The sum of three consecutive integers is 36. What is the largest of the three integers? The correct answer is 13.?

The sum of three consecutive integers is 36. What is the largest of the three integers? The correct answer is 13.?
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6 Answers

Answer :

called x the smaller of the three :

3x+3 = 36

x = 33/3 = 11

y = x+1 = 12

z = x+2 = 13
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Answer :

(x-1), x, (x+1)

sum 3x = 36

x = 12

largest = 13
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Answer :

Let x be the largest.

Let x-1 be the next smaller.

Let x-2 be the smallest.

x + x-1 + x-2 = 36

3x - 3 = 36

3x = 39

x = 13

Answer:

The largest number is 13
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Answer :

The average, 12, is the middle one.

They are consecutive integers so the largest is 13.
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Answer :

n + (n + 1) + (n + 2) = 36

3n + 3 = 36

3n = 36 - 3

3n = 33

n = 11

n = 11

n + 1 = 11 + 1 = 12

n + 2 = 11 + 2 = 13 Largest Integer..

The largest integer is 13......Answer//
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Answer :

The sum of three consecutive integers is 36.

(x - 1) + x + (x + 1) = 36

13 is the largest of the three integers.
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