Huffman trees use the _______________ of each character to work out their encoding. A. Frequency B. Order in ASCII C. Number value

Huffman trees use the _______________ of each character to work out their encoding.
A. Frequency
B. Order in ASCII
C. Number value
by

1 Answer

Answer :

A. Frequency
by

Related questions

Huffman trees use the _______________ of each character to work out their encoding. A. Frequency B. Order in ASCII C. Number value

Description : Huffman trees use the _______________ of each character to work out their encoding. A. Frequency B. Order in ASCII C. Number value

Last Answer : A. Frequency

Huffman trees use the _______________ of each character to work out their encoding. a. Frequency b. Order in ASCII c. Number value d. Both (a) and (b)

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Which formula shows how to work out the percentage a file has been compressed by? A. bits in (Huffman *7) /100 B. bits in ASCii - bits in Huffman C. difference in bits / bits in ASCII * 100

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Last Answer : C. difference in bits / bits in ASCII * 100

How do you calculate the number of bits of a body of text in ASCII? A. Number of characters * 7 B. Number of characters (including spaces) *7 C. bits in Huffman * 7 D. bits in Huffman / 7

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Huffman coding is an encoding algorithm used for A. lossless data compression B. files greater than 1 Mbit C. broadband systems D. lossy data compression

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In Huffman encoding, both the sender and receiver must have a copy of the code a. Same b. Different c. Generate on Demand d. Both (a) and (b)

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Huffman coding is an encoding algorithm used for a. lossless data compression b. files greater than 1 Mbit c. broadband systems d. lossy data compression

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Total number of nodes in the adaptive huffman tree is: A. 2n+1 B. 2n C. 2n-1 D. 2n-2

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A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is A. 8.0 bit B. 2.0 bit C. 1.9 bit D. 2.1 bit

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Extended Huffman method is used due to a. Large alphabet b. Skewed probability c. Equal probability d. Both (a) and(b)

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If the probability is not given which method is preferable a. Huffman b. Non Binary Huffman c. Adaptive Huffman d. Extended Huffman

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Average length of Extended Huffman code is upper bounded by : a. R b. R+1 c. R-1 d. R+1/n

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