(a) Given, area of an isosceles right triangle = 8 cm2 Area of an isosceles triangle = 1/2 (Base x Height) ⇒ 8 = 1/2 (Base x Base) [∴ base = height, as triangle is an isosceles triangle] ⇒ (Base)2 =16 ⇒ Base= 4 cm In ΔABC, using Pythagoras theorem AC2 = AB2 + BC2 = 42 + 42 = 16 + 16 ⇒ AC2 = 32 ⇒ AC = √32 cm [taking positive square root because length is always positive] Hence, the length of its hypotenuse is √32 cm.