Answer : According to question find the value of z

If (log x)/(l + m - 2n) = (log y)/(m + n - 2l) = (log z)/(n + l - 2m), then xyz is equal to : -Maths 9th

Description : If (log x)/(l + m - 2n) = (log y)/(m + n - 2l) = (log z)/(n + l - 2m), then xyz is equal to : -Maths 9th

Last Answer : Let l+m−2nlogx​=m+n−2llogy​=n+l−2mlogz​=k(say) So, we get logx=k(l+m−2n) ....... (i) logy=k(m+n−2l) ....... (ii) logz=k(n+l−2m) ....... (iii) ∴logx+logy+logz=k(l+m−2n)+k(m+n−2l)+k(n+l−2m) ⇒logx+logy+logz=kl+km−2kn+km+kn−2kl+kn+kl−2km ⇒log(xyz)=0 ⇒logxyz=log1 ⇒xyz=1

If (log x)/(l + m - 2n) = (log y)/(m + n - 2l) = (log z)/(n + l - 2m), then xyz is equal to : -Maths 9th

Description : If (log x)/(l + m - 2n) = (log y)/(m + n - 2l) = (log z)/(n + l - 2m), then xyz is equal to : -Maths 9th

Last Answer : (b) 1Let \(rac{ ext{log}\,x}{l+m-2n}\) = \(rac{ ext{log}\,y}{m+n-2l}\) = \(rac{ ext{log}\,z}{n+l-2m}\) = k. Thenlog x = k(l + m – 2n), log y = k(m + n – 2l); log z = k(n + l – 2m) ⇒ log x + log y + log z = k(l + m – 2n) + k(m + n – 2l) + k(n + l – 2m)⇒ log(xyz) = 0 ⇒ log(xyz) = log 1 ⇒ xyz = 1.

If x + y + z = 0, then what is [(y-z-x)/2]^3 + [(z-x-y)/2]^3 + [(x-y-z)/2]^3 equal to ? -Maths 9th

Description : If x + y + z = 0, then what is [(y-z-x)/2]^3 + [(z-x-y)/2]^3 + [(x-y-z)/2]^3 equal to ? -Maths 9th

Last Answer : answer:

If(1/(x+z))+(1/(z+x)) = (2/(x+y)), then what is ( x^2 + y^2) equal to ? -Maths 9th

Description : If(1/(x+z))+(1/(z+x)) = (2/(x+y)), then what is ( x^2 + y^2) equal to ? -Maths 9th

Last Answer : answer:

If a = (xy)/(x+y), b = (xz)/(x+z), and c = (yz)/(y+z), where a, b and c are non-zero, then what is x equal to ? -Maths 9th

Description : If a = (xy)/(x+y), b = (xz)/(x+z), and c = (yz)/(y+z), where a, b and c are non-zero, then what is x equal to ? -Maths 9th

Last Answer : answer:

If x + y + z = 2s, then what is (s – x)^3 + (s – y)^3 + 3(s – x) (s – y)z equal to : -Maths 9th

Description : If x + y + z = 2s, then what is (s – x)^3 + (s – y)^3 + 3(s – x) (s – y)z equal to : -Maths 9th

Last Answer : answer:

If x^(1/3) + y^(1/3) + z^(1/3) = 0, then what is (x + y + z)^3 equal to ? -Maths 9th

Description : If x^(1/3) + y^(1/3) + z^(1/3) = 0, then what is (x + y + z)^3 equal to ? -Maths 9th

Last Answer : answer:

Using factor theorem,show that (x-y) is a factor of x(y(square) - z(square)) + y(z(square) - x(square)) + z(x(square) - y(square) ) -Maths 9th

Description : Using factor theorem,show that (x-y) is a factor of x(y(square) - z(square)) + y(z(square) - x(square)) + z(x(square) - y(square) ) -Maths 9th

Last Answer : Solution :-

What do you mean by Mutually Exclusive Events? -Maths 9th

Description : What do you mean by Mutually Exclusive Events? -Maths 9th

Last Answer : The events are said to be mutually exclusive if they cannot occur simultaneously in a single draw. Events such as tossing a head or a tail with a coin, drawing a queen or a jack from a pack of cards, ... the card can be the king of spades. Similarly for B and C, the card can be king of hearts.

A and B are two mutually exclusive and exhaustive events with P(B) = 3P(A). What is the value of P (bar(B)) ? -Maths 9th

Description : A and B are two mutually exclusive and exhaustive events with P(B) = 3P(A). What is the value of P (bar(B)) ? -Maths 9th

Last Answer : (c) 43 : 34Given, odds against A = 8 : 3⇒ P(not A) = \(rac{8}{8+3}\) = \(rac{8}{11}\) ⇒ P(A happens) = \(rac{3}{11}\)Odds against B = 5 : 2⇒ P(not B) = \(rac{5}{5+2}\) = \(rac{5}{7}\) ⇒ P(B happens ... {43}{77}\)odds against C = \(rac{P(not\,c)}{P(c)}\) = \(rac{rac{43}{77}}{rac{34}{77}}\) = 43 : 34.

The medians AD and BE of the triangle with vertices A(0, b), B(0, 0) and C(a, 0) are mutually perpendicular if -Maths 9th

Description : The medians AD and BE of the triangle with vertices A(0, b), B(0, 0) and C(a, 0) are mutually perpendicular if -Maths 9th

Last Answer : (c) \(rac{b+k}{f+h}\)Let the slope of the lin passing through the points (-k, h) and (b, - f) be m1. Then m1 = \(rac{-f-h}{b+k}\) = \(-\bigg(rac{f+h}{b+k}\bigg)\)\(\bigg[Slope = rac{y_2-y_1}{x_2-x_1}\bigg]\) ... \(-rac{1}{m_1}\)= \(rac{-1}{-\big(rac{f+h}{b+k}\big)}\) = \(\bigg(rac{b+k}{f+h}\bigg)\)

It is known that if x+y =10, then x+y+z = 10+z.Which axiom of Euclids does this statement illustrate? -Maths 9th

Description : It is known that if x+y =10, then x+y+z = 10+z.Which axiom of Euclids does this statement illustrate? -Maths 9th

Last Answer : Solution :- Second axiom.

In Fig. 6.14, if x+y = w+z,then then prove that AOB is a line. -Maths 9th

Description : In Fig. 6.14, if x+y = w+z,then then prove that AOB is a line. -Maths 9th

Last Answer : Solution :-

If x = logabc, y = logbca, z = logc ab, then -Maths 9th

Description : If x = logabc, y = logbca, z = logc ab, then -Maths 9th

Last Answer : (a) x + y + z + 2 = xyz.x = logabc ⇒ ax = bc ⇒ ax + 1 = abc ⇒ a = (abc)1/(x +1) Similarly, b = (abc)1/(y + 1), c = (abc)1/(z + 1)∴ abc = \((abc)^{rac{1}{x+1}+rac{1}{y+1}+rac{1}{z+1}}\)⇒ \({rac{1}{x+1}+ ... + xz + x + z + 1 + xy + y + x + 1 = xyz + xy + yz + zx + x + y + z + 1⇒ x + y + z + 2 = xyz.

If y = (1/(a^(1-loga x))), z = (1/(a^(1-loga y))) and x = a^k, then k = -Maths 9th

Description : If y = (1/(a^(1-loga x))), z = (1/(a^(1-loga y))) and x = a^k, then k = -Maths 9th

Last Answer : (b) \(rac{1}{{1-log_az}}\) y = \(rac{1}{a^{1-log_ax}}\) = \(a^{-(1-log_ax)}\)⇒ logay = \(rac{1}{{1-log_ax}}\) and loga z = \(rac{1}{{1-log_ay}}\)∴ logaz = \(rac{1}{1-\bigg(rac{1}{1-log_ax}\bigg)}\) = \( ... x = \(rac{1}{{1-log_az}}\)⇒ x = \(a^{rac{1}{1-log_az}}\) = ak ⇒ k = \(rac{1}{{1-log_az}}\).

If (log x)/(a^2+ab+b^2) = (log y)/(b^2+bc+c^2) = (log z)/(c^2+ca+a^2), then x^(a-b). y^(b-c). z^(c-a) = -Maths 9th

Description : If (log x)/(a^2+ab+b^2) = (log y)/(b^2+bc+c^2) = (log z)/(c^2+ca+a^2), then x^(a-b). y^(b-c). z^(c-a) = -Maths 9th

Last Answer : (c) 1Let each ratio = k and base = e ⇒ loge x = k(a2 + ab + b2) ⇒ (a - b) loge x = k (a - b) (a2 + ab + b2) ⇒ loge xa - b = k(a3 - b3) ⇒ xa - b = \(e^{k(a^3-b^3)}\) Similarly, yb-c = \(e^{k(b^3-c^3)}\), zc-a = \ ... (e^{k(b^3-c^3)}\) . \(e^{k(c^3-a^3)}\)= \(e^{k[a^3-b^3+b^3-c^3+c^3-a^3]}\) = e0 = 1.

If x = log2a a, y = log3a2a, z = log4a3a, then xyz – 2yz equals -Maths 9th

Description : If x = log2a a, y = log3a2a, z = log4a3a, then xyz – 2yz equals -Maths 9th

Last Answer : (d) -1\(x\) = log2a a = \(rac{ ext{log}\,a}{ ext{log}\,2a}\), y = log3a 2a = \(rac{ ext{log}\,2a}{ ext{log}\,3a}\)z = log4a 3a = \(rac{ ext{log}\,3a}{ ext{log}\,4a}\)∴ xyz - 2yz = \(rac{ ext{log}\ ... \(rac{ ext{log}\,(4a)^{-1}}{ ext{log}\,(4a)}\) = \(rac{-1. ext{log}\,4a}{ ext{log}\,4a}\) = -1.

If a^2 + b^2 + c^2 = 1, x^2 + y^2 + z^2 = 1, where a, b, c, x, y, z are positive reals then ax + by + cz is -Maths 9th

Description : If a^2 + b^2 + c^2 = 1, x^2 + y^2 + z^2 = 1, where a, b, c, x, y, z are positive reals then ax + by + cz is -Maths 9th

Last Answer : answer:

If x, y, z are three positive numbers, then the minimum value of -Maths 9th

Description : If x, y, z are three positive numbers, then the minimum value of -Maths 9th

Last Answer : hope its clear and understandable

If a, b, c, x, y, z are all positve real numbers, then -Maths 9th

Description : If a, b, c, x, y, z are all positve real numbers, then -Maths 9th

Last Answer : answer:

If x = (a-b)/(a+b), y = (b-c)/(b+c), z = (c-a)/(c+a), then what is the value of (1+x)/(1-x). (1+y)/(1-y).(1+z)/(1-z)? -Maths 9th

Description : If x = (a-b)/(a+b), y = (b-c)/(b+c), z = (c-a)/(c+a), then what is the value of (1+x)/(1-x). (1+y)/(1-y).(1+z)/(1-z)? -Maths 9th

Last Answer : answer:

If x + y + z = 0, then x (y – z)^3 + y (z – x)^3 + z (x – y)^3 equals -Maths 9th

Description : If x + y + z = 0, then x (y – z)^3 + y (z – x)^3 + z (x – y)^3 equals -Maths 9th

Last Answer : answer:

If x + y + z = 0, then what is the value of : (1)/(x^2+y^2-z^2)+(1)/(y^2+z^2-x^2)+(1)/(z^2+x^2-y^2)? -Maths 9th

Description : If x + y + z = 0, then what is the value of : (1)/(x^2+y^2-z^2)+(1)/(y^2+z^2-x^2)+(1)/(z^2+x^2-y^2)? -Maths 9th

Last Answer : 0 Given, x + y + z = 0 ⇒ x + y = - z ⇒ x2 + y2 + 2xy = z2 ⇒ x2 + y2 = z2 - 2xy ∴ 1x2+y2−z2=1z2−2xy−z2=1−2xy=−12xy1x2+y2−z2=1z2−2xy−z2=1−2xy=−12xy Similarly, 1y2+z2−x2=−12xy1y2+z2−x2=−12xy and 1z2+x2−y2=−12zx1z2+x2−y2=−12zx ∴ ... −12[z+x+yxyz]−12[z+x+yxyz] = 0. [∵ x + y + z = 0]

If x + y + z = 0, then x^2/(2x^2+yz)+y^2/(2y^2+zx)+z^2/(2z^2+xy) = -Maths 9th

Description : If x + y + z = 0, then x^2/(2x^2+yz)+y^2/(2y^2+zx)+z^2/(2z^2+xy) = -Maths 9th

Last Answer : answer:

If (b + c – a)x = (c + a – b)y = (a + b – c)z = 2, then -Maths 9th

Description : If (b + c – a)x = (c + a – b)y = (a + b – c)z = 2, then -Maths 9th

Last Answer : answer:

If a^x = (x + y + z)^y , a^y = (x + y + z)^z , a^z = (x + y + z)^x , then: -Maths 9th

Description : If a^x = (x + y + z)^y , a^y = (x + y + z)^z , a^z = (x + y + z)^x , then: -Maths 9th

Last Answer : answer:

If x^2 = y + z, y^2 = z + x, z^2 = x + y, then what is the value of: (1/(x+1))+(1/y+1)+(1/z+1)? -Maths 9th

Description : If x^2 = y + z, y^2 = z + x, z^2 = x + y, then what is the value of: (1/(x+1))+(1/y+1)+(1/z+1)? -Maths 9th

Last Answer : answer:

M.I. of sphere of 0.5 m radius about a mutually perpendicular axis (Z-axis) when its M.I. about X-axis and Y-axis are 50 kgm2 and 50 kgm2 is a.50 Kgm2 b.Tapered bearing c.100 Kgm2 d.25 Kgm2 e.12.5 Kgm2

Description : M.I. of sphere of 0.5 m radius about a mutually perpendicular axis (Z-axis) when its M.I. about X-axis and Y-axis are 50 kgm2 and 50 kgm2 is a.50 Kgm2 b.Tapered bearing c.100 Kgm2 d.25 Kgm2 e.12.5 Kgm2

Last Answer : a. 50 Kgm2

Immiscible liquids: w) are not mutually soluble x) dissolve in each other y) dissolve in more than one liquid z) are unstable and chemically react e) do not exist

Description : Immiscible liquids: w) are not mutually soluble x) dissolve in each other y) dissolve in more than one liquid z) are unstable and chemically react e) do not exist

Last Answer : ANSWER: W -- ARE NOT MUTUALLY SOLUBLE

If tan A – tan B = x and cot B – cot A = y, then what is cot (A – B) equal to? -Maths 9th

Description : If tan A – tan B = x and cot B – cot A = y, then what is cot (A – B) equal to? -Maths 9th

Last Answer : answer:

5. Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square. -Maths 9th

Description : 5. Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square. -Maths 9th

Last Answer : Solution: Given that, Let ABCD be a quadrilateral and its diagonals AC and BD bisect each other at right angle at O. To prove that, The Quadrilateral ABCD is a square. Proof, In ΔAOB and ΔCOD, AO = ... right angle. Thus, from (i), (ii) and (iii) given quadrilateral ABCD is a square. Hence Proved.

A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Description : A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Last Answer : O Join AC and BD. Given, COB is the diameter of circle. ∠CAB = ∠BDC = 90° [angle in a semi-circle] Also, AB II CD ∠ABC = ∠DCB (alternate angles] Now, ∠ACB = 90° - ∠ABC and ∠DBC = 90° - ∠DCB = ... = ∠DBC BC = BC [common sides] ΔABC = ΔDCB [by ASA congruency] ∴ AC = BD [by CPCT] Hence Proved.

If the diagonals of a parallelogram are equal, then show that it is a rectangle. -Maths 9th

Description : If the diagonals of a parallelogram are equal, then show that it is a rectangle. -Maths 9th

Last Answer : Given : A parallelogram ABCD , in which AC = BD TO Prove : ABCD is a rectangle . Proof : In △ABC and △ABD AB = AB [common] AC = BD [given] BC = AD [opp . sides of a | | gm] ⇒ △ABC ≅ △BAD [ ... ∵ ∠ABC = ∠BAD] ⇒ 2∠ABC = 180° ⇒ ∠ABC = 1 /2 180° = 90° Hence, parallelogram ABCD is a rectangle.

A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Description : A circle with centre O and diameter COB is given. If AB and CD are parallel, then show that chord AC is equal to chord BD. -Maths 9th

Last Answer : O Join AC and BD. Given, COB is the diameter of circle. ∠CAB = ∠BDC = 90° [angle in a semi-circle] Also, AB II CD ∠ABC = ∠DCB (alternate angles] Now, ∠ACB = 90° - ∠ABC and ∠DBC = 90° - ∠DCB = ... = ∠DBC BC = BC [common sides] ΔABC = ΔDCB [by ASA congruency] ∴ AC = BD [by CPCT] Hence Proved.

If the diagonals of a parallelogram are equal, then show that it is a rectangle. -Maths 9th

Description : If the diagonals of a parallelogram are equal, then show that it is a rectangle. -Maths 9th

Last Answer : Given : A parallelogram ABCD , in which AC = BD TO Prove : ABCD is a rectangle . Proof : In △ABC and △ABD AB = AB [common] AC = BD [given] BC = AD [opp . sides of a | | gm] ⇒ △ABC ≅ △BAD [ ... ∵ ∠ABC = ∠BAD] ⇒ 2∠ABC = 180° ⇒ ∠ABC = 1 /2 180° = 90° Hence, parallelogram ABCD is a rectangle.

Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square. -Maths 9th

Description : Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square. -Maths 9th

Last Answer : Solution :-

Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square. -Maths 9th

Description : Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square. -Maths 9th

Last Answer : We have a quadrilateral ABCD such that angleO is the mid-point of AC and BD. Also AC ⊥ BD. Now, in ΔAOD and ΔAOB, we have AO = AO [Common] OD = OB [ ... i.e. The rhombus ABCD is having one angle equal to 90°. Thus, ABCD is a square.

In the following equations , find which of the variables x, y, z etc. represent rational numbers and which represent irrational numbers -Maths 9th

Description : In the following equations , find which of the variables x, y, z etc. represent rational numbers and which represent irrational numbers -Maths 9th

Last Answer : Following are the rational numbers which represent irrational numbers .

X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Description : X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Last Answer : Here, △XZM and △XZL are on the same base (XZ) and lie between the same parallels (XZ || LM). ∴ ar(△XZL) = ar( △XZM) Adding ar(△XZY) on both sides , we have ar(△XZL) + ar(△XZY) = ar(△XZM) + ar(△XZY) ⇒ ar(△LZY) = ar(quad.MZYX)

A bag contains x white, y red and z blue balls. -Maths 9th

Description : A bag contains x white, y red and z blue balls. -Maths 9th

Last Answer : Number of blue balls = z Total balls = x + y + z therefore P(blue ball)= z /(x+y+z )

Find which of the variables x, y, z and u represent rational numbers and which irrational numbers. -Maths 9th

Description : Find which of the variables x, y, z and u represent rational numbers and which irrational numbers. -Maths 9th

Last Answer : Rational number and irrational number

In the following equations , find which of the variables x, y, z etc. represent rational numbers and which represent irrational numbers -Maths 9th

Description : In the following equations , find which of the variables x, y, z etc. represent rational numbers and which represent irrational numbers -Maths 9th

Last Answer : Following are the rational numbers which represent irrational numbers .

X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Description : X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Last Answer : Here, △XZM and △XZL are on the same base (XZ) and lie between the same parallels (XZ || LM). ∴ ar(△XZL) = ar( △XZM) Adding ar(△XZY) on both sides , we have ar(△XZL) + ar(△XZY) = ar(△XZM) + ar(△XZY) ⇒ ar(△LZY) = ar(quad.MZYX)