Let each of the equal side of isosceles triangle = 3x cm and base of isosceles triangle = 2x cm ∴ Perimeter = 3x + 3x + 2x 32 = 8x ⇒ x = 4 ∴ Sides are 3 x 4,3 x 4, 2 x 4 i.e., 12 cm, 12 cm, 8 cm Now, s = (a + b + c)/2 = (12 + 12 + 8)/2 = 16 cm ∴ Area of triangle = under root(√s(s - a)(s - b)(s - c)) = under root(√16(16 - 12)(16 - 12)(16 - 8)) = under root (√16 x 4 x 4 x 8) = 32√2 cm2