The roller is in the form of a cylinder of diameter = 84 cm ⇒ Radius of the roller(r) = 842 cm = 42 cm Length of the roller (h) = 120 cm Curved surface area of the roller = 2πrh = 2 x 227 x 42 x 120 cm2 = 2 x 22 x 6 x 120 cm2 = 31680 cm2 Now, area of the playground levelled in one revolution of the roller = 31680 cm2 = 3168010000m2 ∴ Area of the playground levelled in 500 revolutions = 500 x 3168010000m2 = 1584m2