What are the benefits of the Golden Quadrilateral? -SST 10th

What are the benefits of the Golden Quadrilateral? -SST 10th
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(i) It will cut down travel time by about 20-25%. (ii) It will help industrial growth of the towns through which it passes. (iii) It will help Transport of the agricultural produce from the hinterland to the major cities and ports. (iv) It will help job opportunities in construction as well as in demand for steel, cement and other construction materials.
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Related questions

Write a short note on the Golden Quadrilateral and the North-South and East-West Corridors. -SST 10th

Description : Write a short note on the Golden Quadrilateral and the North-South and East-West Corridors. -SST 10th

Last Answer : The government has launched a major road development project linking Delhi - Kolkata - Chennai - Mumbai - Delhi by six-lane Super Highways. This is known as Golden Quadrilateral Super ... of India by providing opportunity for free movement of traffic, thus increasing connectivity between them.

What are Golden Quadrilateral Super Highways ? -SST 10th

Description : What are Golden Quadrilateral Super Highways ? -SST 10th

Last Answer : (i) The Golden qudrilateral super Highways is a major road development project linking Delhi - Kolkata - Chennai - Mumbai and Delhi by six lane super highways. (ii) The two major objectives ... and kanyakumari (Tamil Nadu) and East-West corridor connecting Silchar (Assam) and Porbander (Gujarat).

What is the Golden Quadrilateral (GQ)? -SST 10th

Description : What is the Golden Quadrilateral (GQ)? -SST 10th

Last Answer : This is the biggest and most ambitious project. It connects Delhi, Kolkata, Mumbai and Chennai forming a quadrilateral of sorts.

Name the four sections of the Golden Quadrilateral. -SST 10th

Description : Name the four sections of the Golden Quadrilateral. -SST 10th

Last Answer : The four sections are: (i) Delhi-Kolkata NH 2 (ii) Chennai-Mumbai NH 4 / 7 / 46 (iii) Kolkata-Chennai NH 5 (iv) Mumbai-Delhi NH 8 / 76 / 79

Mention any two ways in which Golden Quadrilateral will help in the economic development of the country? -SST 10th

Description : Mention any two ways in which Golden Quadrilateral will help in the economic development of the country? -SST 10th

Last Answer : The Golden Quadrilateral is a highway network connecting India’s for largest metropolises: Delhi, Mumbai, Chennai and Kolkata the project will help industrial development by easing the process of supply of raw materials. It will also help to connect many remote areas with the main cities.

Give one point of difference between Golden Quadrilateral Highways and National Highways. -Geography

Description : Give one point of difference between Golden Quadrilateral Highways and National Highways. -Geography

Last Answer : The main roads which connect the state capitals, big cities and important ports are constructed and maintained by the Central Public Works Dept, and are known as Highways. Golden Quadrilateral ... Kolkata - Delhi by six lane superhighways is being implemented by National Highway Authority of India.

How does the Golden Quadrilateral differ from National Highways ? -Geography

Description : How does the Golden Quadrilateral differ from National Highways ? -Geography

Last Answer : The Golden Quadrilateral are roads like National Highways connecting Delhi - Mumbai-Chennai-Kolkata-Delhi by a six lane highway while National Highways are roads connecting capitals, big cities ... . Golden quadrilateral is maintained by NHDP whereas the National Highways are maintained by CPWD.

Which organisation is responsible for implementation of the Golden Quadrilateral Highway project? -Geography

Description : Which organisation is responsible for implementation of the Golden Quadrilateral Highway project? -Geography

Last Answer : The Indian government launched a project to connect Delhi-Kolkata-Chennai-Mumbai by six-lane superhighways. The objective behind the making of these superhighways is to reduce the time and distance ... project of superhighways is being implemented by the National Highway Authority of India (NHAI).

With reference to National Highways Development Project (NHDP), consider the following statements: 1. Belgaum and Nellore lie on the Golden Quadrilateral. 2. Vadodara and Jhansi lie on the East - West Corridor. 3. Ambala and Kanpur lie on the North - South Corridor. Which of these statements is/are correct ? [CDS 2003] (a) 1, 2 and 3 (b) 2 and 3 (c) 1 and 2 (d) 1 only

Description : With reference to National Highways Development Project (NHDP), consider the following statements: 1. Belgaum and Nellore lie on the Golden Quadrilateral. 2. Vadodara and Jhansi lie on the East - West Corridor. 3. Ambala and Kanpur lie on ... 2003] (a) 1, 2 and 3 (b) 2 and 3 (c) 1 and 2 (d) 1 only

Last Answer : Ans: (d)

Which from the following towns is not on the "Golden Quadrilateral" being created for the roads-infrastructure of the country? [SSC Graduate 2003)] (a) Ajmer (b) Ahmedabad (c) Jabalpur (d) Gaya

Description : Which from the following towns is not on the "Golden Quadrilateral" being created for the roads-infrastructure of the country? [SSC Graduate 2003)] (a) Ajmer (b) Ahmedabad (c) Jabalpur (d) Gaya

Last Answer : Ans: (c)

Which of the following towns is not on the "Golden Quadrilateral" being created for the roads infrastructure of the country ? [SSC Graduate 2003] (a) Chennai (b) Hyderabad (c) Vishakhapatnam (d) Bhubhaneshwar

Description : Which of the following towns is not on the "Golden Quadrilateral" being created for the roads infrastructure of the country ? [SSC Graduate 2003] (a) Chennai (b) Hyderabad (c) Vishakhapatnam (d) Bhubhaneshwar

Last Answer : Ans: (b)

Which among the following cities in India is not located in Golden Quadrilateral Road Network? (1) Kolkata (2) Mumbai (3) New Delhi (4) Chandigarh

Description : Which among the following cities in India is not located in Golden Quadrilateral Road Network? (1) Kolkata (2) Mumbai (3) New Delhi (4) Chandigarh

Last Answer : (4) Chandigarh Explanation: The Golden Quadrilateral Road Network is a highway network connecting many of the major industrial, agricultural and cultural centres of India. A quadrilateral of sorts is formed ... , Kanpur, Pune, Surat, Nellore, Vijayawada and Guntur are also connected by the network.

Which of the following towns is not on the "Golden Quadrilateral" being created for the roads infrastructure of the country? (1) Chennai (2) Hyderabad (3) Visakhapatnam (4) Bhubaneswar

Description : Which of the following towns is not on the "Golden Quadrilateral" being created for the roads infrastructure of the country? (1) Chennai (2) Hyderabad (3) Visakhapatnam (4) Bhubaneswar

Last Answer : (2) Hyderabad Explanation: The Golden Quadrilateral is a highway network connecting India's four largest metropolises: Delhi, Mumbai, Chennai and Kolkata, thus forming a quadrilateral of sorts. Four ... project in India, it is the first phase of the National Highways Development Project (NHDP).

Which highway sector is common to both the Golden Quadrilateral Highway and the North- (1) South Corridor Highway? (2) Agra-Jhansi (3) Bangalore-Krishnagiri (4) Delhi-Jaipur Coirnbatore-Salem

Description : Which highway sector is common to both the Golden Quadrilateral Highway and the North- (1) South Corridor Highway? (2) Agra-Jhansi (3) Bangalore-Krishnagiri (4) Delhi-Jaipur Coirnbatore-Salem

Last Answer : (2) Bangalore-Krishnagiri Explanation: The North-South-East-West Corridor (NS-EW) is the largest ongoing highway project in India. It is the second phase of the National Highways Development.

Golden Quadrilateral Project for the development of National Highways was initiated by – (1) P V Narasimha Rao (2) I K Gujral (3) Manmohan Singh (4) Atal Bihari Vajpayee

Description : Golden Quadrilateral Project for the development of National Highways was initiated by – (1) P V Narasimha Rao (2) I K Gujral (3) Manmohan Singh (4) Atal Bihari Vajpayee

Last Answer : (4) Atal Bihari Vajpayee Explanation: The Golden Quadrilateral project was launched by the then Prinie Minister Atal Bihari Vajpayee in 2001. The Golden Quadrilateral is a highway network connecting many of ... India. It is the largest highway project in India and the fifth longest in the world.

From the following, which type of element is not two dimensional? a.Tetrahedron b.Quadrilateral c.Parallelogram d.Rectangle

Description : From the following, which type of element is not two dimensional? a.Tetrahedron b.Quadrilateral c.Parallelogram d.Rectangle

Last Answer : a.Tetrahedron

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm. -Maths 9th

Description : Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm. -Maths 9th

Last Answer : Given a quadrilateral ABCD with AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm. For ∆ABC, a = AB = 3 cm, b = BC = 4 cm and c = AC = 5 cm Now, area of quadrilateral ABCD = area of ∆ABC + area of ∆ACD = 6 cm2 + 9.2 cm2 = 15.2 cm2 (approx.)

6. Show that the line segments joining the mid-points of the opposite sides of a quadrilateral bisect each other. -Maths 9th

Description : 6. Show that the line segments joining the mid-points of the opposite sides of a quadrilateral bisect each other. -Maths 9th

Last Answer : Solution: Let ABCD be a quadrilateral and P, Q, R and S are the mid points of AB, BC, CD and DA respectively. Now, In ΔACD, R and S are the mid points of CD and DA respectively. , ... , PQRS is parallelogram. PR and QS are the diagonals of the parallelogram PQRS. So, they will bisect each other.

3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Description : 3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Construction, Join AC and BD. To Prove, PQRS is a rhombus. Proof: In ΔABC P and Q ... (ii), (iii), (iv) and (v), PQ = QR = SR = PS So, PQRS is a rhombus. Hence Proved

2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

Description : 2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. To Prove, PQRS is a rectangle. Construction, Join AC and BD. Proof: In ΔDRS and ... , In PQRS, RS = PQ and RQ = SP from (i) and (ii) ∠Q = 90° , PQRS is a rectangle.

ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Description : ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Last Answer : . Solution: (i) In ΔDAC, R is the mid point of DC and S is the mid point of DA. Thus by mid point theorem, SR || AC and SR = ½ AC (ii) In ΔBAC, P is the mid point of AB and Q is the mid point of BC. ... ----- from question (ii) ⇒ SR || PQ - from (i) and (ii) also, PQ = SR , PQRS is a parallelogram.

In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram (ii) quadrilateral BEFC is a parallelogram (iii) AD || CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Description : In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram ( ... CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Last Answer : . Solution: (i) AB = DE and AB || DE (Given) Two opposite sides of a quadrilateral are equal and parallel to each other. Thus, quadrilateral ABED is a parallelogram (ii) Again BC = EF and BC || EF ... (Given) BC = EF (Given) AC = DF (Opposite sides of a parallelogram) , ΔABC ≅ ΔDEF [SSS congruency]

5. Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square. -Maths 9th

Description : 5. Show that if the diagonals of a quadrilateral are equal and bisect each other at right angles, then it is a square. -Maths 9th

Last Answer : Solution: Given that, Let ABCD be a quadrilateral and its diagonals AC and BD bisect each other at right angle at O. To prove that, The Quadrilateral ABCD is a square. Proof, In ΔAOB and ΔCOD, AO = ... right angle. Thus, from (i), (ii) and (iii) given quadrilateral ABCD is a square. Hence Proved.

3. Show that if the diagonals of a quadrilateral bisect each other at right angles, then it is a rhombus. -Maths 9th

Description : 3. Show that if the diagonals of a quadrilateral bisect each other at right angles, then it is a rhombus. -Maths 9th

Last Answer : Solution: Let ABCD be a quadrilateral whose diagonals bisect each other at right angles. Given that, OA = OC OB = OD and ∠AOB = ∠BOC = ∠OCD = ∠ODA = 90° To show that, if the ... a parallelogram. , ABCD is rhombus as it is a parallelogram whose diagonals intersect at right angle. Hence Proved.

Prove that the quadrilateral formed by joining the mid points of quadrilateral forms parallelogram -Maths 9th

Description : Prove that the quadrilateral formed by joining the mid points of quadrilateral forms parallelogram -Maths 9th

Last Answer : Please see Exercise 8.2 - question 1 here in Quadrilaterals.

Proof to show that the quadrilateral formed by joining the midpoints of a square is a square. -Maths 9th

Description : Proof to show that the quadrilateral formed by joining the midpoints of a square is a square. -Maths 9th

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If the diagonals of a quadrilateral bisect each other at right angles , then name the quadrilateral . -Maths 9th

Description : If the diagonals of a quadrilateral bisect each other at right angles , then name the quadrilateral . -Maths 9th

Last Answer : Quadrilateral will be Rhombus .

The diagonals of a quadrilateral ABCD are perpendicular to each other. -Maths 9th

Description : The diagonals of a quadrilateral ABCD are perpendicular to each other. -Maths 9th

Last Answer : Given: A quadrilateral ABCD whose diagonals AC and BD are perpendicular to each other at O. P,Q,R and S are mid points of side AB, BC, CD and DA respectively are joined are formed quadrilateral PQRS. To ... 90° Thus, PQRS is a parallelogram whose one angle is 90°. ∴ PQRS is a rectangle.

In quadrilateral ABCD of the given figure, X and Y are points on diagonal AC such that AX = CY and BXDY ls a parallelogram. -Maths 9th

Description : In quadrilateral ABCD of the given figure, X and Y are points on diagonal AC such that AX = CY and BXDY ls a parallelogram. -Maths 9th

Last Answer : This answer was deleted by our moderators...

BD is one of the diagonals of a quadrilateral ABCD. AM and CN are the perpendiculars from A and C respectively on BD . -Maths 9th

Description : BD is one of the diagonals of a quadrilateral ABCD. AM and CN are the perpendiculars from A and C respectively on BD . -Maths 9th

Last Answer : We know that area of a triangle = 1/2 × base × altitude ∴ ar(△ABD) = 1/2 × BD × AM and ar(△BCD) = 1/2 BD × CN Now, ar(quad. ABCD) = ar(△ABD) + ar(△BCD) = 1/2 × BD × AM + 1/2 × BD × CN = 1/2 × BD × (AM + CN)

In the given figure, WXYZ is a quadrilateral with a point P on side WX. If ZY // WX, show that : -Maths 9th

Description : In the given figure, WXYZ is a quadrilateral with a point P on side WX. If ZY // WX, show that : -Maths 9th

Last Answer : ar (ZPY)=ar( ZXY) they lie between the same base and between the same parallels Similarly, ar(WZY)=ar(ZPY) ar(ZWX)=ar(XWY)

Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. -Maths 9th

Description : Diagonals AC and BD of a quadrilateral ABCD intersect each other at P. -Maths 9th

Last Answer : Draw AM ⟂ BD and CL ⟂ BD. Now, ar(△APB) × ar(△CPD) = {1/2 PB × AM} × {1/2 DP × CL} = {1/2 PB × CL} × {1/2 DP × AM} ar(△BPC) × ar(△APD) Hence, ar(△APB) × ar(△CPD) = ar(△APD) × ar(△BPC)

If two opposite sides of a cyclic quadrilateral are parallel , then prove that - (a) remaining two sides are equal (b) both the diagonals are equal -Maths 9th

Description : If two opposite sides of a cyclic quadrilateral are parallel , then prove that - (a) remaining two sides are equal (b) both the diagonals are equal -Maths 9th

Last Answer : Let ABCD be quadrilateral with ab||cd Join be. In triangle abd and CBD, Angle abd=angle cdb(alternate angles) Anglecbd=angle adb(alternate angles) Bd=bd(common) Abd=~CBD by asa test Ad=BC by cpct Since ad ... c(from 1) Ad =bc(proved above) Triangle adc=~bcd by sas test Ac=bd by cpct Hence proved

The quadrilateral formed by joining the mid-points of the sides of a quadrilateral PQRS, taken in order, is a rectangle, if -Maths 9th

Description : The quadrilateral formed by joining the mid-points of the sides of a quadrilateral PQRS, taken in order, is a rectangle, if -Maths 9th

Last Answer : According to question the mid-points of the sides of a quadrilateral PQRS, taken in order, is a rectangle,

The quadrilateral formed by joining the mid-points of the side of quadrilateral PQRS, taken in order, is a rhombus, if -Maths 9th

Description : The quadrilateral formed by joining the mid-points of the side of quadrilateral PQRS, taken in order, is a rhombus, if -Maths 9th

Last Answer : (d) Given, the quadrilateral ABCD is a rhombus. So, sides AB, BC, CD and AD are equal.

If angles A, B,C and D of the quadrilateral ABCD, taken in order are in the ratio 3 :7:6:4, then ABCD is a -Maths 9th

Description : If angles A, B,C and D of the quadrilateral ABCD, taken in order are in the ratio 3 :7:6:4, then ABCD is a -Maths 9th

Last Answer : (c) Given, ratio of angles of quadrilateral ABCD is 3 : 7 : 6 : 4. Let angles of quadrilateral ABCD be 3x, 7x, 6x and 4x, respectively. We know that, sum of all angles of a quadrilateral is 360°. 3x + 7x + 6x + 4x = 360° => 20x = 360° => x=360°/20° = 18°

The figure formed by joining the mid-points of the sides of a quadrilateral ABCD, taken in order, is a square only, if -Maths 9th

Description : The figure formed by joining the mid-points of the sides of a quadrilateral ABCD, taken in order, is a square only, if -Maths 9th

Last Answer : According to question mid-points of the sides of a quadrilateral ABCD, taken in order, is a square only.

All the angles of a quadrilateral are equal. What special name is given to this quadrilateral ? -Maths 9th

Description : All the angles of a quadrilateral are equal. What special name is given to this quadrilateral ? -Maths 9th

Last Answer : We know that, sum of all angles in a quadrilateral is 360°. If ABCD is a quadrilateral, ∠A+ ∠B+ ∠C + ∠D = 360° (i) But it is given all angles are equal. ∠A = ∠B = ∠C = ∠D From Eq. (i ... ⇒ 4 ∠A = 360° ∠A = 90° So, all angles of a quadrilateral are 90°. Hence, given quadrilateral is a rectangle.

Can all the four angles of a quadrilateral be obtuse angles? Give reason for your answer. -Maths 9th

Description : Can all the four angles of a quadrilateral be obtuse angles? Give reason for your answer. -Maths 9th

Last Answer : No, all the four angles of a quadrilateral cannot be obtuse. As, the sum of the angles of a quadrilateral is 360°, then may have maximum of three obtuse angles.

Can all the angles of a quadrilateral be acute angles ? Give reason for your answer. -Maths 9th

Description : Can all the angles of a quadrilateral be acute angles ? Give reason for your answer. -Maths 9th

Last Answer : No, all the angles of a quadrilateral cannot be acute angles. As, sum of the angles of a quadrilateral is 360°. So, maximum of three acute angles will be possible.

Can all the angles of a quadrilateral be right angles? Give reason for your answer. -Maths 9th

Description : Can all the angles of a quadrilateral be right angles? Give reason for your answer. -Maths 9th

Last Answer : Yes, all the angles of a quadrilateral can be right angles. In this case, the quadrilateral becomes rectangle or square.

Opposite angles of a quadrilateral ABCD are equal. If AB = 4 cm, determine CD. -Maths 9th

Description : Opposite angles of a quadrilateral ABCD are equal. If AB = 4 cm, determine CD. -Maths 9th

Last Answer : Given, opposite angles of a quadrilateral are equal. So, ABCD is a parallelogram and we know that, in a parallelogram opposite sides are also equal. ∴ CD = AB = 4cm

P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

Last Answer : Given In a quadrilateral ABCD, P, Q, R and S are the mid-points of sides AB, BC, CD and DA, respectively. Also, AC = BD To prove PQRS is a rhombus.

P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Last Answer : Given In quadrilateral ABCD, P, Q, R and S are the mid-points of the sides AB, BC, CD and DA, respectively. Also, AC = BD and AC ⊥ BD. To prove PQRS is a square. Proof Now, in ΔADC, S and R are the mid-points of the sides AD and DC respectively, then by mid-point theorem,

Show that the quadrilateral formed by joining the consecutive sides of a square is also a square. -Maths 9th

Description : Show that the quadrilateral formed by joining the consecutive sides of a square is also a square. -Maths 9th

Last Answer : According to question quadrilateral formed by joining the consecutive sides of a square is also a square.

Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle. -Maths 9th

Description : Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle. -Maths 9th

Last Answer : Given Let ABCD be a parallelogram and AP, BR, CR, be are the bisectors of ∠A, ∠B, ∠C and ∠D, respectively. To prove Quadrilateral PQRS is a rectangle. Proof Since, ABCD is a parallelogram, then DC ... and ∠PSR = 90° Thus, PQRS is a quadrilateral whose each angle is 90°. Hence, PQRS is a rectangle.

ABCD is a quadrilateral whose diagonal AC divides it into two parts, equal in area, then ABCD -Maths 9th

Description : ABCD is a quadrilateral whose diagonal AC divides it into two parts, equal in area, then ABCD -Maths 9th

Last Answer : (d) Here, ABCD need not be any of rectangle, rhombus and parallelogram because if ABCD is a square, then its diagonal AC also divides it into two parts which are equal in area.

If the mid-points of the sides of a quadrilateral are joined in order, prove that the area of the parallelogram, so formed will be half of the area of the given quadrilateral (figure). -Maths 9th

Description : If the mid-points of the sides of a quadrilateral are joined in order, prove that the area of the parallelogram, so formed will be half of the area of the given quadrilateral (figure). -Maths 9th

Last Answer : According to question prove that the area of the parallelogram

ABCD is such a quadrilateral that A is the centre of the circle passing through B, C and D. -Maths 9th

Description : ABCD is such a quadrilateral that A is the centre of the circle passing through B, C and D. -Maths 9th

Last Answer : According to question p rove that ∠CBD +∠CDB = 1/2 ∠BAD.

If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Description : If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Last Answer : Given ΔABC is an isosceles triangle such that AB = AC and also DE || SC. To prove Quadrilateral BCDE is a cyclic quadrilateral. Construction Draw a circle passes through the points B, C, D and E.