147 A ray directed towards the centre of curvature of a spherical mirror
a) become parallel to principal axis b)retraces its path
 c)appears to diverge from focus d)passes through focus.

1 Answer

Answer :

b)retraces its path

Related questions

Description : The distance between Pole and Focus is called a) principal axis b)focal length c)radius of curvature d)centre of curvature

Last Answer : b)focal length

Description : We can see non luminous object ,when the light a) emitted by the object falls on the eye . b) is reflected from the object towards eye . c) completely passes through the object . d) gets completely absorbed by object .

Last Answer : b) is reflected from the object towards eye .

Description : When light moves from air to water the ray of light bends ________ the normal. a) away b)towards c)along d)no change

Last Answer : b)towards

Description : When beam of parallel rays of light falls on _______ then all the rays of light converge . a) convex lens b)concave lens c)plain mirror d)plano concave lens

Last Answer : a) convex lens

Description : A perfectly spherical bubble of air is suspended in a tank of water. A beam of light consisting of parallel rays passes through the bubble. As the light emerges from the opposite side of the bubble the light rays: w) diverge x) converge y) are unaffected

Last Answer : ANSWER: W -- DIVERGE

Description : The centre of the reflecting surface of a spherical mirror is called the : (1) Radius (2) Centre of Curvature (3) Pole (4) Focus

Last Answer : (3) Pole Explanation: The center of the reflecting surface of a spherical mirron is called as the pole of the mirror which is mainly known as the center of curvature.

Description : Draw the ray diagram in each case to show the position and nature of the image formed when the object is placed: (i) at the centre of curvature of a concave mirror (ii) between the pole P and focus F of ... front of a convex mirror (iv) at 2F of a convex lens (v) in front of a concave lens -Physics

Last Answer : Answer. Nature of image: Real, inverted and same size image is formed at the centre of curvature. Nature of image: Virtual, enlarged and erect image is formed behind the mirror. Nature of image: Virtual ... : Virtual, erect and diminished image is formed between O and F on the same side of object.

Description : An incident ray comes in parallel to the principle axis of a concave mirror. Is it reflected: w) back along the incident ray x) at 30 degrees to incident ray y) through the focal point z) through the center of curvature

Last Answer : ANSWER: Y -- THROUGH THE FOCAL POINT 

Description : When a pencil is dipped in glass of water it appears bent near the surface of water due to ______ of light. a) refraction b)reflection c)bouncing back of light d)none

Last Answer : a) refraction

Description : In case of convex lens when the image formed is real, inverted and same size as the object then the object should have been at ______ position of lens. a) infinity b)focus c)2F d)between F and 2F

Last Answer : c)2F

Description : The distance of the object from the plain mirror is 1.5 cm . What will be the total distance between the object and its image. a) 1.5cm b)3cm c)2.5cm d)1cm

Last Answer : b)3cm

Description : The size of the image formed by a plane mirror is a) bigger than the object b)same as object c)smaller than the object d)far away from the object .

Last Answer : b)same as object

Description : A concave mirror forms real, inverted and enlarged image at infinity. Where is the object kept a) at F b)at C c)between F and C d)beyond C

Last Answer : a) at F

Description : If the incident ray falls directly on the normal. What will be the angle of incidence .? a ) 0 b)30 c)60 d)90

Last Answer : a ) 0

Description : When object is placed _______ in front of convex lens than image formed is virtual, erect, magnified and on same side beyond F . a) between optical centre and F b)At F c)between F and 2F d)2F

Last Answer : a) between optical centre and F

Description : Explain why a ray of light passing through the centre of curvature of concave minor gets reflected along the same path. -Science

Last Answer : The light falling on the centre of curvature is reflected back along the same path because incident ray falls on the mirror along the normal to the reflecting surface.

Description : Diffused reflection takes place through a) metal b)glass c)wood d)thin transparent sheet

Last Answer : c)wood

Description : The phenomenon of interchange of the left side and right side between the object and its image is called_________. a) reflection b)refraction c)dispersion d)lateral inversion

Last Answer : d)lateral inversion

Description : Force which acts on a body moving in a circular path and it is directed towards centre is called?

Last Answer : Centripetal force

Description : A concave lens always forms a virtual, erect and ________ image . a) same b)magnified c)diminished d)none

Last Answer : c)diminished

Description : _____ is natural phenomenon associated with dispersion of sunlight. a) rainbow b)reflection c)dispersion d)refraction

Last Answer : a) rainbow

Description : The white light after falling on prism gets split into seven colours due to _______ of light. a) reflection b)refraction c)dispersion d)bend

Last Answer : c)dispersion

Description : When light falls on shiny surface it gets __________ . a) refracted b)reflected c)bent d)nothing happens

Last Answer : b)reflected

Description : When a ray passes through a prism ______. A. It goes undeviated B. It remain parallel to a base C. It bends towards the base D. None

Last Answer : C. It bends towards the base

Description : 2. The radius of curvature of a spherical mirror is 20 cm. What is its focal length? -Physics-10

Last Answer : Radius of curvature (R) = 20 cm Radius of curvature of the spherical mirror = 2 × Focal length (f) R = 2f f= R/2 = 20 / 2 = 10 Therefore, the focal length of the spherical mirror is 10 cm.

Description : The focal length of a concave spherical mirror is equal to 1 meter. What is the radius of curvature of this mirror?  

Last Answer : ANSWER: 2 METERS

Description : To create an enlarged real image using a concave mirror, the object must be placed: w) beyond the center of curvature. x) between the center and the focus. y) at the focus. z) closer than the focus.

Last Answer : ANSWER: X -- BETWEEN THE CENTER AND THE FOCUS.

Description : What is the main focus of spherical mirror ?

Last Answer : : The point at which the rays of light parallel to the main axis of the spherical mirror meet at the point above the main axis (in the concave mirror) or appear to be moving away from the point above the main axis (in the convex mirror) is called the main focus of the spherical mirror.

Description : An object is placed beyond 2F, in front of a convex lens, image will be formed : (a) between F and 2F (b) at focus (c) at the centre of curvature (d) between focus and Optical centre

Last Answer : (a) between F and 2F

Description : The line joining the centre of curvature and pole of the mirror is called. ______.

Last Answer : The line joining the centre of curvature and pole of the mirror is called. ______. A. the principal axis B. y-axis C. the centre axis D. None of these

Description : When light enters an optically denser medium, the light ray: w) bends away from a normal to surface x) passes through unbent y) bends towards a normal to surface z) none of the above

Last Answer : ANSWER: Y -- BENDS TOWARDS A NORMAL TO SURFACE

Description : 1. Define the principal focus of a concave mirror. -Physics-10

Last Answer : Light rays that are parallel to the principal axis of a concave mirror converge at a specific point on its principal axis after reflecting from the mirror. This point is called the principal focus of the concave mirror.

Description : Force that acts on a body moving in a circu- lar path and is directed away from the centre is called?

Last Answer : Centrifugal force

Description : Centripetal force is directed towards the A. tangent to circle B. center C. normal to circle D. parallel to circl

Last Answer : center

Description : A man is standing near the edge of a uniformly rotating platform about an axis passing through its centre. The speed of rotation of the platform will decrease if he a.extends his arms outwards b.moves ... heavy bag from one of his friends standing near by and holds it in his hand e.107 dynes

Last Answer : d. accepts a heavy bag from one of his friends standing near by and holds it in his hand

Description : A man is standing ner the edge of a uniformly rotating platform about an axis passing through its centre. The speed of rotation of the platorm will decrease if he a.extends his arms outwards b.107 ... towards the axis of rotation d.jumps out from that platform e.take out his coat and throws away

Last Answer : a. extends his arms outwards

Description : Prove that the line joining the mid-points of two parallel chords of a circle passes through the centre. -Maths 9th

Last Answer : Let AB and CD be two parallel chords having P and Q as their mid-points, respectively. Let O be the centre of the circle. Join OP and OQ and draw OX | | AB | | CD. Since, Pis the mid-point of AB. ⇒ OP ... 90° Now, ∠POX + ∠XOQ = 90° + 90° = 180° so, POQ is a straight line . Hence proved

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : According to question prove that the two chords are parallel.

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : Given : E and F are mid points of 2 chords AB and CD respectively. Line EF passes through centre. To prove : AB||CD ∠ OFC = ∠ OEA = 90° as line drawn through the centre to bisect the ... EF as traversal for lines AB and CD as alternate interior angles on same side are equal. Therefore, AB || CD

Description : Prove that the line joining the mid-points of two parallel chords of a circle passes through the centre. -Maths 9th

Last Answer : Let AB and CD be two parallel chords having P and Q as their mid-points, respectively. Let O be the centre of the circle. Join OP and OQ and draw OX | | AB | | CD. Since, Pis the mid-point of AB. ⇒ OP ... 90° Now, ∠POX + ∠XOQ = 90° + 90° = 180° so, POQ is a straight line . Hence proved

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : According to question prove that the two chords are parallel.

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : Given : E and F are mid points of 2 chords AB and CD respectively. Line EF passes through centre. To prove : AB||CD ∠ OFC = ∠ OEA = 90° as line drawn through the centre to bisect the ... EF as traversal for lines AB and CD as alternate interior angles on same side are equal. Therefore, AB || CD

Description : AB and CD are equal and parallel chords of a circle with centre O. Then AC passes through the centre O. [Agree `//` Disagree]

Last Answer : AB and CD are equal and parallel chords of a circle with centre O. Then AC passes through the centre O. [Agree `//` Disagree]

Description : When light enters a closed room through a small hole in the door, the image of an outside building appears as inverted on the opposite wall. This is because (a) The hole acts as a convex lens (b) ... the edges of the hole (c) Of rectilinear propagation of light (d) The hole acts as a concave lens

Last Answer : Ans:(b)

Description : Two plane mirrors are inclined at angle `theta` as shown in figure. If a ray parallel to OB strikes the other mirror at P and finally emerges parallel

Last Answer : Two plane mirrors are inclined at angle `theta` as shown in figure. If a ray parallel to OB ... OA after two reflections then `theta` is equal to

Description : A spherical convex surface separates object and image space of refractive index `1.0 and 4/3.` If radius of curvature of the surface is `10cm,` find i

Last Answer : A spherical convex surface separates object and image space of refractive index `1.0 and 4/3.` If ... of the surface is `10cm,` find its power.

Description : Knot is a measure of – (1) The speed of ship (2) The curvature of spherical objects (3) Solar radiation (4) Intensity of earthquake shock

Last Answer : (1) The speed of ship Explanation: The knot (pronounced not) is a unit of speed equal to one nautical mile (1.852 km) per hour, approximately 1.151 mph. There is no standard abbreviation but km is commonly used. The knot is a non-SI unit accepted for use with the International System of Units (SI).

Description : Knot is a measure of – (1) Unit of speed (2) the curvature of spherical objects (3) solar radiation (4) intensiry of earthquake shock

Last Answer : (1) Unit of speed Explanation: The Knot is a unit of speed equal to one nautical mile per hour. The ISO standerd symbol for the knot is Kn.