Prove that x^3+y^3=x+y(x^2+y^2-xy) -Maths 9th

Prove that x^3+y^3=x+y(x^2+y^2-xy) -Maths 9th
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x3 + y3 = x+y (x2 + y2 -xy) RHS =  x+y (x2 + y2 -xy) On expanding, = x3 + xy2 - x2y + x2y + y3 - xy2 = x3 + y3  LHS = RHS
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Prove that x^3+y^3=x+y(x^2+y^2-xy) -Maths 9th

Description : Prove that x^3+y^3=x+y(x^2+y^2-xy) -Maths 9th

Last Answer : NEED ANSWER

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Last Answer : Here, △XZM and △XZL are on the same base (XZ) and lie between the same parallels (XZ || LM). ∴ ar(△XZL) = ar( △XZM) Adding ar(△XZY) on both sides , we have ar(△XZL) + ar(△XZY) = ar(△XZM) + ar(△XZY) ⇒ ar(△LZY) = ar(quad.MZYX)

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In the given figure, equal chords AB and CD of a circle with centre O cut at right angles at E. If M and N are the mid-points of AB and CD respectively, prove that OMEN is a square. -Maths 9th

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