A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5cm. Find the outer curved surface of the bowl. -Maths 9th

1 Answer

Answer :

Inner radius of hemispherical bowl = 5cm Thickness of the bowl = 0.25 cm Outer radius of hemispherical bowl = (5+0.25) cm = 5.25 cm Formula for outer CSA of hemispherical bowl = 2πr2, where r is radius of hemisphere = 2×(22/7)×(5.25)2 = 173.25 Therefore, the outer curved surface area of the bowl is 173.25 cm2.

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