What is the largest of three consecutive odd integers if the product of the first and third integers is 6 more than three times the second integer?

What is the largest of three consecutive odd integers if the product of the first and third integers is 6 more than three times the second integer?
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Let the middle one be n, then:(n - 2)(n + 2) = 3n + 6→ n² - 4 = 3n + 6→ n² - 3n - 10 = 0→ (n + 2)(n - 5) = 0→ n = -2 or 5-2 can be discounted as n is odd→ n = 5→ largest of the three odd numbers is 5 + 2 = 7.
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